Chapter 26: Problem 68
Three identical resistors are connected in series. When a certain potential difference is applied across the combination, the total power dissipated is 45.0 W. What power would be dissipated if the three resistors were connected in parallel across the same potential difference?
Short Answer
Expert verified
405 W of power is dissipated when resistors are in parallel.
Step by step solution
01
Understand Series Circuit
In a series circuit, the same current flows through all components. The total resistance \( R_{total} \) is the sum of the individual resistances. If each resistor has resistance \( R \), then \( R_{total} = 3R \) for three resistors.
02
Calculate Resistance in Series
Using the power formula for a series circuit, \( P = \frac{V^2}{R_{total}} \). Rearrange to find \( R \): \( R_{total} = \frac{V^2}{P} \). Thus, \( 3R = \frac{V^2}{45} \).
03
Determine Individual Resistance
From \( 3R = \frac{V^2}{45} \), solving for \( R \) gives \( R = \frac{V^2}{135} \). This is the resistance of each individual resistor.
04
Analyze Parallel Circuit
In a parallel circuit, the total resistance \( R_{total} \) is given by \( \frac{1}{R_{total}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} = \frac{3}{R} \). Simplifying, \( R_{total} = \frac{R}{3} \).
05
Calculate Power in Parallel
Using the power formula for the parallel circuit \( P = \frac{V^2}{R_{total}} \), substitute for \( R_{total} \): \( P = \frac{V^2}{\frac{R}{3}} = 3 \frac{V^2}{R} \).
06
Substitute for R from Step 3
From Step 3, we know \( R = \frac{V^2}{135} \). Substitute this into the power equation: \( P = 3 \frac{V^2}{\frac{V^2}{135}} = 3 \times 135 = 405 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Series Circuit
In a series circuit, all components are connected one after another, allowing the same electric current to flow through each component sequentially. This means the overall resistance in the circuit is simply the sum of individual resistances. When resistors are connected in series, the total resistance can be calculated using the formula:
- \( R_{total} = R_1 + R_2 + R_3 + ... + R_n \)
- \( P = \frac{V^2}{R_{total}} \)
Parallel Circuit
A parallel circuit offers multiple different paths for the electric current to flow. If one path is obstructed or broken, the others can continue to function. In contrast to series circuits, the total resistance in a parallel circuit decreases. It can be determined using the reciprocal formula:
- \( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ... + \frac{1}{R_n} \)
- \( \frac{1}{R_{total}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} = \frac{3}{R} \)
- \( R_{total} = \frac{R}{3} \)
Power Dissipation
Power dissipation refers to the process by which electrical energy is converted into thermal energy or heat within a circuit, often across resistors. It's a critical factor in both series and parallel circuits. Power dissipation is governed by the formula:
- \( P = VI \)
- \( P = I^2R \) (for circuits with a known current)
- \( P = \frac{V^2}{R} \) (for circuits with a known voltage)
Resistance Calculation
Calculating resistance is a crucial step in analyzing both series and parallel circuits. For series circuits, resistance is straightforward, as you just sum up the individual resistances. However, for parallel circuits, it becomes necessary to use the reciprocal relation for accurate calculations.
- Series: \( R_{total} = R_1 + R_2 + R_3 + ... + R_n \)
- Parallel: \( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ... \)