Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Radio station WCCO in Minneapolis broadcasts at a frequency of . At a point some distance from the transmitter, the magnetic-field amplitude of the electromagnetic wave from WCCO is 4.82×10-11T. Calculate (a) the wavelength; (b) the wave number; (c) the angular frequency; (d) the electric-field amplitude.

Short Answer

Expert verified
  1. The wavelength of the electromagnetic wave is 361 m
  2. The wave number of the electromagnetic wave is 174×10-4rad/m.
  3. The angular velocity of the electromagnetic wave is 5.22×106rad/s.
  4. The amplitude of electric field is 144×10-4V/m.

Step by step solution

01

Step 1: Define frequency and write formulas.

The number of waves that moves a fixed point in unit time is known as frequency.

f=1Torω2π

Where, T = Time period in seconds and is angular frequency in .

The frequency, wavelength, and speed of light of any wave are related by the wavelength-frequency relationship.

The wavelength-frequency relationship is:

c=λf

Where, c is the speed of light which is equal to 3×108m/s, λis the wavelength and is the frequency.

The wavelength is inversely proportional to the frequency.

λ=cforvf

Where, v is velocity of wave in m/s.

The relation between wave number and wavelength is:

k=2πλ

Where, k is wavenumber in rad/m.

The formula used to determine the amplitude of electric and magnetic fields of the wave are:

Emax=2lε0CBmax=Emaxc

02

Determine the wavelength and wave number of wave.

Given that,f=830×103Hz

The wavelength of wave is:

λ=cf=3×108830×103=361m

The wave number of wave is:

role="math" k=2πλ=2π361=174×10-4rad/s

Hence, wavelength of the electromagnetic wave is 361 m and the wave number of the electromagnetic wave is 174×10-4rad/m.

03

Determine the angular frequency and amplitude of electric field.

The angular frequency of wave is:

ω=2πf=2π830×103=5.22×108rad/s

Given that,Bmax=4.82×10-11T

The formula used to determine the amplitude of electric field of the wave is:

Emax=cBmax=3×1084.82×10-11=144×10-4V/m

Hence, the angular velocity of the electromagnetic wave is 5.22×106rad/sand the amplitude of electric field is144×10-4V/m .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) At room temperature, what is the strength of the electric field in a

12-gauge copper wire (diameter 2.05mm) that is needed to cause a 4.50-A

current to flow? (b) What field would be needed if the wire were made of silver

instead?

A 140-g ball containing excess electrons is dropped into a 110-m vertical shaft. At the bottom of the shaft, the ball suddenly enters a uniform horizontal magnetic field that has magnitude 0.300 T and direction from east to west. If air resistance is negligibly small, find the magnitude ond direction of the force that this magnetic field exerts on the ball just as it enters the field.

Cyclotrons are widely used in nuclear medicine for producing short-lived radioactive isotopes. These cyclotrons typically accelerate H-(the hydride ion, which has one proton and two electrons) to an energy of 5MeVto20MeV.This ion has a mass very close to that of a proton because the electron mass is negligible about 12000of the proton’s mass. A typical magnetic field in such cyclotrons is 1.9T..(a) What is the speed of a 5.0-MeVH-? (b) If the H-has energy 5.0MeVandB=1.9T what is the radius of this ion’s circulator orbit?

Two copper wires with different diameter are joined end to end. If a current flow in the wire combination, what happens to electrons when they move from the large diameter wire into the smaller diameter wire? Does their drift speed increase, decrease, or stay the same? If the drift speed change, what is the role the force that causes the change? Explain your reasoning.

In Europe the standard voltage in homes is 220 V instead of the 120 used in the United States. Therefore a “100-W” European bulb would be intended for use with a 220-V potential difference (see Problem 25.36). (a) If you bring a “100-W” European bulb home to the United States, what should be its U.S. power rating? (b) How much current will the 100-W European bulb draw in normal use in the United States?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free