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For a convex spherical mirror that has focal length \(f\) = -12.0 cm, what is the distance of an object from the mirror's vertex if the height of the image is half the height of the object?

Short Answer

Expert verified
The object is 12 cm from the mirror.

Step by step solution

01

Understand the Mirror Equation

For a spherical mirror, we use the mirror equation: \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \), where \( f \) is the focal length, \( d_o \) is the object distance, and \( d_i \) is the image distance. Since the mirror is convex, \( f = -12.0 \) cm.
02

Relate Image and Object Heights

We know from the problem statement that the image height \( h_i \) is half of the object height \( h_o \), giving us the magnification equation: \( M = \frac{h_i}{h_o} = \frac{1}{2} \). Magnification is also represented as \( M = -\frac{d_i}{d_o} \).
03

Substitute in the Magnification Equation

Since \( M = \frac{1}{2} \), we have \( \frac{1}{2} = -\frac{d_i}{d_o} \), leading to \( d_i = -\frac{1}{2}d_o \). This relationship will help us find the object distance \( d_o \).
04

Solve the Mirror Equation with Substitution

Substitute \( d_i = -\frac{1}{2}d_o \) into the mirror equation: \( \frac{1}{-12} = \frac{1}{d_o} + \frac{1}{-\frac{1}{2}d_o} \). Simplify it to: \( \frac{1}{-12} = \frac{1}{d_o} - \frac{2}{d_o} = -\frac{1}{d_o} \).
05

Solve for the Object Distance

From \( -\frac{1}{d_o} = \frac{1}{-12} \), we rearrange to find \( d_o = 12 \) cm. The object distance is 12 cm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convex Mirror
Convex mirrors are a type of spherical mirror where the reflecting surface bulges outward, resembling the exterior of a sphere. These mirrors are known for creating virtual images that appear smaller and upright compared to the actual object. The interesting feature of a convex mirror is that it always forms images that are diminished and placed between the mirror and its focal point.
This occurs because the reflected rays diverge, and when extended backwards, they appear to converge at a point behind the mirror. Some common applications of convex mirrors include:
  • Rearview mirrors in vehicles, offering a wider field of view
  • Security mirrors in stores, allowing for broad surveillance
  • Architectural features enhancing space perception
Understanding how a convex mirror works helps you appreciate its function in various daily life scenarios.
Mirror Equation
The mirror equation is a fundamental formula used to relate the object distance ( d_o ), image distance ( d_i ), and the focal length ( f ) of the mirror. This relationship is expressed as: \[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\]This equation is applicable for both convex and concave mirrors, though it behaves differently based on the type of mirror. For convex mirrors, the focal length is given a negative value.
This distinction is important as it influences how you interpret the resulting image's characteristics, such as its location and size. To effectively use the mirror equation:
  • Determine the type of mirror and assign the correct sign to the focal length
  • Know the values of two out of three variables ( d_o , d_i , f ), and solve for the unknown
  • Ensure all distances are measured from the mirror's vertex
In our original problem, we used this equation to find the object distance with known focal length and a derived relation between object and image distances.
Magnification
Magnification is an important concept when working with mirrors and lenses. It measures how much larger or smaller the image is compared to the object. The formula for magnification ( M ) is given by: \[ M = \frac{h_i}{h_o} = -\frac{d_i}{d_o}\]where ( h_i ) is the image height and ( h_o ) is the object height. The negative sign in the magnification equation applies to mirrors, indicating inversion of the image in cases where the image is real. However, for convex mirrors, the images formed are virtual, upright, and diminished, making them oriented the same as the object.Key points about magnification include:
  • In convex mirrors, magnification is always less than 1, indicating a smaller image
  • A positive magnification signifies an upright image
  • A negative magnification suggests an inverted image, which is typical with real images formed by concave mirrors
When solving problems, understanding magnification helps predict characteristics of the image like its orientation and relative size to the object.
Focal Length
Focal length is a crucial concept associated with spherical mirrors. It is the distance from the mirror's surface to its focal point, the point where parallel light rays either converge (concave mirror) or seem to diverge from (convex mirror). For spherical mirrors, the focal length ( f ) is half of the radius of curvature ( R ): \[ f = \frac{R}{2}\]This relationship helps calculate or verify focal lengths using geometry principles.
In convex mirrors, f is considered negative, which affects many calculations involving the mirror equation.Why is focal length important?
  • It helps determine the image position and size using the mirror equation
  • It defines the mirror's power and effectiveness at forming images
  • It is essential for designing optical instruments like telescopes and cameras
In the exercise scenario, understanding the mirror's focal length was central to predicting image formation and solving for object distance.

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Most popular questions from this chapter

(a) For a lens with focal length f, find the smallest distance possible between the object and its real image. (b) Graph the distance between the object and the real image as a function of the distance of the object from the lens. Does your graph agree with the result you found in part (a)

The image formed by a microscope objective with a focal length of 5.00 mm is 160 mm from its second focal point. The eyepiece has a focal length of 26.0 mm. (a) What is the angular magnification of the microscope? (b) The unaided eye can distinguish two points at its near point as separate if they are about 0.10 mm apart. What is the minimum separation between two points that can be observed (or resolved) through this microscope?

What is the size of the smallest vertical plane mirror in which a woman of height \(h\) can see her full-length image?

A lens forms an image of an object. The object is 16.0 cm from the lens. The image is 12.0 cm from the lens on the same side as the object. (a) What is the focal length of the lens? Is the lens converging or diverging? (b) If the object is 8.50 mm tall, how tall is the image? Is it erect or inverted? (c) Draw a principal-ray diagram.

Given that frogs are nearsighted in air, which statement is most likely to be true about their vision in water? (a) They are even more nearsighted; because water has a higher index of refraction than air, a frog's ability to focus light increases in water. (b) They are less nearsighted, because the cornea is less effective at refracting light in water than in air. (c) Their vision is no different, because only structures that are internal to the eye can affect the eye's ability to focus. (d) The images projected on the retina are no longer inverted, because the eye in water functions as a diverging lens rather than a converging lens.

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