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If you run away from a plane mirror at 3.60 m\(/\)s, at what speed does your image move away from you?

Short Answer

Expert verified
Your image moves away from you at 7.20 m/s.

Step by step solution

01

Understanding the problem

A plane mirror creates an image that appears to be at the same distance from the mirror as the object, but on the opposite side. The critical point is that both the object and the image move with respect to the mirror.
02

Identifying the movement

If you move away from the mirror at a speed of 3.60 m/s, your image also moves on the other side of the mirror. Both you and the image are moving relative to the mirror.
03

Calculating the speed of the image

As you move away from the mirror, your image moves at the same speed relative to the mirror but in the opposite direction. Therefore, the image also moves at 3.60 m/s relative to the mirror.
04

Determining the relative speed between you and your image

Since you and your image both move at 3.60 m/s away from the mirror, the relative speed of separation is the sum of your speed and the speed of the image: \[ ext{Relative speed} = 3.60 ext{ m/s} + 3.60 ext{ m/s} = 7.20 ext{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Image Formation in Plane Mirrors
When you stand in front of a plane mirror, a fascinating phenomenon occurs. The mirror creates an image that looks just like you but appears to be located on the opposite side of the mirror. This image appears at the same distance from the mirror as you are on this side. Plane mirrors produce virtual images, meaning they cannot be projected on a screen because the light does not actually pass through the image location. The image in a plane mirror is always upright and reversed from left to right.

When you move, the image moves too. If you move towards the mirror, the image seems to come closer to you, and if you move away, the image seems to move further away. This direct relation between your movement and the image's movement is essential in understanding how images are formed by plane mirrors.
Exploring Relative Speed with Mirrors
Relative speed can be a little tricky in mirror scenarios, but it becomes clearer once we break it down. **Relative speed** refers to how fast one object is moving compared to another. In the context of a plane mirror, imagine you are running away from the mirror at a speed of 3.60 m/s. The key idea is that not only are you moving, but your mirror image is also moving away at the same speed.

The image appears to be on the opposite side, but both you and your image have a relative motion with respect to the mirror itself. When we talk about the relative speed between you and the image, we add your speed and the image's speed together. So, if both are moving away from the mirror at 3.60 m/s, the relative speed of separation is 3.60 m/s plus 3.60 m/s, making it 7.20 m/s. This total gives the combined speed at which you and your image pull away from each other.
Key Optics Concepts in Image Reflection
Optics is the branch of science that deals with light and its interactions. The concept of reflection is a central idea in optics and is easily observed in plane mirrors. When light hits a mirror, it bounces back, creating a reflection. This reflection allows us to see images in the mirror.
  • **Law of Reflection:** This law states that the angle of incidence (the angle between the incoming light and the normal to the surface) is equal to the angle of reflection (the angle between the reflected light and the normal).
  • **Virtual Images:** These are images formed where rays of light appear to meet or come from after reflection, even though they do not really meet at any actual point. The image is perceived behind the plane mirror.
  • **Reversal of Images:** In plane mirrors, images are laterally inverted, meaning your left hand appears as your right hand in the reflection.

Understanding these principles helps clarify how images form and move with mirrors, and why reflection leads to the fascinating visual displays we see with plane mirrors.

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Most popular questions from this chapter

A telescope is constructed from two lenses with focal lengths of 95.0 cm and 15.0 cm, the 95.0-cm lens being used as the objective. Both the object being viewed and the final image are at infinity. (a) Find the angular magnification for the telescope. (b) Find the height of the image formed by the objective of a building 60.0 m tall, 3.00 km away. (c) What is the angular size of the final image as viewed by an eye very close to the eyepiece?

The image formed by a microscope objective with a focal length of 5.00 mm is 160 mm from its second focal point. The eyepiece has a focal length of 26.0 mm. (a) What is the angular magnification of the microscope? (b) The unaided eye can distinguish two points at its near point as separate if they are about 0.10 mm apart. What is the minimum separation between two points that can be observed (or resolved) through this microscope?

A photographic slide is to the left of a lens. The lens projects an image of the slide onto a wall 6.00 m to the right of the slide. The image is 80.0 times the size of the slide. (a) How far is the slide from the lens? (b) Is the image erect or inverted? (c) What is the focal length of the lens? (d) Is the lens converging or diverging?

The radii of curvature of the surfaces of a thin converging meniscus lens are \(R_1\) = +12.0 cm and \(R_2\) = +28.0 cm. The index of refraction is 1.60. (a) Compute the position and size of the image of an object in the form of an arrow 5.00 mm tall, perpendicular to the lens axis, 45.0 cm to the left of the lens. (b) A second converging lens with the same focal length is placed 3.15 m to the right of the first. Find the position and size of the final image. Is the final image erect or inverted with respect to the original object? (c) Repeat part (b) except with the second lens 45.0 cm to the right of the first.

A converging meniscus lens (see Fig. 34.32a) with a refractive index of 1.52 has spherical surfaces whose radii are 7.00 cm and 4.00 cm. What is the position of the image if an object is placed 24.0 cm to the left of the lens? What is the magnification?

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