Chapter 42: Problem 27
Germanium has a band gap of 0.67 eV. Doping with arsenic adds donor levels in the gap 0.01 eV below the bottom of the conduction band. At a temperature of 300 K, the probability is 4.4 \(\times\) 10\(^-$$^4\) that an electron state is occupied at the bottom of the conduction band. Where is the Fermi level relative to the conduction band in this case?
Short Answer
Step by step solution
Understand the Problem
Recall the Fermi-Dirac Distribution
Set Up the Equation
Solve for Fermi Level \( E_F \)
Interpret the Result
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Band gap
The band gap affects how well a semiconductor can conduct electricity. If the band gap is too large, it acts more like an insulator, making it difficult for electrons to gain enough energy to jump into the conduction band. Conversely, if it is too small, the semiconductor might act more like a conductor. Therefore, the band gap is a balancing act to achieve desired electrical properties in electronic applications.
Doping in semiconductors
When these donor levels are present, they can easily donate electrons to the conduction band. This makes the material more conductive because there are more charge carriers available to move through the semiconductor.
- n-type doping adds extra electrons to the material.
- Increases conductivity by providing additional charge carriers.
Fermi-Dirac distribution
The distribution is given by:\[ f(E) = \frac{1}{e^{(E - E_F)/(kT)} + 1}\]where:
- \(E\) is the energy of the state.
- \(E_F\) is the Fermi level, a crucial concept that denotes the energy level at which the probability of an electron occupying that state is 50%.
- \(k\) is the Boltzmann constant.
- \(T\) is the absolute temperature in Kelvin.