Chapter 21: Problem 17
Three point charges are arranged along the \(x\)-axis. Charge \(q_1 = +3.00 \space \mu\)C is at the origin, and charge \(q_2 = -5.00 \space \mu\)C is at \(x =\) 0.200 m. Charge \(q_3 = -8.00 \space \mu\)C. Where is \(q_3\) located if the net force on \(q_1\) is 7.00 N in the \(-\) \(x\)-direction ?
Short Answer
Expert verified
Charge \(q_3\) is located at \( x = -0.456 \text{ m} \) along the \(x\)-axis.
Step by step solution
01
Understand the Forces Involved
We have three point charges, with their interactions governed by Coulomb's Law, which states that the electric force between two charges is proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. The net force on charge \(q_1\) is given by the forces exerted by \(q_2\) and \(q_3\) on \(q_1\).
02
Coulomb's Law Equation
The force exerted by a charge \(q\) on another charge \(Q\), separated by a distance \(r\), is given by: \[ F = k \frac{|qQ|}{r^2} \]where \(k = 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2\). This will be used to calculate individual forces \(F_{12}\) between \(q_1\) and \(q_2\), and \(F_{13}\) between \(q_1\) and \(q_3\).
03
Calculate Force due to q2 on q1 ( F_{12})
Using Coulomb's Law for \(F_{12}\):\[ F_{12} = k \frac{|q_1 \times q_2|}{(0.200)^2} \]Substitute the values:\[ F_{12} = (8.99 \times 10^9) \frac{3.00 \times 10^{-6} \times 5.00 \times 10^{-6}}{0.200^2} \approx 3.37 \, \text{N} \] This force is in the positive \(x\)-direction, since they have opposite signs.
04
Determine the Force due to q3 on q1 (F_{13})
Since the net force on \(q_1\) is 7.00 N in the \(-x\)-direction, we can express the total force equation:\[ F_{net} = F_{12} - F_{13} = -7.00 \, \text{N} \]Re-arrange this to find \(F_{13}\):\[ F_{13} = F_{12} + 7.00 = 3.37 + 7.00 = 10.37 \, \text{N} \]
05
Find the Distance of q3 from q1
To locate \(q_3\), use Coulomb's Law:\[ F_{13} = k \frac{|q_1 \times q_3|}{x^2} \]Substitute the known values:\[ 10.37 = (8.99 \times 10^9) \frac{3.00 \times 10^{-6} \times 8.00 \times 10^{-6}}{x^2} \]Solving for \(x\), we get:\[ x^2 = \frac{(8.99 \times 10^9) \times 3.00 \times 10^{-6} \times 8.00 \times 10^{-6}}{10.37} \]\[ x^2 = 20.756 \times 10^{-2} \]\[ x \approx 0.456 \text{ m} \]Since this force is in the negative \(x\)-direction, \(q_3\) is placed at \( x = -0.456 \text{ m} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electric Force
The concept of electric force is fundamentally linked to the interactions between charged particles. In physics, the electric force that acts between two point charges is governed by Coulomb's Law. This foundational principle states that the force is directly proportional to the product of the magnitudes of the charges involved and inversely proportional to the square of the distance separating them.
In more straightforward terms, the larger the charge magnitudes or the closer they are, the stronger the force. Electric force can be attractive or repulsive. It becomes attractive when charges have opposite signs and repulsive when charges have the same signs.
Electric forces play a key role in many natural phenomena and technological applications, from the operation of electronic devices to chemical bonding and beyond.
In more straightforward terms, the larger the charge magnitudes or the closer they are, the stronger the force. Electric force can be attractive or repulsive. It becomes attractive when charges have opposite signs and repulsive when charges have the same signs.
Electric forces play a key role in many natural phenomena and technological applications, from the operation of electronic devices to chemical bonding and beyond.
Point Charges
Point charges are idealized charges that are considered to be located at a single point in space. These charges simplify the calculations in electrostatics because their small size allows us to ignore the complexities of charge distribution on objects.
Point charges are often used in theoretical models to help us understand the behavior of electric fields and forces in a simplified manner. For example, in the original exercise, the charges are treated as point charges, so we can easily calculate the forces using Coulomb's Law.
The notion of point charges is crucial in electrostatics as it provides the basis for determining how charges interact in various configurations, such as the alignment along a line or in a plane.
Point charges are often used in theoretical models to help us understand the behavior of electric fields and forces in a simplified manner. For example, in the original exercise, the charges are treated as point charges, so we can easily calculate the forces using Coulomb's Law.
The notion of point charges is crucial in electrostatics as it provides the basis for determining how charges interact in various configurations, such as the alignment along a line or in a plane.
Net Force Calculation
Net force is a critical concept that refers to the total force acting on an object when all the individual forces are considered. It determines how an object will move or stand still.
When multiple forces act on a charge, you need to consider all contributions to find the net force. This can involve summing the vector forces because directionality is crucial. For instance, a positive force in one direction will offset a negative one in the opposite direction.
In the exercise at hand, calculating the net force was necessary to determine the position of one of the charges. By analyzing the forces from other charges and applying the net force equation, it became possible to deduce unknown distances or positions.
When multiple forces act on a charge, you need to consider all contributions to find the net force. This can involve summing the vector forces because directionality is crucial. For instance, a positive force in one direction will offset a negative one in the opposite direction.
In the exercise at hand, calculating the net force was necessary to determine the position of one of the charges. By analyzing the forces from other charges and applying the net force equation, it became possible to deduce unknown distances or positions.
Electric Charge Interaction
Electric charge interactions are fundamental to understanding how charges exert forces on each other within a system. Different charges interact based on their polarity: positive with negative charges will attract, whereas like charges will repel.
This interaction is quantifiable by Coulomb's Law, enabling predictions of force magnitudes and directions. Moreover, such interactions underpin the behavior of atoms, molecules, and electromagnetic fields.
In practical terms, comprehending these interactions helps in predicting the stability of chemical compounds, the alignment of electronic circuits, and even celestial phenomena. In our specific case of point charges aligned on the x-axis, their interactions determine how they exert forces on one another, guiding us to locate where one charge must be positioned.
This interaction is quantifiable by Coulomb's Law, enabling predictions of force magnitudes and directions. Moreover, such interactions underpin the behavior of atoms, molecules, and electromagnetic fields.
In practical terms, comprehending these interactions helps in predicting the stability of chemical compounds, the alignment of electronic circuits, and even celestial phenomena. In our specific case of point charges aligned on the x-axis, their interactions determine how they exert forces on one another, guiding us to locate where one charge must be positioned.