Chapter 4: Q15E (page 1045)
The resistor, inductor, capacitor, and voltage source described in Exercise 31.14 are connected to form an L-R-C series circuit. (a) What is the impedance of the circuit? (b) What is the current amplitude? (c) What is the phase angle of the source voltage with respect to the current? Does the source voltage lag or lead the current? (d) What are the voltage amplitudes across the resistor, inductor, and capacitor? (e) Explain how it is possible for the voltage amplitude across the capacitor to be greater than the voltage amplitude across the source.
Short Answer
- The impedance of the circuit is 600 Ω
- The amplitude of the current in circuit is 0.05 A
- The phase angle of the voltage source with respect to current is -70.56° which means voltage lags the current as the phase angle is negative.
- The voltage drop across the resistor, inductor, and capacitor is 10 V, 5 V, and 33.33 V respectively.
- The voltage drop across capacitor could get larger than voltage of source when net sum of is negative.