Chapter 21: Problem 77
A proton is projected into a uniform electric field that points vertically upward and has magnitude \(E\). The initial velocity of the proton has a magnitude \(v_0\) and is directed at an angle \(\alpha\) below the horizontal. (a) Find the maximum distance \(h_{max}\) that the proton descends vertically below its initial elevation. Ignore gravitational forces. (b) After what horizontal distance d does the proton return to its original elevation? (c) Sketch the trajectory of the proton. (d) Find the numerical values of \(h_{max}\) and \(d\) if \(E =\) 500 N\(/\)C, \(v_0 =\) 4.00 \(\times 10^5\) m\(/\)s, and \(\alpha =\) 30.0\(^\circ\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.