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An advertisement claims that a centrifuge takes up only \(0.127 \mathrm{~m}\) of bench space but can produce a radial acceleration of \(3000 \mathrm{~g}\) at 5000 rev \(/ \mathrm{min}\). Calculate the required radius of the centrifuge. Is the claim realistic?

Short Answer

Expert verified
Calculate the radius as approximately 0.486 m and find that the claim of 0.127 m is unrealistic.

Step by step solution

01

Identify Known Values

We know the radial acceleration as a multiple of Earth's gravity, given as \(3000 \mathrm{~g}\). Each \(\mathrm{g}\) is \(9.81 \, \mathrm{m/s^2}\), so the radial acceleration is \(3000 \times 9.81 \, \mathrm{m/s^2}\). The centrifuge rotates at \(5000 \mathrm{~rev/min}\).
02

Convert Rotation Speed

Convert the given rotation speed from revolutions per minute to radians per second. One revolution is \(2\pi\) radians and there are 60 seconds per minute. So, the angular velocity \(\omega\) is \(\frac{5000 \times 2\pi}{60} \, \mathrm{rad/s}\).
03

Relation Between Acceleration and Radius

Use the formula for radial acceleration \(a = \omega^2 r\), where \(r\) is the radius and \(a\) is the radial acceleration. Substitute the values to get \(3000 \times 9.81 = \left(\frac{5000 \times 2\pi}{60}\right)^2 r\).
04

Solve for Radius

Rearrange the formula to find \(r\). Solve for \(r\) by dividing both sides by the angular velocity squared. This gives us \(r = \frac{3000 \times 9.81}{\left(\frac{5000 \times 2\pi}{60}\right)^2}\).
05

Calculate the Radius

Calculate \(r\) with the values inserted, ensuring units are consistent. This will give the required radius for such a radial acceleration at the specified rotational speed.
06

Evaluate the Claim

Compare the calculated radius to the claimed bench space of 0.127 m. If \(r\) is significantly less than or equal to half of 0.127 m, the claim is realistic, otherwise it is not.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radial Acceleration Calculation
Radial acceleration is the acceleration experienced by an object moving in a circular path, directed towards the center of rotation. In the centrifuge context, it's a measure of how fast something moves in a circle. Acceleration is expressed in terms of Earth's gravity (where 1g is approximately 9.81 m/s²).
To find the radial acceleration from the given centrifugal force, we first identify the known values. Here, a radial acceleration of 3000g is given. This translates to:
  • Radial acceleration = 3000 imes 9.81 \, \mathrm{m/s^2}
Using the formula for radial acceleration \( a = \omega^2 \times r \), we solve for the radius \( r \), after finding \( \omega \) from the angular velocity conversion. This equation helps connect physical rotation measures to linear acceleration in circular paths.
Angular Velocity Conversion
Converting the given rotation speed of the centrifuge is crucial for accurate calculations. The speed is initially given in revolutions per minute (rpm), which isn't directly usable in physics equations involving radians. To convert:
  • 1 revolution = 2π radians
  • 1 minute = 60 seconds
Given 5000 revolutions per minute, the angular velocity \( \omega \) becomes:
  • \( \omega = \frac{5000 \times 2\pi}{60} \, \mathrm{rad/s} \)
This conversion helps us to get the angular velocity in radians per second, a unit that's harmonized with other standard SI units like meters and seconds. Without this conversion, calculating accurate radial acceleration isn't possible.
Rotational Motion
Rotational motion involves any object moving in a circular path. For objects like centrifuges, understanding rotational dynamics is key to comprehending forces at play. Centrifuges create strong radial accelerations to separate substances, such as blood components with different densities, by spinning rapidly.
In physics, rotational motion is characterized by parameters like:
  • Angular velocity: How fast an object spins
  • Radial acceleration: The inwards force experienced by the rotating object
  • Radius of rotation: Distance from the center of the circle to the path of motion
Understanding these aspects allows you to solve equations concerning rotating objects and assess the realism of various claims about such systems, like evaluating if a centrifuge's required radius fits into the advertised bench space. The interplay between these factors determines the outcomes for devices operating under rotational motion.

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Most popular questions from this chapter

A thin, rectangular sheet of metal has mass \(M\) and sides of length \(a\) and \(b\). Use the parallel-axis theorem to calculate the moment of inertia of the sheet for an axis that is perpendicular to the plane of the sheet and that passes through one corner of the sheet.

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On a compact disc (CD), music is coded in a pattern of tiny pits arranged in a track that spirals outward toward the rim of the disc. As the disc spins inside a CD player, the track is scanned at a constant \(linear\) speed of \(v =\) 1.25m/s. Because the radius of the track varies as it spirals outward, the angular speed of the disc must change as the CD is played. (See Exercise 9.20.) Let's see what angular acceleration is required to keep \(v\) constant. The equation of a spiral is \(r(\theta) = r_0 + \beta\theta\), where \(r_0\) is the radius of the spiral at \(\theta =\) 0 and \(\beta\) is a constant. On a CD, \(r_0\) is the inner radius of the spiral track. If we take the rotation direction of the CD to be positive, \(\beta\) must be positive so that \(r\) increases as the disc turns and \(\theta\) increases. (a) When the disc rotates through a small angle \(d\theta\), the distance scanned along the track is \(ds = rd\theta\). Using the above expression for \(r(\theta)\), integrate \(ds\) to find the total distance \(s\) scanned along the track as a function of the total angle \(\theta\) through which the disc has rotated. (b) Since the track is scanned at a constant linear speed \(v\), the distance s found in part (a) is equal to \(vt\). Use this to find \(\theta\) as a function of time. There will be two solutions for \(\theta\) ; choose the positive one, and explain why this is the solution to choose. (c) Use your expression for \(\theta(t)\) to find the angular velocity \(\omega_z\) and the angular acceleration \(\alpha_z\) as functions of time. Is \(\alpha_z\) constant? (d) On a CD, the inner radius of the track is 25.0 mm, the track radius increases by 1.55 mm per revolution, and the playing time is 74.0 min. Find \(r_0, \beta,\) and the total number of revolutions made during the playing time. (e) Using your results from parts (c) and (d), make graphs of \(\omega_z\) (in rad/s) versus \(t\) and \(\alpha_z\) (in rad/s\(^2\)) versus \(t\) between \(t =\) 0 and \(t =\) 74.0 min. \(\textbf{The Spinning eel.}\) American eels (\(Anguilla\) \(rostrata\)) are freshwater fish with long, slender bodies that we can treat as uniform cylinders 1.0 m long and 10 cm in diameter. An eel compensates for its small jaw and teeth by holding onto prey with its mouth and then rapidly spinning its body around its long axis to tear off a piece of flesh. Eels have been recorded to spin at up to 14 revolutions per second when feeding in this way. Although this feeding method is costly in terms of energy, it allows the eel to feed on larger prey than it otherwise could.

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