Chapter 18: Problem 34
Calculate the mean free path of air molecules at 3.50 \(\times\) 10\({^-}{^1}{^3}\) atm and 300 K. (This pressure is readily attainable in the laboratory; see Exercise 18.23.) As in Example 18.8, model the air molecules as spheres of radius 2.0 \(\times\) 10\({^-}{^1}{^0}\) m.
Short Answer
Expert verified
The mean free path of air molecules is approximately \( 1.86 \times 10^{-6} \text{ m} \).
Step by step solution
01
Recall the Formula for Mean Free Path
The mean free path, \( \lambda \), is given by the formula: \( \lambda = \frac{kT}{\sqrt{2} \pi d^2 P} \), where \( k \) is the Boltzmann constant \( (1.38 \times 10^{-23} \text{ J/K}) \), \( T \) is the temperature in Kelvin, \( d \) is the diameter of the molecules, and \( P \) is the pressure.
02
Convert Radius to Diameter
Given the radius of the air molecules is \( 2.0 \times 10^{-10} \text{ m} \). The diameter \( d \) will be twice the radius: \( d = 2 \times 2.0 \times 10^{-10} \text{ m} = 4.0 \times 10^{-10} \text{ m} \).
03
Insert Known Values into the Formula
Using \( T = 300 \text{ K} \), \( P = 3.50 \times 10^{-13} \text{ atm} \), and converting pressure from atm to pascals (1 atm \( = 1.013 \times 10^5 \text{ Pa}\)), we find \( P = 3.50 \times 10^{-13} \times 1.013 \times 10^5 \text{ Pa} = 3.5465 \times 10^{-8} \text{ Pa} \). Insert the values into the formula: \[ \lambda = \frac{(1.38 \times 10^{-23} \text{ J/K}) \times 300 \text{ K}}{\sqrt{2} \pi (4.0 \times 10^{-10} \text{ m})^2 \times 3.5465 \times 10^{-8} \text{ Pa}} \].
04
Calculate the Mean Free Path
Simplify the expression: \[ \lambda = \frac{4.14 \times 10^{-21} \text{ J}}{2.2212 \times 10^{-27} \text{ m}^2 \text{ Pa}} \]. This simplifies to \( \lambda \approx 1.86 \times 10^{-6} \text{ m} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Kinetic Theory of Gases
The kinetic theory of gases provides a fundamental understanding of how gases behave on a molecular level. It explains their macroscopic properties in terms of the motion of individual molecules.
- Basic Premises: According to this theory, a gas is composed of a large number of tiny particles (atoms or molecules) that are in continuous random motion.
- Interactions: These gas particles are considered to be point masses without volume, implying that the interactions between them occur only during collisions.
- Collisions: The collisions between particles, as well as with the walls of the container, are perfectly elastic. This means kinetic energy is conserved, leading to the pressure exerted by the gas.
- Pressure and Temperature: The pressure exerted by a gas results from the collisions of the molecules with the walls of the container, while temperature is a measure of the average kinetic energy of these particles.
Molecular Diameter
Molecular diameter is a key factor when calculating the mean free path of gas molecules. It represents the effective size of a molecule, which plays a significant role in how often molecules collide in a gas.
- Definition: The molecular diameter can be thought of as the "size" of the molecule, calculated as twice its radius.
- Importance in Calculations: When determining mean free path, the diameter directly influences how frequently molecules collide. This is because a larger diameter suggests that molecules will have more frequent interactions, reducing the mean free path.
- Spherical Assumption: In practice, molecules are often considered spherical for simplicity in calculations. This assumption allows the use of straightforward geometric formulas to describe molecular interactions.
Boltzmann Constant
The Boltzmann constant is a fundamental factor in many physical formulas, including those used in the kinetic theory of gases. It links macroscopic and microscopic physical quantities.
- Definition: The Boltzmann constant, denoted by the symbol \( k \), is a physical constant that relates the average kinetic energy of particles in a gas with the temperature of the gas, having a value of \( 1.38 \times 10^{-23} \text{ J/K} \).
- Role in Mean Free Path: In the mean free path equation \( \lambda = \frac{kT}{\sqrt{2} \pi d^2 P} \), the Boltzmann constant \( (k) \) allows us to account for the temperature effects on the kinetic energy and movement of molecules. This is vital in determining how frequently molecules collide.
- Fundamental in Thermodynamics: The constant plays a critical role in statistical mechanics and thermodynamics, bridging the statistical properties at atomic scales to thermodynamic properties at macroscopic levels.