Chapter 34: Problem 45
A camera lens has a focal length of 200 mm. How far from the lens should the subject for the photo be if the lens is 20.4 cm from the sensor?
Short Answer
Expert verified
The subject should be 10.2 meters from the lens.
Step by step solution
01
Convert Units
First, make sure all units are consistent. The focal length is given as 200 mm, and the lens is 20.4 cm from the sensor. Convert 20.4 cm to mm by multiplying by 10: \[ 20.4 \text{ cm} = 204 \text{ mm} \]
02
Apply the Lens Formula
Use the lens formula which relates the object distance \( u \), the image distance \( v \), and the focal length \( f \): \[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \]Here, \( f = 200 \text{ mm} \) and \( v = 204 \text{ mm} \). We need to find \( u \).
03
Derive the Object Distance Formula
Re-arrange the lens formula to solve for \( \frac{1}{u} \): \[ \frac{1}{u} = \frac{1}{f} - \frac{1}{v} \]
04
Substitute Values
Substitute the known values into the re-arranged formula: \[ \frac{1}{u} = \frac{1}{200} - \frac{1}{204} \]
05
Calculate \( \frac{1}{u} \)
Perform the calculation of \( \frac{1}{u} \):\[ \frac{1}{u} = \frac{1}{200} - \frac{1}{204} = \frac{204 - 200}{200 \times 204} \]Simplify: \[ \frac{1}{u} = \frac{4}{40800} \]
06
Find Object Distance \( u \)
Invert \( \frac{1}{u} \) to find \( u \): \[ u = \frac{40800}{4} = 10200 \text{ mm} \]
07
Convert to Desired Units
The solution requires the object distance in meters. Convert \( 10200 \text{ mm} \) to meters by dividing by 1000:\[ u = \frac{10200}{1000} = 10.2 \text{ m} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Focal Length
The term "focal length" refers to the distance between the lens and its focus, where parallel light rays converge after passing through the lens. In the context of a camera lens, the focal length is crucial because it determines how zoomed in or out an image appears. A long focal length stretches out the vision, offering a zoomed-in view of a distant object.
In simple terms, the focal length is how "strong" or "powerful" a lens is. It's measured in millimeters (mm). For our particular problem, the focal length is 200 mm. This number indicates how far the sensor captures the image, in terms of its depth of field, and affects the perspective of the photo.
When applying the lens formula in the problem, the focal length becomes part of the equation:
In simple terms, the focal length is how "strong" or "powerful" a lens is. It's measured in millimeters (mm). For our particular problem, the focal length is 200 mm. This number indicates how far the sensor captures the image, in terms of its depth of field, and affects the perspective of the photo.
When applying the lens formula in the problem, the focal length becomes part of the equation:
- Formula: \( \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \)
- Given: \( f = 200 \text{ mm} \)
Object Distance
Object distance refers to the gap between the object being photographed (or observed) and the lens. In order to get a clear image, understanding and calculating this distance is crucial. For photographers, this is often adjustable depending on the lens and camera settings, allowing for flexibility in taking sharp images.
In mathematical terms, the object distance is represented by \( u \) in the lens formula. The equation can be adjusted to solve for \( u \), which helps determine precisely how far the object should be from the lens to capture a focused photograph. The formula re-arranged to solve for object distance is:
In mathematical terms, the object distance is represented by \( u \) in the lens formula. The equation can be adjusted to solve for \( u \), which helps determine precisely how far the object should be from the lens to capture a focused photograph. The formula re-arranged to solve for object distance is:
- \( \frac{1}{u} = \frac{1}{f} - \frac{1}{v} \)
- \( \frac{1}{u} = \frac{1}{200} - \frac{1}{204} \)
- Resulting in \( u = 10200 \text{ mm} \) (or \( 10.2 \text{ m} \) when converted)
Image Distance
Image distance measures how far the focused image is from the lens itself, most often ending up on the sensor in a camera setup. This is crucial in determining the configuration of the lens relative to the sensor for achieving a sharp image on the film or digital sensor.
In many cases, like in our problem, the image distance \( v \) is initially provided or can be measured directly if the camera or device has a fixed position. Here, the image distance is given as 204 mm. This value tells us how far the sensor is from the lens, which is crucial for setting up the equation:
In many cases, like in our problem, the image distance \( v \) is initially provided or can be measured directly if the camera or device has a fixed position. Here, the image distance is given as 204 mm. This value tells us how far the sensor is from the lens, which is crucial for setting up the equation:
- \( \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \)
- Given: \( v = 204 \text{ mm} \)