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Helium gas is in a cylinder that has rigid walls. If the pressure of the gas is 2.00 atm, then the root-mean-square speed of the helium atoms is \(\upsilon {_r}{_m}{_s}\) = 176 m/s. By how much (in atmospheres) must the pressure be increased to increase the \(\upsilon {_r}{_m}{_s}\) of the He atoms by 100 m/s? Ignore any change in the volume of the cylinder.

Short Answer

Expert verified
The pressure must be increased by approximately 2.92 atm.

Step by step solution

01

Identify the given data

We are given the initial pressure of helium gas, \(P_1 = 2.00\) atm, and its initial root-mean-square speed, \(v_{rms1} = 176\) m/s. We need to find the increase in pressure such that \(v_{rms2} = v_{rms1} + 100 = 276\) m/s.
02

Understand the relationship between pressure and RMS speed

The root-mean-square speed \(v_{rms}\) of gas atoms is related to its temperature \(T\) by the equation \(v_{rms} = \sqrt{\frac{3kT}{m}}\), where \(k\) is the Boltzmann constant and \(m\) is the mass of the gas particles. However, considering the ideal gas law \(PV=nRT\), and since the volume \(V\) is constant in this problem, the pressure \(P\) is directly proportional to \(T\). Thus, \(v_{rms} \propto \sqrt{P}\).
03

Apply proportion relation

Using the relation \(v_{rms} \propto \sqrt{P}\), we can write: \(\frac{v_{rms2}}{v_{rms1}} = \sqrt{\frac{P_2}{P_1}}\). Substitute the known values: \(\frac{276}{176} = \sqrt{\frac{P_2}{2}}\).
04

Solve for \(P_2\)

Square both sides to remove the square root:\[\left(\frac{276}{176}\right)^2 = \frac{P_2}{2}\]Calculate \((\frac{276}{176})^2 = 2.46025\), thus:\[P_2 = 2 \times 2.46025 = 4.9205\] atm.
05

Determine the increase in pressure

The increase in pressure is given by \(\Delta P = P_2 - P_1\). Calculate:\[\Delta P = 4.9205 - 2.00 = 2.9205\] atm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental principle used to understand the behavior of gases. It is expressed as \( PV = nRT \), where:
  • \(P\) is the pressure of the gas
  • \(V\) is the volume of the gas
  • \(n\) is the number of moles
  • \(R\) is the ideal gas constant
  • \(T\) is the temperature in Kelvin
When dealing with problems involving gases, this equation helps relate these variables to each other.
In the exercise with helium gas, the volume \(V\) remains constant, simplifying the relationship between pressure and temperature.
This concept tells us that if the number of moles and the volume do not change, any increase in pressure is directly associated with an increase in temperature. This principle helps in calculating how the root-mean-square speed changes with pressure.
Pressure-Temperature Relationship
The connection between pressure and temperature in gases is crucial to understanding gas behavior. According to the ideal gas law, with constant volume and number of moles, the pressure of a gas is directly proportional to its temperature. If we double the temperature, the pressure also doubles, provided mass and volume remain unchanged.
In the context of the problem, increasing the root-mean-square speed of helium molecules requires raising the temperature, which in turn requires increasing the pressure due to their proportional relationship.
This understanding allows us to predict changes in gas behavior and calculate precise requirements, such as how much the pressure needs to be increased for a specific increase in the root-mean-square speed.
Helium Gas Properties
Helium is a noble gas with some unique properties that influence how it behaves as a gas. It is an inert, colorless, and odorless gas that is less dense than the air we breathe.
Here are some important properties of helium gas:
  • Low atomic mass: Helium atoms have lower mass compared to many other gases, allowing them to move more quickly, as seen in their relatively high root-mean-square speeds.
  • Non-reactive: Being a noble gas, helium does not easily form compounds with other elements, making it stable under various conditions.
  • Low density and high internal energy: Its low density contributes to unique behavior in terms of buoyancy and thermal properties.
These attributes are critical when considering helium in applications where pressure, volume, and temperature are important, such as in this problem where the speed of its atoms relate directly to its pressure and temperature due to its distinct physical characteristics.

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Most popular questions from this chapter

A 3.00-L tank contains air at 3.00 atm and 20.0\(^\circ\)C. The tank is sealed and cooled until the pressure is 1.00 atm. (a) What is the temperature then in degrees Celsius? Assume that the volume of the tank is constant. (b) If the temperature is kept at the value found in part (a) and the gas is compressed, what is the volume when the pressure again becomes 3.00 atm?

Oxygen (O\(_2\)) has a molar mass of 32.0 g/mol. What is (a) the average translational kinetic energy of an oxygen molecule at a temperature of 300 K; (b) the average value of the square of its speed; (c) the root-mean-square speed; (d) the momentum of an oxygen molecule traveling at this speed? (e) Suppose an oxygen molecule traveling at this speed bounces back and forth between opposite sides of a cubical vessel 0.10 m on a side. What is the average force the molecule exerts on one of the walls of the container? (Assume that the molecule's velocity is perpendicular to the two sides that it strikes.) (f) What is the average force per unit area? (g) How many oxygen molecules traveling at this speed are necessary to produce an average pressure of 1 atm? (h) Compute the number of oxygen molecules that are contained in a vessel of this size at 300 K and atmospheric pressure. (i) Your answer for part (h) should be three times as large as the answer for part (g). Where does this discrepancy arise?

A welder using a tank of volume 0.0750 m\(^3\) fills it with oxygen (molar mass 32.0 g/mol) at a gauge pressure of 3.00 \(\times\) 10\({^5}\) Pa and temperature of 37.0\(^\circ\)C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 22.0\(^\circ\)C, the gauge pressure of the oxygen in the tank is 1.80 \(\times\) 10\({^5}\) Pa. Find (a) the initial mass of oxygen and (b) the mass of oxygen that has leaked out.

If deep-sea divers rise to the surface too quickly, nitrogen bubbles in their blood can expand and prove fatal. This phenomenon is known as the \(bends\). If a scuba diver rises quickly from a depth of 25 m in Lake Michigan (which is fresh water), what will be the volume at the surface of an N\(_2\) bubble that occupied 1.0 mm\(^3\) in his blood at the lower depth? Does it seem that this difference is large enough to be a problem? (Assume that the pressure difference is due to only the changing water pressure, not to any temperature difference. This assumption is reasonable, since we are warm-blooded creatures.)

You have several identical balloons. You experimentally determine that a balloon will break if its volume exceeds 0.900 L. The pressure of the gas inside the balloon equals air pressure (1.00 atm). (a) If the air inside the balloon is at a constant 22.0\(^\circ\)C and behaves as an ideal gas, what mass of air can you blow into one of the balloons before it bursts? (b) Repeat part (a) if the gas is helium rather than air.

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