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Higher-energy photons might be desirable for the treatment of certain tumors. Which of these actions would generate higher-energy photons in this linear accelerator? (a) Increasing the number of electrons that hit the tungsten target; (b) accelerating the electrons through a higher potential difference; (c) both (a) and (b); (d) none of these.

Short Answer

Expert verified
The correct answer is (b): accelerating the electrons through a higher potential difference.

Step by step solution

01

Understanding Photons in Linear Accelerators

Photons are generated in a linear accelerator when electrons are accelerated and then collide with a target, such as tungsten. The energy of the photons produced depends on the energy of the electrons when they strike the target.
02

Analyzing option (a)

Option (a) suggests increasing the number of electrons that hit the tungsten target. While this increases the quantity of photons produced, it does not increase the energy of individual photons. Energy is determined by the potential difference electrons are accelerated through, not the number of electrons.
03

Analyzing option (b)

Option (b) involves accelerating electrons through a higher potential difference. This will increase the energy of electrons, which directly increases the energy of the photons produced, as energy of photons is directly related to the energy of impacting electrons.
04

Evaluate combined option (c)

Option (c) is a combination of (a) and (b). While increasing the number of electrons does not affect photon energy, accelerating them through higher potential difference does increase the photon energy. Thus, (b) alone suffices.
05

Conclusion for option (d)

Option (d) suggests that none of the options increase photon energy. However, since (b) clearly increases the energy, (d) is incorrect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Accelerator
A linear accelerator, often called a linac, is a device that uses electromagnetic fields to propel charged particles, such as electrons, to high speeds and to contain them in well-defined beams. The primary purpose of a linear accelerator is to accelerate electrons using alternating electrical potentials. The result is high-energy particles with the capability to produce X-ray or gamma-ray photons.

Linear accelerators are vital in medical treatments, especially in radiation therapy for cancer. They enable precise targeting of tumors with high-energy radiation, sparing surrounding healthy tissues. Inside a linac, electrons are emitted by a hot cathode and then accelerated in a straight line.
  • Consist of components like electron source, waveguide, and accelerator structure
  • Used in medical therapies and scientific research
  • Key for producing high-energy radiation in a controlled environment
In the context of photon production for medical treatment, understanding how these devices work is crucial to tailoring treatments to patient needs.
Electron Acceleration
Electron acceleration in a linear accelerator is a fundamental process where electrons gain kinetic energy. This process involves applying a high voltage across two points, propelling the electrons across a short distance. The primary aim is to increase the energy of electrons to a point where they can emit high-energy photons upon impact with a target, like tungsten.

Within the linac, electrons start from an electron gun and are subjected to alternating electromagnetic fields. These fields push the electrons forward, increasing their speed and kinetic energy each cycle they pass through.
  • Involves boosting the speed of electrons to near light-speed
  • Requires intricate synchronization of electromagnetic fields
  • Crucial for ensuring electrons have enough energy to produce desired photons
Effective acceleration is essential because the energy of the photons produced is directly related to the energy of the electrons when they hit the target, making this process critical in applications such as radiation therapy.
Potential Difference
A potential difference, often called voltage, is a fundamental concept in the field of physics and plays an essential role in linear accelerators. It refers to the difference in electric potential between two points. When electrons pass between these points, the potential difference gives them energy.

Higher potential differences in a linear accelerator translate to electrons receiving more kinetic energy. This increased energy is necessary for producing high-energy photons suitable for medical treatments such as tumor therapy. The relation between the energy of electrons and potential difference is linear: doubling the potential difference results in a doubling of the electron's energy.
  • Measured in volts (V)
  • Directly influences the energy of accelerated electrons
  • Key factor for determining the final energy of photons produced
This concept is crucial, as tweaking the potential difference can change the photon's energy, making it a powerful tool in medical and scientific applications.
Photon Production
Photon production in the context of a linear accelerator involves the conversion of high-energy electrons into photons when they strike a target. This target, typically made of a high atomic number element like tungsten, is where the electrons lose their energy in the form of radiation.

The energy of the resultant photons is directly tied to the initial energy of the electrons. This relationship is why manipulating factors such as potential difference is critical in the design of linear accelerators. Achieving the desired photon energy levels ensures that they can effectively be used in applications such as radiation therapy for cancer treatment.
  • Involves emission of photons via electron collision
  • Energy of photons is a result of initial electron energy
  • Target material like tungsten is crucial for efficient photon production
For effectively treating tumors, producing the right energy level of photons is imperative, as too high or too low could either damage surrounding tissue or not be effective enough.

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Most popular questions from this chapter

An x-ray tube is operating at voltage \(V\) and current \(I\). (a) If only a fraction \(p\) of the electric power supplied is converted into x rays, at what rate is energy being delivered to the target? (b) If the target has mass \(m\) and specific heat \(c\) (in J/kg \(\bullet\) K), at what average rate would its temperature rise if there were no thermal losses? (c) Evaluate your results from parts (a) and (b) for an x-ray tube operating at 18.0 kV and 60.0 mA that converts 1.0\(\%\) of the electric power into x rays. Assume that the 0.250-kg target is made of lead (\(c\) = 130 J/kg \(\bullet\) K). (d) What must the physical properties of a practical target material be? What would be some suitable target elements?

X rays with an initial wavelength of 0.900 \(\times\) 10\(^{-10}\) m undergo Compton scattering. For what scattering angle is the wavelength of the scattered x rays greater by 1.0\(\%\) than that of the incident x rays?

(a) What is the minimum potential difference between the filament and the target of an x-ray tube if the tube is to produce x rays with a wavelength of 0.150 nm? (b) What is the shortest wavelength produced in an x-ray tube operated at 30.0 kV?

A photon with wavelength \(\lambda\) = 0.0980 nm is incident on an electron that is initially at rest. If the photon scatters in the backward direction, what is the magnitude of the linear momentum of the electron just after the collision with the photon?

A 2.50-W beam of light of wavelength 124 nm falls on a metal surface. You observe that the maximum kinetic energy of the ejected electrons is 4.16 eV. Assume that each photon in the beam ejects a photoelectron. (a) What is the work function (in electron volts) of this metal? (b) How many photoelectrons are ejected each second from this metal? (c) If the power of the light beam, but not its wavelength, were reduced by half, what would be the answer to part (b)? (d) If the wavelength of the beam, but not its power, were reduced by half, what would be the answer to part (b)?

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