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A mirror on the passenger side of your car is convex and has a radius of curvature with magnitude 18.0 cm. (a) Another car is behind your car, 9.00 m from the mirror, and this car is viewed in the mirror by your passenger. If this car is 1.5 m tall, what is the height of the image? (b) The mirror has a warning attached that objects viewed in it are closer than they appear. Why is this so?

Short Answer

Expert verified
The image height is 1.485 cm, and objects look smaller in convex mirrors, appearing farther.

Step by step solution

01

Understanding the Problem

A convex mirror has a radius of curvature with absolute value \( R = 18.0 \) cm. The object (another car) is at a distance \( d_o = 900 \) cm (converting from 9.00 m to cm) from the mirror, and the height of this car \( h_o = 150 \) cm (converting from 1.5 m to cm). We need to find the height of the image formed by the mirror.
02

Find the Focal Length

The focal length \( f \) of a mirror is given by \( f = \frac{R}{2} \). For a convex mirror, the focal length is negative, so \( f = -\frac{18.0}{2} = -9.0 \) cm.
03

Use the Mirror Equation

The mirror equation is \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \), where \( d_i \) is the image distance. Substituting the known values we have \( \frac{1}{-9.0} = \frac{1}{900} + \frac{1}{d_i} \). Solve for \( d_i \).
04

Solve for Image Distance

Rearrange the equation to find \( \frac{1}{d_i} = \frac{1}{-9.0} - \frac{1}{900} \). Calculating these gives \( \frac{1}{d_i} = -0.1111 - 0.0011 = -0.1122 \). So, \( d_i = -8.91 \) cm.
05

Apply the Magnification Formula

The magnification \( m \) of a mirror is given by \( m = -\frac{d_i}{d_o} \) and also by \( m = \frac{h_i}{h_o} \). Using \( m = -\frac{-8.91}{900} \approx 0.0099 \). Thus, the height of the image \( h_i = m \cdot h_o = 0.0099 \times 150 = 1.485 \) cm.
06

Explanation of Warning

Convex mirrors cause images to appear smaller, making them seem farther away. This is due to the diverging nature of the mirror, which compresses the field of view into a smaller area.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convex Mirror
A convex mirror is a type of spherical mirror that curves outward, like the exterior of a sphere. It is often used in vehicles, such as on the passenger side of cars, due to its ability to provide a wider field of view. This is because light rays diverge after reflecting off the convex surface, making it easier for drivers to see more area behind them.

One of the peculiar features of convex mirrors is that they always produce virtual, upright, and diminished images of objects, regardless of their position. These qualities make convex mirrors particularly useful for safety and surveillance purposes in situations where a broad field of vision is necessary.
Mirror Equation
The mirror equation relates the focal length of the mirror, the object distance, and the image distance. It is an essential tool in optics for analyzing mirrors' behavior. The equation is written as:

\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]

Here, \( f \) is the focal length, \( d_o \) is the object distance from the mirror, and \( d_i \) is the image distance. The focal length for convex mirrors is negative because they cause parallel rays to diverge.

By substituting the known values into this equation, one can solve for the unknowns, like the image distance. This equation shows that when an object is positioned very far from a convex mirror, the image becomes increasingly smaller and appears closer to the focal point.
Image Magnification
Image magnification in optics tells us how much larger or smaller an image appears compared to the original object. It can be determined using the formula:

\[ m = -\frac{d_i}{d_o} \]

It is also defined as the ratio of the image height \( h_i \) to the object height \( h_o \):
\[ m = \frac{h_i}{h_o} \]

In the context of a convex mirror, since the image height is smaller than the object height, the magnification factor will be less than one. This is the reason why objects reflect smaller than their actual size in a convex mirror.
Focal Length
Focal length is a critical property of mirrors and lenses, representing the distance from the mirror to the focal point. For a spherical mirror, the focal length \( f \) can be calculated from the radius of curvature \( R \) using the formula:

\[ f = \frac{R}{2} \]

With convex mirrors, the focal length is considered negative, which reflects the diverging nature of these mirrors. Diverging means that parallel rays of light that hit the mirror spread out after reflection.

Understanding the focal length is crucial for predicting how images will form, especially in determining whether they will appear larger or smaller, closer or farther than they are. This explains why objects viewed in convex mirrors seem farther away than they actually are, as stated in warnings often printed on vehicle mirrors.

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Most popular questions from this chapter

You are in your car driving on a highway at 25 m\(/\)s when you glance in the passenger-side mirror (a convex mirror with radius of curvature 150 cm) and notice a truck approaching. If the image of the truck is approaching the vertex of the mirror at a speed of 1.9 m\(/\)s when the truck is 2.0 m from the mirror, what is the speed of the truck relative to the highway?

A small tropical fish is at the center of a water-filled, spherical fish bowl 28.0 cm in diameter. (a) Find the apparent position and magnification of the fish to an observer outside the bowl. The effect of the thin walls of the bowl may be ignored. (b) A friend advised the owner of the bowl to keep it out of direct sunlight to avoid blinding the fish, which might swim into the focal point of the parallel rays from the sun. Is the focal point actually within the bowl?

Given that frogs are nearsighted in air, which statement is most likely to be true about their vision in water? (a) They are even more nearsighted; because water has a higher index of refraction than air, a frog's ability to focus light increases in water. (b) They are less nearsighted, because the cornea is less effective at refracting light in water than in air. (c) Their vision is no different, because only structures that are internal to the eye can affect the eye's ability to focus. (d) The images projected on the retina are no longer inverted, because the eye in water functions as a diverging lens rather than a converging lens.

To determine whether a frog can judge distance by means of the amount its lens must move to focus on an object, researchers covered one eye with an opaque material. An insect was placed in front of the frog, and the distance that the frog snapped its tongue out to catch the insect was measured with high-speed video. The experiment was repeated with a contact lens over the eye to determine whether the frog could correctly judge the distance under these conditions. If such an experiment is performed twice, once with a lens of power -9-D and once with a lens of power -15-D, in which case does the frog have to focus at a shorter distance, and why? (a) With the -9-D lens; because the lenses are diverging, the lens with the longer focal length creates an image that is closer to the frog. (b) With the -15-D lens; because the lenses are diverging, the lens with the shorter focal length creates an image that is closer to the frog. (c) With the -9-D lens; because the lenses are converging, the lens with the longer focal length creates a larger real image. (d) With the -15-D lens; because the lenses are converging, the lens with the shorter focal length creates a larger real image.

A person with a near point of \(85 \mathrm{~cm},\) but excellent distant vision, normally wears corrective glasses. But he loses them while traveling. Fortunately, he has his old pair as a spare. (a) If the lenses of the old pair have a power of \(+2.25\) diopters, what is his near point (measured from his eye) when he is wearing the old glasses if they rest \(2.0 \mathrm{~cm}\) in front of his eye? (b) What would his near point be if his old glasses were contact lenses instead?

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