Chapter 8: Problem 32
Two skaters collide and grab on to each other on frictionless ice. One of them, of mass 70.0 kg, is moving to the right at 4.00 m/s, while the other, of mass 65.0 kg, is moving to the left at 2.50 m/s. What are the magnitude and direction of the velocity of these skaters just after they collide?
Short Answer
Expert verified
The skaters move together at 0.87 m/s to the right after the collision.
Step by step solution
01
Understanding the Conservation of Momentum
In a collision, where no external forces are acting on the system, the total momentum before the collision is equal to the total momentum after the collision, according to the law of conservation of momentum. We need to calculate the total momentum before the collision to find the velocity of the combined masses after they collide.
02
Calculating Initial Momentum of Each Skater
The momentum of an object is given by the product of its mass and velocity. For the first skater (70.0 kg moving at 4.00 m/s to the right):\[ p_1 = 70.0 \text{ kg} \times 4.00 \text{ m/s} = 280.0 \text{ kg m/s to the right}\]For the second skater (65.0 kg moving at 2.50 m/s to the left):\[ p_2 = 65.0 \text{ kg} \times (-2.50 \text{ m/s}) = -162.5 \text{ kg m/s to the left}\](Note: Velocity to the left is negative.)
03
Calculating Total Initial Momentum
The total initial momentum of the system is the sum of the momenta of the two skaters:\[ p_{\text{total, initial}} = p_1 + p_2 = 280.0 \text{ kg m/s} + (-162.5 \text{ kg m/s}) = 117.5 \text{ kg m/s}\]
04
Calculating the Total Mass After Collision
After the collision, the skaters grab onto each other and move together as a single object. Therefore, the total mass of the system after the collision is the sum of their masses:\[ m_{\text{total}} = 70.0 \text{ kg} + 65.0 \text{ kg} = 135.0 \text{ kg}\]
05
Finding the Velocity After Collision
Using the conservation of momentum, where total momentum before collision equals total momentum after collision:\[ p_{\text{total, initial}} = m_{\text{total}} \times v_{\text{final}}\]Substitute the known values:\[ 117.5 \text{ kg m/s} = 135.0 \text{ kg} \times v_{\text{final}}\]Solve for \( v_{\text{final}} \):\[ v_{\text{final}} = \frac{117.5 \text{ kg m/s}}{135.0 \text{ kg}} = 0.87 \text{ m/s}\]
06
Analyzing Direction of Motion
Since the total initial momentum is positive, the final direction of motion is to the right. The final velocity of the pair moving together is 0.87 m/s to the right.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inelastic Collision
In physics, an inelastic collision is a type of collision where the colliding objects stick together after the impact. Unlike an elastic collision, where the objects bounce apart and total kinetic energy is conserved, inelastic collisions do not conserve kinetic energy. Instead, they conserve momentum.
- Inelastic collisions often result in deformations or energy being lost as heat or sound.
- The focus is on the conservation of the total momentum of the system.
Momentum
Momentum is a fundamental concept in physics describing the quantity of motion an object has. It is calculated as the product of an object's mass and its velocity. Expressed mathematically, momentum
$p = m imes v$, where $m$ is mass and $v$ is velocity.
- It is a vector quantity, meaning it has both magnitude and direction.
- The law of conservation of momentum states that in a closed system with no external forces, the total momentum remains constant.
Physics Problems
Solving physics problems often requires a systematic approach. Understanding the foundational principles such as momentum conservation is crucial. Let's break down the key steps you can take:
- Clearly identify what is given and what needs to be found.
- Use appropriate physical laws. For example, here we use the conservation of momentum because there are no external forces acting on the skaters.
- Translate the problem into mathematical equations, ensuring correct sign conventions for directions.
- Solve equations carefully using algebraic manipulation.