Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

How many years older will you be 1.00 gigasecond from now? (Assume a 365-day year.)

Short Answer

Expert verified
You will be 32 years older in 1 gigasecond.

Step by step solution

01

Understand a Gigasecond

A gigasecond is equivalent to 10^9 seconds. It's a unit of measurement commonly used in scientific contexts to represent large amounts of time.
02

Convert Gigaseconds to Seconds

Since we know that 1 gigasecond is equal to 10^9 seconds, we now have the total time in seconds directly: 1 gigasecond = 10^9 seconds.
03

Convert Seconds to Minutes

There are 60 seconds in a minute. Hence, we compute the number of minutes in a gigasecond as follows:\[\text{Minutes} = \frac{10^9}{60} = \frac{1000000000}{60}\approx 16666666.67\text{ minutes}\]
04

Convert Minutes to Hours

There are 60 minutes in an hour. Hence, compute the number of hours:\[\text{Hours} = \frac{16666666.67}{60} = \approx 277777.78\text{ hours}\]
05

Convert Hours to Days

There are 24 hours in a day. Thus, compute the number of days:\[\text{Days} = \frac{277777.78}{24}\approx 11574.07\text{ days}\]
06

Convert Days to Years

Assuming a year has 365 days, divide the number of days by 365 to obtain the number of years:\[\text{Years} = \frac{11574.07}{365} \approx 31.71\text{ years}\]
07

Round to Find Whole Years

Since you typically talk about age in whole years, we can round 31.71 to the nearest whole number, which is 32.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Time Conversion
Time conversion is the process of changing a measure of time in one unit to another. This is important in many calculations, like from seconds to minutes, minutes to hours, or even seconds to years.
For example, to convert seconds to minutes, we use the fact that there are 60 seconds in one minute. This means if you have a gigasecond, which is 1,000,000,000 seconds, you divide by 60 to find the equivalent in minutes.
  • Converting minutes to hours uses the same concept but involves dividing by 60 again, because there are 60 minutes in an hour.
  • For hours to days, you divide by 24 because each day has 24 hours.
The conversion continues this way, using fundamental constants to switch from one unit to another, helping you to understand the magnitude of different timescales.
Scientific Notation
Scientific notation is a way to express very large or very small numbers in a simplified form, which is especially useful in scientific calculations.
A gigasecond, which represents 1,000,000,000 seconds, can be expressed in scientific notation as \(10^9\) seconds.
This notation is convenient in computation because it makes reading, writing, and working with large numbers manageable.
  • In scientific notation, a number is split into a coefficient and a power of ten. For example, \(1.0 \times 10^9\).
  • This helps in easily multiplying and dividing numbers by adjusting the exponents.
By employing scientific notation, calculations involving enormous figures, like a gigasecond, become much simpler and less error-prone.
Age Calculation
Age calculation using a given time span helps in estimating how much older you or someone will be after a specified duration.
In this exercise, the calculation is to determine how many years you will age in a gigasecond.
This involves converting one gigasecond into years and then seeing how many years that is.
  • The result comes from first determining how many seconds fit into a standard year (assuming 365 days).
  • By finding out how many of these segments of time fit into a gigasecond, you can determine the growth in age over such a period.
This can be a fun and insightful way to understand the vastness of a gigasecond and grip on how our age can change dramatically over such massive stretches of time.
Seconds to Years Conversion
The conversion from seconds to years is crucial to understand how a brief unit like a second correlates to something larger like a year.
One gigasecond consists of \(10^9\) seconds, which needs to be converted step-by-step into years for practical understanding.
To achieve this, you first convert seconds into minutes, then into hours, and so forth until reaching years.
  • This conversion involves using consistent constants: 60 seconds equals one minute, 60 minutes equals one hour, 24 hours equals one day, and typically, 365 days make up a year.
  • Finally, by dividing the total number of seconds by the total number of seconds in a year, you obtain how many years are in a gigasecond.
Understanding this extensive transformation provides insight into converting small units into far larger ones and is particularly beneficial in contexts requiring the grasp of enormous time periods, like predicting astronomical events or geological phenomena.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following conversions occur frequently in physics and are very useful. (a) Use 1 mi = 5280 ft and 1 h = 3600 s to convert 60 mph to units of ft/s. (b) The acceleration of a freely falling object is 32 ft/s\(^2\). Use 1 ft = 30.48 cm to express this acceleration in units of m/s\(^2\). (c) The density of water is 1.0 g/cm\(^3\). Convert this density to units of kg/m\(^3\).

Vector \(\overrightarrow{A}\) is 2.80 cm long and is 60.0\(^{\circ}\) above the \(x\)-axis in the first quadrant. Vector \(\overrightarrow{B}\) is 1.90 cm long and is 60.0\(^{\circ}\) below the x-axis in the fourth quadrant (Fig. E1.35).Use components to find the magnitude and direction of (a) \(\overrightarrow{A}\) \(+\) \(\overrightarrow{B}\); (b) \(\overrightarrow{A}\) \(-\) \(\overrightarrow{B}\); (c) \(\overrightarrow{B}\) \(-\) \(\overrightarrow{A}\). In each case, sketch the vector addition or subtraction and show that your numerical answers are in qualitative agreement with your sketch.

You decide to go to your favorite neighborhood restaurant. You leave your apartment, take the elevator 10 flights down (each flight is 3.0 m), and then walk 15 m south to the apartment exit. You then proceed 0.200 km east, turn north, and walk 0.100 km to the entrance of the restaurant. (a) Determine the displacement from your apartment to the restaurant. Use unit vector notation for your answer, clearly indicating your choice of coordinates. (b) How far did you travel along the path you took from your apartment to the restaurant, and what is the magnitude of the displacement you calculated in part (a)?

You are given two vectors \(\overrightarrow{A}\) = \(-\)3.00\(\hat{\imath}\) \(+\) 6.00\(\hat{\jmath}\) and \(\overrightarrow{B}\) = 7.00\(\hat{\imath}\) \(+\) 2.00\(\hat{\jmath}\). Let counterclockwise angles be positive. (a) What angle does \(\overrightarrow{A}\) make with the \(+\)x-axis? (b) What angle does \(\overrightarrow{B}\) make with the \(+\)x-axis? (c) Vector \(\overrightarrow{C}\) is the sum of \(\overrightarrow{A}\) and \(\overrightarrow{B}\), so \(\overrightarrow{C}\) = \(\overrightarrow{A}\) \(+\) \(\overrightarrow{B}\). What angle does \(\overrightarrow{C}\) make with the \(+\)x-axis?

Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 26.0 m in a direction 60.0\(^{\circ}\) west of north. Jane walks 16.0 m in a direction 30.0\(^{\circ}\) south of west. They then stop and turn to face each other. (a) What is the distance between them? (b) In what direction should Ricardo walk to go directly toward Jane?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free