Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Fig. E26.11, the battery has emf 35.0 V and negligible internal resistance. R1=5.00Ω. The current through is R1, 1.5 A and the current through R3is 4.50 A. What are the resistances R1and R3?

Short Answer

Expert verified

The value of resistances isR2=2.5Ω and R3=6.11Ω.

Step by step solution

01

Definition of Internal Resistance

Internal resistance refers to the opposition to the flow of charges offered by the cells and batteries themselves resulting in the generation of heat.

02

Determine the resistance R2

Given data:

  • ε=35.0V
  • I3=4.5A
  • I1=1.5A
  • r = 0

AsR1 andR2 are in parallel, this means they have the same voltage that equals to the voltage across their combination R12. So, the voltage acrossR2 is given using Ohm’s law as:

V2=V1=I1R1

Plug the values,

V2=1.5A5.0Ω=7.5V

Now, the combination is in series with , which means the current is the same for both as:

I3=I12=I1+I2

Plug the values,

l2=l3-l1=4.5-1.5=3.0A

Now, use Ohm’s law to calculate resistance as:

R2=V2l2=7.53.0=2.5Ω

03

Determine the resistance R3

The voltage drop of the battery is due to R3and the combination R12. And as the internal resistance is zero, the Ohm's law can be used as:

ε=I(R12+R3)R3=εl=R12 (1)

The combination can be calculated as:

R12=R1R2R1+R2=5.02.55.0+2.5=1.67Ω

Plug the values in equation (1),

R3=35.0V4.5A-1.67Ω=6.11Ω

Thus, the value of resistances is R2=2.5Ωand R3=6.11Ω.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A typical small flashlight contains two batteries, each having an emf of1.5V, connected in series with a bulb having resistance17Ω. (a) If the internal resistance of the batteries is negligible, what power is delivered to the bulb? (b) If the batteries last for1.5hwhat is the total energy delivered to the bulb? (c) The resistance of real batteries increases as they run down. If the initial internal resistance is negligible, what is the combined internal resistance of both batteries when the power to the bulb has decreased to half its initial value? (Assume that the resistance of the bulb is constant. Actually, it will change somewhat when the current through the filament changes, because this changes the temperature of the filament and hence the resistivity of the filament wire.)

In the circuit shown in Fig. E26.41, both capacitors are initially charged to 45.0 V. (a) How long after closing the switch S will the potential across each capacitor be reduced to 10.0 V, and (b) what will be the current at that time?

Each of the lettered points at the corners of the cube in Fig. Q27.12 represents a positive charge qmoving with a velocity of magnitude vin the direction indicated. The region in the figure is in a uniform magnetic field , parallel to the x-axis and directed toward the right. Which charges experience a force due to B? What is the direction of the force on each charge?

A particle with charge-5.60nCis moving in a uniform magnetic fieldrole="math" localid="1655717557369" B=-(1.25T)k^

The magnetic force on the particle is measured to berole="math" localid="1655717706597" F=-(3.40×10-7N)i^-(7.40×10-7N)j^ (a) Calculate all the components of the velocity of the particle that you can from this information. (b) Are there
components of the velocity that are not determined by the measurement of the force? Explain. (c) Calculate the scalar productv֏F. What is the angle between velocity and force?

The tightly wound toroidal solenoid is one of the few configurations for which it is easy to calculate self-inductance. What features of the toroidal solenoid give it this simplicity?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free