Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A proton is placed in a uniform electric field and thenreleased. Then an electron is placed at this same point and released.Do these two particles experience the same force? The sameacceleration? Do they move in the same direction when released?

Short Answer

Expert verified

The two particles experience the same force but in opposite direction.

No, they don’t have the same acceleration.

When released, they move in an opposite direction.

Step by step solution

01

Definition of the acceleration

The rate at which an object's velocity changes with function of time is called acceleration.

The acceleration when the velocity is zero is called initial acceleration. The acceleration from the Newton’s second law is given by,

a=Fm

Here, mis the mass, and Fis the force.

02

Calculation of the force, the acceleration and the direction exerted by the two particles

The charges of the positively charged particle-proton and the negatively charged particle-electron are equal in magnitude but opposite in sign.On each particle, the electric field produces the same magnitude of forces but in opposing directions.

Since the proton has more mass, its acceleration is less than that of an electron. This is because acceleration and mass are inversely related with constant F, a=Fm.

Protons accelerate in the direction of the electric field but with a tiny magnitude, while electrons accelerate in the opposite direction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

High-voltage power supplies are sometimes designed intentionally to have rather large internal resistance as a safety precaution. Why is such a power supply with a large internal resistance safer than a supply with the same voltage but lower internal resistance?

(a) At room temperature, what is the strength of the electric field in a

12-gauge copper wire (diameter 2.05mm) that is needed to cause a 4.50-A

current to flow? (b) What field would be needed if the wire were made of silver

instead?

A25.0-Ωbulb is connected across the terminals of a12.0-Vbattery having3.50Ωof internal resistance. What percentage of the power of the battery is dissipated across the internal resistance and hence is not available to the bulb?

A horizontal rectangular surface has dimensions 2.80cmby 3.20cmand is in a uniform magnetic field that is directed at an angle of 30.0°above the horizontal. What must the magnitude of the magnetic field be to produce a flux of 3.10×10-4Wb through the surface?

In the circuit shown in Fig. E26.49, C = 5.90 mF, Ԑ = 28.0 V, and the emf has negligible resistance. Initially, the capacitor is uncharged and the switch S is in position 1. The switch is then moved to position 2 so that the capacitor begins to charge. (a) What will be the charge on the capacitor a long time after S is moved to position 2? (b) After S has been in position 2 for 3.00 ms, the charge on the capacitor is measured to be 110 mC What is the value of the resistance R? (c) How long after S is moved to position 2 will the charge on the capacitor be equal to 99.0% of the final value found in part (a)?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free