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Light traveling in air is incident on the surface of a block of plastic at an angle of 62.7 to the normal and is bent so that it makes a 48.1 angle with the normal in the plastic. Find the speed of light in the plastic.

Short Answer

Expert verified
The speed of light in the plastic is approximately 2.31×108 m/s.

Step by step solution

01

Identify Given Values

We are given the angle of incidence θ1=62.7 and the angle of refraction θ2=48.1.
02

Apply Snell's Law

Snell's law states that n1sinθ1=n2sinθ2, where n1 is the refractive index of air (approximately 1) and n2 is the refractive index of the plastic that we need to find.
03

Calculate Refractive Index of Plastic

Since n11, we have sin(62.7)=n2sin(48.1). Solving for n2, we have n2=sin(62.7)sin(48.1)1.296.
04

Use the Refractive Index to Find the Speed of Light

The speed of light in a medium is given by v=cn, where c3×108 m/s is the speed of light in a vacuum and n=1.296 is the refractive index of the plastic.
05

Calculate the Speed of Light in the Plastic

Plugging the values into the equation, we get: v=3×108 m/s1.2962.31×108 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle of Incidence
The angle of incidence is a fundamental concept when studying how light interacts with different media. It refers to the angle at which a light ray approaches a surface, measured from the normal, which is an imaginary line perpendicular to the surface. For instance, in the given exercise, light hits the surface of the plastic block at an angle of 62.7 degrees from the normal. Understanding this angle helps us predict how the light will behave as it passes into the new medium.
To visualize this, imagine a beam of light striking the surface of a clear plastic sheet. The line where this light meets the plastic forms the angle of incidence. Properly identifying this angle is crucial for applying Snell's Law, which relates the angles of incidence and refraction in different media.
Angle of Refraction
The angle of refraction is the angle that a light ray forms as it exits one medium and enters another. This angle is also measured relative to the normal. In our exercise, after the light enters the plastic, it bends and forms a 48.1-degree angle with the normal.
The process of bending, or refraction, occurs because light travels at different speeds in different media. As light enters a denser medium from a less dense medium, it slows down, causing it to change direction. This alteration of angle is what we observe as refraction. The angle of refraction is key to understanding how lenses work, how prisms disperse light, and much more in optics.
  • Occurs due to the speed change of light.
  • Helps to determine the extent of light bending.
Refractive Index
The refractive index is a measure that describes how fast light travels through a material compared to the speed of light in a vacuum. It is a crucial element of Snell's Law, which is expressed as n1sinθ1=n2sinθ2. In our case, the air (n₁) has a refractive index of approximately 1, while the plastic's refractive index (n₂) is calculated to be about 1.296.
This index helps us determine how much a ray of light will bend, depending on the media it is traveling through. If light moves from a medium with a lower refractive index like air to a higher one like plastic, it bends towards the normal.
  • Higher index = stronger bending effect.
  • Important for designing lenses and fiber optics.
Speed of Light
The speed of light in a vacuum is a constant c of approximately 3×108 m/s. However, when light travels through different materials, its speed changes, which is integral to understanding refractive behavior. In the exercise, we find the speed of light in the plastic using the equation v=cn, where n is the refractive index of the plastic.
After calculating, we found that light travels at roughly 2.31×108 m/s in the plastic. Knowing these speeds and how they vary between substances helps us understand phenomena such as refraction and reflection, and is essential for designing optical devices like cameras and glasses.
  • Speeds differ across materials due to density differences.
  • Crucial for high-precision scientific applications.

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Most popular questions from this chapter

A thin layer of ice (n = 1.309) floats on the surface of water (n = 1.333) in a bucket. A ray of light from the bottom of the bucket travels upward through the water. (a) What is the largest angle with respect to the normal that the ray can make at the ice-water interface and still pass out into the air above the ice? (b) What is this angle after the ice melts?

When the sun is either rising or setting and appears to be just on the horizon, it is in fact below the horizon. The explanation for this seeming paradox is that light from the sun bends slightly when entering the earth’s atmosphere, as shown in Fig. P33.51. Since our perception is based on the idea that light travels in straight lines, we perceive the light to be coming from an apparent position that is an angle δ above the sun's true position. (a) Make the simplifying assumptions that the atmosphere has uniform density, and hence uniform index of refraction n, and extends to a height h above the earth's surface, at which point it abruptly stops. Show that the angle δ is given by δ=arcsin(nRR+h)arcsin(RR+h) where R = 6378 km is the radius of the earth. (b) Calculate δ using n = 1.0003 and h = 20 km. How does this compare to the angular radius of the sun, which is about one quarter of a degree? (In actuality a light ray from the sun bends gradually, not abruptly, since the density and refractive index of the atmosphere change gradually with altitude.)

A ray of light is incident on a plane surface separating two sheets of glass with refractive indexes 1.70 and 1.58. The angle of incidence is 62.0, and the ray originates in the glass with n = 1.70. Compute the angle of refraction.

Given small samples of three liquids, you are asked to determine their refractive indexes. However, you do not have enough of each liquid to measure the angle of refraction for light refracting from air into the liquid. Instead, for each liquid, you take a rectangular block of glass (n = 1.52) and place a drop of the liquid on the top surface of the block. You shine a laser beam with wavelength 638 nm in vacuum at one side of the block and measure the largest angle of incidence θa for which there is total internal reflection at the interface between the glass and the liquid (Fig. P33.58). Your results are given in the table: What is the refractive index of each liquid at this wavelength?

A beam of light is traveling inside a solid glass cube that has index of refraction 1.62. It strikes the surface of the cube from the inside. (a) If the cube is in air, at what minimum angle with the normal inside the glass will this light not enter the air at this surface? (b) What would be the minimum angle in part (a) if the cube were immersed in water?

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