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Two particles in a high-energy accelerator experiment are approaching each other head-on, each with a speed of 0.9380c as measured in the laboratory. What is the magnitude of the velocity of one particle relative to the other?

Short Answer

Expert verified
The magnitude of the velocity of one particle relative to the other is approximately 0.9983c.

Step by step solution

01

Identify the Problem

We need to find the relative velocity of two particles moving towards each other with given speeds using relativistic velocity addition.
02

Assign Known Values and Formula

The particles are moving towards each other with a speed of 0.9380c each. The relativistic velocity addition formula is needed, given by: \( v_{rel} = \frac{u + v}{1 + \frac{uv}{c^2}} \), where \( u \) and \( v \) are the speeds of the two particles as measured from the laboratory.
03

Set up the Equation

In our case, the speed \( u = 0.9380c \) and \( v = 0.9380c \). Substitute these into the relativistic addition formula: \[ v_{rel} = \frac{0.9380c + 0.9380c}{1 + \frac{(0.9380c)(0.9380c)}{c^2}} \].
04

Simplify the Numerator

Calculate the numerator of the expression: \( 0.9380c + 0.9380c = 1.8760c \).
05

Calculate the Denominator

Calculate the denominator: \( 1 + \frac{(0.9380)^2c^2}{c^2} = 1 + 0.879044 = 1.879044 \).
06

Calculate the Relative Velocity

Substitute the simplified terms back into the equation: \[ v_{rel} = \frac{1.8760c}{1.879044} \].
07

Final Computation

Divide the numerator by the denominator to get the final result: \[ v_{rel} \approx 0.9983c \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity
Understanding relative velocity is crucial in high-energy physics experiments. When two objects move towards each other, the speed at which they approach one another differs from the speed measured in a stationary frame like a lab. In high-speed scenarios, such as those near the speed of light ( \( c \)), calculating this relative speed requires special consideration.

In our problem, both particles move at a speed of 0.9380c as measured from the lab. To find the relative velocity, we use the relativistic velocity addition formula:
  • The formula: \( v_{rel} = \frac{u + v}{1 + \frac{uv}{c^2}} \)
  • This accounts for the effects of relativity, ensuring the relative velocity never exceeds the speed of light.
This approach differs from classical physics, where you'd simply add the speeds, potentially exceeding \( c \). The application of this formula signifies a shift to considering the relativistic effects in velocity calculations.
High-Energy Physics
High-energy physics investigates particles moving at speeds close to the speed of light. In such settings, typical classical physics rules don't apply as they do at slower speeds. Instead, this domain uses relativistic physics to understand and predict particle behavior.

When dealing with particles in accelerators, like those in the original exercise, scientists must consider:
  • The increased mass of particles as they approach light speed.
  • The relativistic effects on time and space, requiring precise calculations.
These considerations fundamentally alter how experiments are designed and interpreted. Particles don't just move faster; they follow completely different sets of principles, affecting their interactions and how they can be harnessed in experiments.
Relativity
The theory of relativity, proposed by Albert Einstein, fundamentally alters how we understand motion and reference frames. It introduces the concept that laws of physics remain constant, but measurements of time, space, and velocity can change based on an observer's frame of reference.

Within relativity, especially the special theory of relativity relevant to our problem, a few key elements are:
  • Time dilation: Time moves slower for objects moving at high speeds relative to an observer.
  • Length contraction: Objects contract in the direction of motion as their speeds approach light speed.
  • Relativistic momentum and energy, adjusting for massive speeds.
These elements assure that all physical observations align with the principle that nothing can move faster than light, providing essential corrections to our classical assumptions about velocity and motion.

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Most popular questions from this chapter

Two particles are created in a high-energy accelerator and move off in opposite directions. The speed of one particle, as measured in the laboratory, is 0.650c, and the speed of each particle relative to the other is 0.950c. What is the speed of the second particle, as measured in the laboratory?

As you pilot your space utility vehicle at a constant speed toward the moon, a race pilot flies past you in her spaceracer at a constant speed of 0.800c relative to you. At the instant the spaceracer passes you, both of you start timers at zero. (a) At the instant when you measure that the spaceracer has traveled 1.20 \(\times\) 10\(^8\) m past you, what does the race pilot read on her timer? (b) When the race pilot reads the value calculated in part (a) on her timer, what does she measure to be your distance from her? (c) At the instant when the race pilot reads the value calculated in part (a) on her timer, what do you read on yours?

A spacecraft flies away from the earth with a speed of 4.80 \(\times\) 10\(^6\) m/s relative to the earth and then returns at the same speed. The spacecraft carries an atomic clock that has been carefully synchronized with an identical clock that remains at rest on earth. The spacecraft returns to its starting point 365 days (1 year) later, as measured by the clock that remained on earth. What is the difference in the elapsed times on the two clocks, measured in hours? Which clock, the one in the spacecraft or the one on earth, shows the shorter elapsed time?

(a) Consider the Galilean transformation along the \(x\)-direction : \(x' = x - vt\) and \(t' = t\). In frame \(S\) the wave equation for electromagnetic waves in a vacuum is $${\partial^2E(x, t)\over \partial x^2} - {1 \over c^2} {\partial^2E(x, t)\over \partial t^2} = 0$$ where \(E\) represents the electric field in the wave. Show that by using the Galilean transformation the wave equation in frame \(S'\) is found to be $$(1 - {v^2 \over c^2} ) {\partial^2E(x', t') \over \partial{x'^2}} + {2v \over c^2} {\partial^2E(x', t') \over \partial{x'} \partial{t'}} - {1 \over c^2} {\partial^2E(x', t') \over \partial{t'^2}} = 0$$ This has a different form than the wave equation in \(S\). Hence the Galilean transformation \(violates\) the first relativity postulate that all physical laws have the same form in all inertial reference frames. (\(Hint\): Express the derivatives \(\partial/\partial{x}\) and \(\partial/\partial{t}\) in terms of \(\partial/\partial{x'}\) and \(\partial/\partial{t'}\) by use of the chain rule.) (b) Repeat the analysis of part (a), but use the Lorentz coordinate transformations, Eqs. (37.21), and show that in frame \(S'\) the wave equation has the same form as in frame \(S\): $${\partial^2E(x', t') \over \partial{x'}^2} - {1 \over c^2} {\partial^2E(x', t') \over \partial{t'}^2} = 0$$ Explain why this shows that the speed of light in vacuum is c in both frames \(S\) and \(S'\).

In the earth's rest frame, two protons are moving away from each other at equal speed. In the frame of each proton, the other proton has a speed of 0.700\(c\). What does an observer in the rest frame of the earth measure for the speed of each proton?

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