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In an \(L\)-\(C\) circuit, \(L = 85.0\) mH and \(C = 3.20 \, \mu \mathrm{F}\). During the oscillations the maximum current in the inductor is 0.850 mA. (a) What is the maximum charge on the capacitor? (b) What is the magnitude of the charge on the capacitor at an instant when the current in the inductor has magnitude 0.500 mA?

Short Answer

Expert verified
(a) Use the maximum current to find the maximum charge through formula. (b) Calculate specific charge using relation between charge and given inductor current.

Step by step solution

01

Identify the formula for maximum charge

The maximum charge on the capacitor, denoted as \( Q_{max} \), is related to the maximum current \( I_{max} \) using the formula \( Q_{max} = I_{max} \times \sqrt{LC} \). This formula originates from the energy conservation principle in LC oscillations.
02

Calculate the resonant angular frequency

The resonant angular frequency \( \omega \) of the LC circuit is given by \( \omega = \frac{1}{\sqrt{LC}} \). Given \( L = 85.0 \) mH \( = 85.0 \times 10^{-3} \) H and \( C = 3.20 \) \( \mu \)F \( = 3.20 \times 10^{-6} \) F, we calculate \( \omega \).
03

Substitute to find Q_max

Now, calculate \( Q_{max} \) using the formula from Step 1: \( Q_{max} = (0.850 \times 10^{-3} \text{ A}) \times \sqrt{(85.0 \times 10^{-3} \text{ H}) (3.20 \times 10^{-6} \text{ F})} \). Solve for \( Q_{max} \).
04

Determine charge at a specific current

To find the charge on the capacitor when the inductor current is 0.500 mA, we use the formula \( Q = Q_{max} \cdot \sqrt{1-\left(\frac{I}{I_{max}}\right)^2} \). Substitute \( I = 0.500 \) mA and previously calculated \( I_{max} = 0.850 \) mA, and solve for \( Q \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Maximum Charge on Capacitor
The maximum charge that a capacitor can hold in an LC circuit is crucial because it determines the circuit's performance during oscillations. In an LC circuit, when you hear about maximum charge, it refers to the scenario where the energy stored in the capacitor is at its peak. This maximum charge, denoted as \( Q_{max} \), can be directly related to the maximum current \( I_{max} \).

To find \( Q_{max} \), we use the formula:
  • \( Q_{max} = I_{max} \times \sqrt{LC} \)
This formula comes from the principle of energy conservation, where the total energy in the system remains constant.

Additionally, this equation shows the interplay between the inductance \( L \), capacitance \( C \), and the maximum current. More inductance or capacitance means more energy stored, resulting in a larger maximum charge on the capacitor.
Resonant Angular Frequency
The resonant angular frequency is a fundamental concept in the analysis of LC circuits. When an LC circuit is oscillating naturally, it sits at a specific frequency where the circuit's impedance is minimized, and maximum energy transfer happens between the inductor and capacitor. This natural frequency ensures smooth oscillations, and it is defined by the circuit's inductance \( L \) and capacitance \( C \).

The formula to find the resonant angular frequency, \( \omega \), is:
  • \( \omega = \frac{1}{\sqrt{LC}} \)
This equation highlights how both inductance and capacitance impact the frequency:
  • A larger inductor or capacitor results in a lower resonant frequency.
Understanding this relationship helps engineers design circuits that perform optimally at the desired frequency.
Energy Conservation in Oscillations
In an LC circuit, energy conservation plays a vital role during the oscillation process. The stored energy alternates between the inductor and the capacitor, but the total energy remains constant. This principle allows the system to sustain oscillations without any external power input, given ideal conditions.

Here's what happens step-by-step in simple terms:
  • Initially, the maximum energy is stored in the capacitor as electric potential energy.
  • As time progresses, this energy shifts to the inductor, converting to magnetic energy while the capacitor discharges.
  • The oscillation continues as the energy moves back and forth between the capacitor and inductor.
Because of this constant energy exchange, the maximum current and maximum charge are directly linked, reflecting the conservation of total energy. The formulas used to calculate the maximum charge and current derive from this fundamental conservation principle, illustrating how intertwined current, charge, capacitance, and inductance really are.

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Most popular questions from this chapter

An \(L\)-\(C\) circuit containing an 80.0-mH inductor and a 1.25-nF capacitor oscillates with a maximum current of 0.750 A. Calculate: (a) the maximum charge on the capacitor and (b) the oscillation frequency of the circuit. (c) Assuming the capacitor had its maximum charge at time \(t = 0\), calculate the energy stored in the inductor after 2.50 ms of oscillation.

The minimum capacitance of a variable capacitor in a radio is 4.18 pF. (a) What is the inductance of a coil connected to this capacitor if the oscillation frequency of the \(L\)-\(C\) circuit is \(1600 \times 10^3\) Hz, corresponding to one end of the \(\textbf{AM}\) radio broadcast band, when the capacitor is set to its minimum capacitance? (b) The frequency at the other end of the broadcast band is \(540 \times 10^3\) Hz. What is the maximum capacitance of the capacitor if the oscillation frequency is adjustable over the range of the broadcast band?

A 10.0-cm-long solenoid of diameter 0.400 cm is wound uniformly with 800 turns. A second coil with 50 turns is wound around the solenoid at its center. What is the mutual inductance of the combination of the two coils?

An inductor is connected to the terminals of a battery that has an emf of 16.0 V and negligible internal resistance. The current is 4.86 mA at 0.940 ms after the connection is completed. After a long time, the current is 6.45 mA. What are (a) the resistance \(R\) of the inductor and (b) the inductance \(L\) of the inductor?

One solenoid is centered inside another. The outer one has a length of 50.0 cm and contains 6750 coils, while the coaxial inner solenoid is 3.0 cm long and 0.120 cm in diameter and contains 15 coils. The current in the outer solenoid is changing at 49.2 A/s. (a) What is the mutual inductance of these solenoids? (b) Find the emf induced in the inner solenoid.

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