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A lonely party balloon with a volume of 2.40 \(L\) and containing 0.100 mol of air is left behind to drift in the temporarily uninhabited and depressurized International Space Station. Sunlight coming through a porthole heats and explodes the balloon, causing the air in it to undergo a free expansion into the empty station, whose total volume is 425 m\(^3\). Calculate the entropy change of the air during the expansion.

Short Answer

Expert verified
The entropy change is approximately 10.06 J/K.

Step by step solution

01

Understanding Free Expansion

In a free expansion, the process is irreversible, and the gas expands into a vacuum without exchanging heat with the surroundings. Therefore, the internal energy of the gas does not change.
02

Entropy Change Formula for Free Expansion

The entropy change (\( \Delta S \)) of an ideal gas during free expansion is given by the formula: \[ \Delta S = nR \ln \frac{V_f}{V_i} \] where \( n \) is the number of moles of gas, \( R \) is the ideal gas constant (8.314 J/mol·K), \( V_f \) is the final volume, and \( V_i \) is the initial volume.
03

Calculate Initial and Final Volume

The initial volume \( V_i \) of the balloon is given as 2.40 L. Since 1 m³ = 1000 L, we convert this to 0.00240 m³. The final volume \( V_f \) is the volume of the entire space station, 425 m³.
04

Applying Values to Entropy Change Formula

Substitute the values into the entropy change formula: \[ \Delta S = 0.100 \times 8.314 \times \ln \left( \frac{425}{0.00240} \right) \] Calculate the natural logarithm value first.
05

Calculate Natural Logarithm

Calculate \( \ln \left( \frac{425}{0.00240} \right) \) to get \( \ln (177083.33) \approx 12.09 \).
06

Calculate Entropy Change

Now calculate \( \Delta S = 0.100 \times 8.314 \times 12.09 \). The calculation yields \( \Delta S \approx 10.06 \text{ J/K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free Expansion
Free expansion is a fascinating process often studied in physics, especially thermodynamics. It occurs when a gas expands into a vacuum without any obstacles or resistance. Imagine a balloon bursting in an empty room; the gas molecules will race out to fill the space.

In free expansion, there is no external pressure applied. This is why it does not perform any external work during the expansion. The process is considered to be quick and energetic.

Some key facts about free expansion include:
  • The internal energy of the gas remains unchanged because it does not perform work or exchange heat.
  • It is an irreversible process, meaning you can't reverse it and return to the initial state.
  • It results in an increase in entropy, which is a measure of disorder or randomness in the system.
Ideal Gas Law
The ideal gas law is a master key in understanding how gases behave. It's represented by the equation \( PV = nRT \), where:
  • \( P \) is the pressure of the gas.
  • \( V \) is the volume of the gas.
  • \( n \) is the number of moles of gas.
  • \( R \) is the ideal gas constant (8.314 J/mol·K).
  • \( T \) is the temperature in Kelvin.
The beauty of the ideal gas law lies in its ability to link all these fundamental gas properties.

In our free expansion example, even though the gas expands and fills a much larger space, the ideal gas law helps us understand and calculate changes, especially the entropy change, due to the increased volume.
Irreversible Process
When discussing thermodynamic processes, the term "irreversible" often pops up. Irreversible processes are those that cannot return the system to its original state without new changes occurring.

Free expansion is a classic example of an irreversible process. This is because, once the gas molecules are scattered, it's impossible to force them back into their initial confined state without interference.

Key aspects of irreversible processes:
  • They often involve friction, turbulence, or mixing, which are common in real-world applications.
  • They lead to an increase in entropy, representing energy dispersion and disorder.
  • Recovering initial conditions is practically impossible, underlining the direction of time.
International Space Station
The International Space Station (ISS) presents a unique environment for scientific experiments, including those on gas behavior. Situated in low Earth orbit, the ISS is essentially a large, vacuum-sealed laboratory.

Here, physics takes an exciting turn due to microgravity and lack of atmosphere. This means gases behave differently compared to on Earth. Our balloon in the problem utilized the vast, empty space of the ISS for free expansion.

Notable characteristics of the ISS that affect gas experiments:
  • The microgravity environment alters how gases spread and mix.
  • The lack of atmosphere means there's no external pressure to counteract a gas's movement.
  • Diverse environments within the ISS allow for various scientific explorations in controlled conditions.


These unique characteristics make the ISS an exceptional place for studying thermodynamics in new and enlightening ways.

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Most popular questions from this chapter

An experimental power plant at the Natural Energy Laboratory of Hawaii generates electricity from the temperature gradient of the ocean. The surface and deep-water temperatures are 27\(^\circ\)C and 6\(^\circ\)C, respectively. (a) What is the maximum theoretical efficiency of this power plant? (b) If the power plant is to produce 210 \(kW\) of power, at what rate must heat be extracted from the warm water? At what rate must heat be absorbed by the cold water? Assume the maximum theoretical efficiency. (c) The cold water that enters the plant leaves it at a temperature of 10\(^\circ\)C. What must be the flow rate of cold water through the system? Give your answer in kg/h and in \(L\)/h.

CP A certain heat engine operating on a Carnot cycle absorbs 410 J of heat per cycle at its hot reservoir at 135\(^\circ\)C and has a thermal efficiency of 22.0%. (a) How much work does this engine do per cycle? (b) How much heat does the engine waste each cycle? (c) What is the temperature of the cold reservoir? (d) By how much does the engine change the entropy of the world each cycle? (e) What mass of water could this engine pump per cycle from a well 35.0 m deep?

A diesel engine performs 2200 J of mechanical work and discards 4300 J of heat each cycle. (a) How much heat must be supplied to the engine in each cycle? (b) What is the thermal efficiency of the engine?

A freezer has a coefficient of performance of 2.40. The freezer is to convert 1.80 kg of water at 25.0\(^\circ\)C to 1.80 kg of ice at -5.0\(^\circ\)C in one hour. (a) What amount of heat must be removed from the water at 25.0\(^\circ\)C to convert it to ice at -5.0\(^\circ\)C? (b) How much electrical energy is consumed by the freezer during this hour? (c) How much wasted heat is delivered to the room in which the freezer sits?

An average sleeping person metabolizes at a rate of about 80 \(W\) by digesting food or burning fat. Typically, 20% of this energy goes into bodily functions, such as cell repair, pumping blood, and other uses of mechanical energy, while the rest goes to heat. Most people get rid of all this excess heat by transferring it (by conduction and the flow of blood) to the surface of the body, where it is radiated away. The normal internal temperature of the body (where the metabolism takes place) is 37\(^\circ\)C, and the skin is typically 7 C\(^\circ\) cooler. By how much does the person's entropy change per second due to this heat transfer?

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