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A rocket with mass 5.00 \(\times\) 10\(^3\) kg is in a circular orbit of radius 7.20 \(\times\) 10\(^6\) m around the earth. The rocket's engines fire for a period of time to increase that radius to 8.80 \(\times\) 10\(^6\) m, with the orbit again circular. (a) What is the change in the rocket's kinetic energy? Does the kinetic energy increase or decrease? (b) What is the change in the rocket's gravitational potential energy? Does the potential energy increase or decrease? (c) How much work is done by the rocket engines in changing the orbital radius?

Short Answer

Expert verified
The kinetic energy decreases, potential energy increases, and work done by engines is positive.

Step by step solution

01

Analyze Given Data

We are given the mass of the rocket, which is \( m = 5.00 \times 10^3 \text{ kg} \). The initial radius of the circular orbit is \( r_1 = 7.20 \times 10^6 \text{ m} \), and the final radius is \( r_2 = 8.80 \times 10^6 \text{ m} \). We need to calculate the changes in kinetic and gravitational potential energies and then find the work done by the rocket engines.
02

Calculate Initial and Final Kinetic Energies

The kinetic energy of an object in a circular orbit is given by the formula \( KE = \frac{1}{2} m v^2 \). However, for an object in orbit, we also have \( v^2 = \frac{GM}{r} \) where \( G \) is the gravitational constant \( 6.674 \times 10^{-11} \text{ N}\cdot\text{m}^2/\text{kg}^2 \), and \( M \) is the mass of the Earth \( 5.972 \times 10^{24} \text{ kg} \). Thus, the initial kinetic energy \( KE_1 = \frac{1}{2} m \frac{GM}{r_1} \) and the final kinetic energy \( KE_2 = \frac{1}{2} m \frac{GM}{r_2} \). Calculate both \( KE_1 \) and \( KE_2 \) and find the change \( \Delta KE = KE_2 - KE_1 \).
03

Calculate Initial and Final Potential Energies

The gravitational potential energy is given by \( U = -\frac{GMm}{r} \). Calculate the initial potential energy \( U_1 = -\frac{GMm}{r_1} \) and the final potential energy \( U_2 = -\frac{GMm}{r_2} \). The change in potential energy is \( \Delta U = U_2 - U_1 \).
04

Determine Whether Energies Increase or Decrease

Since \( r_2 > r_1 \), \( \frac{1}{r_2} < \frac{1}{r_1} \) and thus \( KE_2 < KE_1 \). This means the kinetic energy decreases. Similarly, \( U_2 > U_1 \), meaning the potential energy increases, since the potential energy becomes less negative.
05

Calculate Work Done

The work done by the rocket engines is equal to the change in the mechanical energy of the system. This is given by \( W = \Delta KE + \Delta U \). Use the previously calculated change in kinetic and potential energies to find \( W \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Orbital Mechanics
Orbital mechanics is the study of the motion of objects in space, particularly around celestial bodies like planets. It uses principles from physics to explain how objects like rockets and satellites move. When a rocket or satellite orbits a planet, it follows a path that is determined by the gravitational pull of the planet and the object's velocity.

According to Kepler's laws and Newton's laws of motion, an object in orbit will travel in an elliptical path, but in special cases, like a circular orbit, the path can be a perfect circle. The strength of the gravitational force and the speed of the object determine the shape and stability of the orbit.
  • Gravitational force keeps the object in orbit by pulling it towards the celestial body.
  • Velocity keeps the object from crashing into the celestial body by moving it forward.
Understanding these mechanics is crucial to calculating how spacecraft, like rockets, can change orbit or stay in a stable orbit.
Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. In physics, it is expressed with the formula: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is the mass of the object and \( v \) is its velocity.

