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Two dogs pull horizontally on ropes attached to a post; the angle between the ropes is 60.0\(^\circ\). If Rover exerts a force of 270 N and Fido exerts a force of 300 N, find the magnitude of the resultant force and the angle it makes with Rover's rope.

Short Answer

Expert verified
The magnitude of the resultant force is approximately 493.87 N, and it makes an angle of about 31.6° with Rover's rope.

Step by step solution

01

Understand the Given Problem

We have two forces acting at an angle to each other. Rover exerts a force of 270 N, and Fido exerts a force of 300 N. The angle between the ropes is 60.0 degrees. We need to find the resultant force vector's magnitude and its angle with Rover's rope.
02

Use the Formula for Resultant Force

To find the magnitude of the resultant force when two forces act at an angle, we use the formula: \[R = \sqrt{F_1^2 + F_2^2 + 2F_1F_2\cos\theta}\]where \(F_1 = 270\, N\), \(F_2 = 300\, N\), and \(\theta = 60.0^\circ\).
03

Calculate Cosine of the Angle

Calculate \(\cos\theta\):\[\cos 60.0^\circ = 0.5\]
04

Substitute Values into Resultant Force Formula

Substitute the known values into the formula:\[R = \sqrt{270^2 + 300^2 + 2 \times 270 \times 300 \times 0.5}\]
05

Perform Calculations

Calculate inside the square root:\[= \sqrt{72900 + 90000 + 81000}\]\[= \sqrt{243900}\]Now take the square root:\[R \approx 493.87\, N\]
06

Find the Angle with Rover's Rope

Use the formula for the direction of the resultant force:\[\tan\phi = \frac{F_2\sin\theta}{F_1 + F_2\cos\theta}\]where \(\phi\) is the angle between the resultant and Rover's force. Substitute the values:\[\tan\phi = \frac{300 \times 0.866}{270 + 300 \times 0.5}\]
07

Calculate the Angle

Calculate the tangent:\[= \frac{300 \times \sqrt{3}/2}{270 + 150}\]\[= \frac{259.8}{420}\]Calculate \(\phi\):\[\phi \approx \tan^{-1}(0.6186) \approx 31.6^\circ\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resultant Force Calculation
When we're dealing with forces, calculating the resultant force is like finding a single force that could replace several individual forces acting on an object, such as the dogs pulling on the ropes in this case. The trick to finding the magnitude of this resultant force is by using a special formula when the forces act at an angle to each other:\[ R = \sqrt{F_1^2 + F_2^2 + 2F_1F_2\cos\theta} \]Here's how it works:- Suppose two forces, \(F_1\) and \(F_2\), are acting on an object at an angle \(\theta\).- You square the magnitudes of both forces.- Then sum these squares.- Don't forget to add twice the product of the two forces multiplied by the cosine of the angle between them.- Finally, take the square root of the entire expression.For the dogs, Rover exerts \(270\, N\) and Fido \(300\, N\), with an angle of \(60^\circ\) between them. First calculate \(\cos 60^\circ\), which is \(0.5\). Then substitute all values into the formula to find \(R\). This gives us a resultant force of approximately \(493.87\, N\). This result tells us the combined effort in terms of a singular force magnitude.
Vector Angle Determination
Determining the angle a resultant force makes with one of the original forces is about understanding direction as well as magnitude. In our problem, we figure out the angle between the resultant force and Rover's rope using this formula:\[ \tan\phi = \frac{F_2\sin\theta}{F_1 + F_2\cos\theta} \]To grasp this, here's a breakdown:- \(\phi\) is the angle you're solving for, between the resultant force and Rover's direction.- \(\sin\theta\) and \(\cos\theta\) are trigonometric functions based on the angle \(\theta\).- Put the force due to Fido, \(F_2\), on the numerator after multiplying it by \(\sin\theta\).- On the denominator, combine Rover's force \(F_1\) with Fido's force times the cosine of \(\theta\).- Solve \(\phi\) by applying the inverse tangent function.For our exercise, substituting \(F_1 = 270\, N\), \(F_2 = 300\, N\), and \(\theta = 60^\circ\) gives us an angle \(\phi\approx 31.6^\circ\). Thus, the resultant force is tilted about \(31.6\) degrees from Rover's original direction.
Physics Problem Solving
Physics problems often involve breaking things down into manageable parts. Let's apply that idea to figure out how to solve scenarios like our dog scenario with ropes and forces.Here is a simple approach:
  • Start by understanding what you are being asked. For example, are you finding a resultant vector or an angle?
  • Identify all the given values, and determine the relationships between them, such as forces and angles.
  • Use appropriate formulas. For forces, vector addition formulas are your friend. Understand each variable and where it fits.
  • Break down the calculation into smaller steps, like solving for \(\cos\theta\) or \(\sin\theta\), to make your life easier.
  • Always double-check your results to see if they make sense in a practical context, like ensuring the angle is possible given the situation.
In the dogs' pulling problem, this means recognizing that we are adding vectors, using trigonometry to solve for angles, and making sure the resultant has direction and magnitude that make sense."

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Most popular questions from this chapter

A loaded elevator with very worn cables has a total mass of 2200 kg, and the cables can withstand a maximum tension of 28,000 N. (a) Draw the free-body force diagram for the elevator. In terms of the forces on your diagram, what is the net force on the elevator? Apply Newton's second law to the elevator and find the maximum upward acceleration for the elevator if the cables are not to break. (b) What would be the answer to part (a) if the elevator were on the moon, where \(g =\) 1.62 m/s\(^2\)?

A hockey puck with mass 0.160 kg is at rest at the origin (\(x =\) 0) on the horizontal, frictionless surface of the rink. At time \(t =\) 0 a player applies a force of 0.250 N to the puck, parallel to the \(x\)-axis; she continues to apply this force until \(t =\) 2.00 s. (a) What are the position and speed of the puck at \(t =\) 2.00 s? (b) If the same force is again applied at \(t =\) 5.00 s, what are the position and speed of the puck at \(t =\) 7.00 s?

An 8.00-kg box sits on a level floor. You give the box a sharp push and find that it travels 8.22 m in 2.8 s before coming to rest again. (a) You measure that with a different push the box traveled 4.20 m in 2.0 s. Do you think the box has a constant acceleration as it slows down? Explain your reasoning. (b) You add books to the box to increase its mass. Repeating the experiment, you give the box a push and measure how long it takes the box to come to rest and how far the box travels. The results, including the initial experiment with no added mass, are given in the table: In each case, did your push give the box the same initial speed? What is the ratio between the greatest initial speed and the smallest initial speed for these four cases? (c) Is the average horizontal force \(f\) exerted on the box by the floor the same in each case? Graph the magnitude of force \(f\) versus the total mass \(m\) of the box plus its contents, and use your graph to determine an equation for \(f\) as a function of \(m\).

Forces \(\vec{F_1}\) and \(\vec{F_2}\)act at a point. The magnitude of \(\vec{F_1}\) is 9.00 N, and its direction is 60.0\(^\circ\) above the \(x\)-axis in the second quadrant. The magnitude of \(\vec{F_2}\) is 6.00 N, and its direction is 53.1\(^\circ\) below the \(x\)-axis in the third quadrant. (a) What are the \(x\)- and \(y\)-components of the resultant force? (b) What is the magnitude of the resultant force?

A 6.50-kg instrument is hanging by a vertical wire inside a spaceship that is blasting off from rest at the earth's surface. This spaceship reaches an altitude of 276 m in 15.0 s with constant acceleration. (a) Draw a free-body diagram for the instrument during this time. Indicate which force is greater. (b) Find the force that the wire exerts on the instrument.

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