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Two coils have mutual inductance \(M = 3.25 \times 10^{-4}\) H. The current \(i_1\) in the first coil increases at a uniform rate of 830 A/s. (a) What is the magnitude of the induced emf in the second coil? Is it constant? (b) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil?

Short Answer

Expert verified
(a) 0.26975 V; it is constant. (b) 0.26975 V; it is also constant.

Step by step solution

01

Understanding Mutual Inductance

Mutual inductance \(M\) is a measure of how much the magnetic field created by one coil induces electromotive force (emf) in another coil. Here, \(M = 3.25 \times 10^{-4}\) H.
02

Analyze Induced EMF Formula

The emf induced in a coil is given by the formula \( \text{emf} = M \times \frac{di}{dt} \), where \( \frac{di}{dt} \) is the rate of change of current. Here, it is uniform at 830 A/s.
03

Calculate the Magnitude of Induced EMF for Part (a)

Using the formula \( \text{emf} = M \times \frac{di}{dt} \), substitute \(M = 3.25 \times 10^{-4}\) H and \(\frac{di_1}{dt} = 830\) A/s: \[ \text{emf} = 3.25 \times 10^{-4} \times 830 = 0.26975 \text{ V} \] Thus, the magnitude of the induced emf in the second coil is 0.26975 V.
04

Determine if the Induced EMF is Constant

Since the rate of change of current \(\frac{di_1}{dt}\) is constant, the induced emf is also constant at 0.26975 V.
05

Calculate the Magnitude of Induced EMF for Part (b)

For part (b), if the current changing at the same rate is in the second coil, the induced emf in the first coil is calculated similarly: Use the same formula, where \(M = 3.25 \times 10^{-4}\) H and \(\frac{di_2}{dt} = 830\) A/s: \[ \text{emf} = 3.25 \times 10^{-4} \times 830 = 0.26975 \text{ V} \]Thus, the induced emf in the first coil is also 0.26975 V, which is constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Induced Electromotive Force (EMF)
Induced electromotive force (emf) is a fundamental concept in electromagnetism. It refers to the voltage that is generated in a coil due to a changing magnetic field. This phenomenon is based on Faraday's law of electromagnetic induction. The law states that the induced emf in a coil is directly proportional to the rate of change of the magnetic flux through the coil. In simple terms, any time there is a change in the magnetic environment of a coil, it will cause an induced voltage in the coil.

For two mutually inductive coils, the induced emf in one coil can be calculated using the formula:
  • \( \text{emf} = M \times \frac{di}{dt} \)
Here, \(M\) is the mutual inductance between the coils, and \(\frac{di}{dt}\) is the rate of change of current in the other coil. If the current's rate of change is uniform, like in our exercise, the induced emf will be constant. This is important because it means the induced voltage does not fluctuate, making it predictable and easier to manage in electrical circuits.
Rate of Change of Current
The rate of change of current is an essential factor in determining the induced emf across a coil. This rate, denoted by \( \frac{di}{dt} \), represents how quickly the current in a circuit is increasing or decreasing. In our context, it’s the speed at which the current in one coil changes that affects the second coil via mutual inductance.

Consider the given rate of current change, which is 830 A/s for our exercise. This rate is uniform, meaning it doesn't change over time. When the rate of current change is constant as in our case, it simplifies the calculation of induced emf because you can directly multiply it with the mutual inductance \(M\) to find the emf. The induced voltage remains steady over time because of this uniformity, which is a common scenario in many practical applications, such as transformers.
Magnetic Field
A magnetic field is an invisible field that exerts force on substances that are sensitive to magnetism, like iron and other ferromagnetic materials. In the context of mutual inductance, the magnetic field created by a current-carrying coil is key to inducing an emf in another nearby coil.

This magnetic field is generated when an electric current passes through a wire or coil. The strength and orientation of this magnetic field change with the current. So, when the current in one coil changes, it alters the magnetic field around it, which in turn affects the neighboring coil. This change is the driving factor that induces an emf in the second coil according to Faraday’s Law of Induction.

In applications involving mutual inductance, both coils influence one another through their magnetic fields. Understanding this interaction is crucial when designing circuits that rely on these principles, such as transformers, which adjust voltage levels in power systems.

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Most popular questions from this chapter

A 7.00-\(\mu\)F capacitor is initially charged to a potential of 16.0 V. It is then connected in series with a 3.75-mH inductor. (a) What is the total energy stored in this circuit? (b) What is the maximum current in the inductor? What is the charge on the capacitor plates at the instant the current in the inductor is maximal?

The minimum capacitance of a variable capacitor in a radio is 4.18 pF. (a) What is the inductance of a coil connected to this capacitor if the oscillation frequency of the \(L\)-\(C\) circuit is \(1600 \times 10^3\) Hz, corresponding to one end of the \(\textbf{AM}\) radio broadcast band, when the capacitor is set to its minimum capacitance? (b) The frequency at the other end of the broadcast band is \(540 \times 10^3\) Hz. What is the maximum capacitance of the capacitor if the oscillation frequency is adjustable over the range of the broadcast band?

In an \(L\)-\(C\) circuit, \(L = 85.0\) mH and \(C = 3.20 \, \mu \mathrm{F}\). During the oscillations the maximum current in the inductor is 0.850 mA. (a) What is the maximum charge on the capacitor? (b) What is the magnitude of the charge on the capacitor at an instant when the current in the inductor has magnitude 0.500 mA?

Two coils are wound around the same cylindrical form, like the coils in Example 30.1. When the current in the first coil is decreasing at a rate of -0.242 A/s, the induced emf in the second coil has magnitude \(1.65 \times 10^{-3}\) V. (a) What is the mutual inductance of the pair of coils? (b) If the second coil has 25 turns, what is the flux through each turn when the current in the first coil equals 1.20 A? (c) If the current in the second coil increases at a rate of 0.360 A/s, what is the magnitude of the induced emf in the first coil?

A 7.50-nF capacitor is charged up to 12.0 V, then disconnected from the power supply and connected in series through a coil. The period of oscillation of the circuit is then measured to be 8.60 \(\times\) 10\(^{-5}\) s. Calculate: (a) the inductance of the coil; (b) the maximum charge on the capacitor; (c) the total energy of the circuit; (d) the maximum current in the circuit.

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