Chapter 17: Problem 6
Convert the following Kelvin temperatures to the Celsius and Fahrenheit scales: (a) the midday temperature at the surface of the moon (400 K); (b) the temperature at the tops of the clouds in the atmosphere of Saturn (95 K); (c) the temperature at the center of the sun \((1.55 \times 10{^7} K)\).
Short Answer
Expert verified
400 K: 126.85 °C, 260.33 °F; 95 K: -178.15 °C, -288.67 °F; Sun's core: 1.5499973 x 10⁷ °C, 2.789995 x 10⁷ °F.
Step by step solution
01
Understanding Conversion Formulas
To convert Kelvin (K) to Celsius (°C), use the formula: \( °C = K - 273.15 \). To convert Kelvin (K) to Fahrenheit (°F), use the formula: \( °F = (K - 273.15) \times \frac{9}{5} + 32 \).
02
Convert 400 K to Celsius
Using the formula \( °C = K - 273.15 \), calculate: \( 400 - 273.15 = 126.85 \ °C \).
03
Convert 400 K to Fahrenheit
Using the formula \( °F = (400 - 273.15) \times \frac{9}{5} + 32 \), calculate: \( 126.85 \times \frac{9}{5} + 32 = 260.33 \ °F \).
04
Convert 95 K to Celsius
Using the formula \( °C = K - 273.15 \), calculate: \( 95 - 273.15 = -178.15 \ °C \).
05
Convert 95 K to Fahrenheit
Using the formula \( °F = (95 - 273.15) \times \frac{9}{5} + 32 \), calculate: \( -178.15 \times \frac{9}{5} + 32 = -288.67 \ °F \).
06
Convert \(1.55 \times 10^7\) K to Celsius
Using the formula \( °C = K - 273.15 \), calculate: \( 1.55 \times 10^7 - 273.15 = 1.5499973 \times 10^7 \ °C \).
07
Convert \(1.55 \times 10^7\) K to Fahrenheit
Using the formula \( °F = (1.55 \times 10^7 - 273.15) \times \frac{9}{5} + 32 \), calculate: \( 1.5499973 \times 10^7 \times \frac{9}{5} + 32 = 2.789995 \times 10^7 \ °F \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Kelvin to Celsius
Converting temperatures from Kelvin to Celsius is quite straightforward and follows a simple formula. The Kelvin and Celsius scales are directly related with a linear offset.
To convert a temperature from Kelvin to Celsius, just subtract 273.15 from the Kelvin temperature:
For example, if you're converting the moon's midday temperature at 400 K, the calculation is:
To convert a temperature from Kelvin to Celsius, just subtract 273.15 from the Kelvin temperature:
- Formula: \( °C = K - 273.15 \)
- This formula arises because 0 °C is equivalent to 273.15 K. The 273.15 is the freezing point of water in Kelvin, serving as the reference point between these scales.
For example, if you're converting the moon's midday temperature at 400 K, the calculation is:
- \( 400 - 273.15 = 126.85 \ \degree C \)
Kelvin to Fahrenheit
While converting from Kelvin to Fahrenheit involves a bit more math than converting to Celsius, it's still quite manageable with a methodical approach. Fahrenheit, unlike Celsius, does not directly align with Kelvin through a straightforward addition or subtraction due to its differing scale intervals.
Here's the step-by-step formula:
Here's the step-by-step formula:
- First, convert Kelvin to Celsius: \( K - 273.15 \).
- Next, convert the Celsius temperature to Fahrenheit using: \( °F = (°C \times \frac{9}{5}) + 32 \).
- Combine these into a single formula: \( °F = (K - 273.15) \times \frac{9}{5} + 32 \).
- \( °F = (400 - 273.15) \times \frac{9}{5} + 32 = 260.33 \ \degree F \)
Temperature scales
Understanding temperature scales is essential for interpreting different temperature readings across scientific fields and everyday contexts. Primarily, three temperature scales are widely used: Kelvin, Celsius, and Fahrenheit.
- Kelvin: Absolute thermodynamic scale. It starts from absolute zero, the point where molecular motion stops, set at 0 K. Kelvin numbers share the same step increment as Celsius, making direct conversions straightforward.
- Celsius: Based on the freezing and boiling points of water, 0 °C and 100 °C respectively. Predominantly used globally for weather and most routine temperatures.
- Fahrenheit: Commonplace in the United States. It defines 32 °F as the freezing point of water and 212 °F as its boiling point. As such, smaller temperature intervals make changes appear more significant compared to Celsius or Kelvin.