In terms of orbital motion, an object's kinetic energy depends on how fast it is moving along its orbit. It plays a significant role when analyzing how a rocket or satellite's energy changes when it moves within different orbits. In a circular orbit, the speed of an object can be derived from the gravitational relation to the radius: \[ v^2 = \frac{GM}{r} \] where \( G \) is the gravitational constant and \( M \) is the mass of the celestial body being orbited.
  • A smaller radius (closer orbit) means higher velocity, resulting in greater kinetic energy.
  • A larger radius (farther orbit) means lower velocity, resulting in lesser kinetic energy.
This relationship means that as a rocket or satellite moves to a higher orbit, its kinetic energy decreases due to a reduction in speed.
Gravitational Potential Energy
Gravitational potential energy (GPE) is the energy an object possesses because of its position in a gravitational field. For objects in orbit, this energy is affected by the distance from the center of the Earth. The formula for gravitational potential energy is: \[ U = -\frac{GMm}{r} \] where:
  • \( G \) is the universal gravitational constant
  • \( M \) is the mass of the Earth
  • \( m \) is the mass of the object
  • \( r \) is the distance from the center of the Earth
Gravitational potential energy is negative because it represents a bound state within the gravitational field.

As the radius increases (the object moves to a higher orbit), the magnitude of this negative potential energy decreases (becomes less negative), suggesting an increase in potential energy. This increase occurs because more energy must be invested to move the object further from the center of the Earth.
Satellite Motion
Satellite motion involves understanding how artificial satellites orbit planets. This is important for everything from GPS functionality to telecommunications. The balance between gravitational forces and velocity enables satellites to maintain their path around a planet effectively.

For a satellite in a stable orbit, the centrifugal force due to its velocity counteracts the gravitational pull from the planet. This results in a dynamic balance that keeps the satellite from either falling back to Earth or shooting off into space.
  • To change an orbit, energy must be added or removed, adjusting either speed or altitude (or both).
  • If a satellite speeds up, it will move to a higher orbit.
  • Slowing down will cause the satellite to descend to a lower orbit.
Understanding satellite motion helps in determining how much energy (work) is needed when changing orbits, such as when a rocket's engines fire to push it into a higher orbit as in the given exercise, resulting in a change in both kinetic and potential energies.

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Most popular questions from this chapter

The dwarf planet Pluto has an elliptical orbit with a semimajor axis of 5.91 \(\times\) 10\(^{12}\) m and eccentricity 0.249. (a) Calculate Pluto's orbital period. Express your answer in seconds and in earth years. (b) During Pluto's orbit around the sun, what are its closest and farthest distances from the sun?

A hammer with mass \(m\) is dropped from rest from a height \(h\) above the earth's surface. This height is not necessarily small compared with the radius \(R_E\) of the earth. Ignoring air resistance, derive an expression for the speed y of the hammer when it reaches the earth's surface. Your expression should involve \(h\), \(R_E\), and \(m_E\) (the earth's mass).

Your starship, the \(Aimless\) \(Wanderer\), lands on the mysterious planet Mongo. As chief scientist-engineer, you make the following measurements: A 2.50-kg stone thrown upward from the ground at 12.0 m/s returns to the ground in 4.80 s; the circumference of Mongo at the equator is 2.00 \(\times\) 10\(^5\) km; and there is no appreciable atmosphere on Mongo. The starship commander, Captain Confusion, asks for the following information: (a) What is the mass of Mongo? (b) If the \(Aimless\) \(Wanderer\) goes into a circular orbit 30,000 km above the surface of Mongo, how many hours will it take the ship to complete one orbit?

Titania, the largest moon of the planet Uranus, has \(\frac{1}{8}\) the radius of the earth and \(\frac{1}{1700}\) the mass of the earth. (a) What is the acceleration due to gravity at the surface of Titania? (b) What is the average density of Titania? (This is less than the density of rock, which is one piece of evidence that Titania is made primarily of ice.)

For a spherical planet with mass \(M\), volume \(V\), and radius \(R\), derive an expression for the acceleration due to gravity at the planet's surface, \(g\), in terms of the average density of the planet, \(\rho =\) \(M/V\), and the planet's diameter, \(D = 2R\). The table gives the values of \(D\) and \(g\) for the eight major planets: (a) Treat the planets as spheres. Your equation for \(g\) as a function of \(\rho\) and \(D\) shows that if the average density of the planets is constant, a graph of \(g\) versus \(D\) will be well represented by a straight line. Graph g as a function of \(D\) for the eight major planets. What does the graph tell you about the variation in average density? (b) Calculate the average density for each major planet. List the planets in order of decreasing density, and give the calculated average density of each. (c) The earth is not a uniform sphere and has greater density near its center. It is reasonable to assume this might be true for the other planets. Discuss the effect this nonuniformity has on your analysis. (d) If Saturn had the same average density as the earth, what would be the value of \(g\) at Saturn's surface?

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