Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Two masses hang from two strings of equal length that are attached to the ceiling of a car. One mass is over the driver's seat; the other is over the passenger's seat. As the car makes a sharp turn, both masses swing away from the center of the turn. In their resulting positions, will they be farther apart, closer together, or the same distance apart as they were when the car wasn't turning?

Short Answer

Expert verified
Answer: During a sharp turn, the distance between the two masses hanging from strings will increase as they swing away from the center of the turn due to the net force acting on them.

Step by step solution

01

Visualize the problem

Picture the car in the stationary scenario, with two masses hanging from the ceiling by strings of equal length. When the car is not turning, the masses will be hanging straight down due to gravity, and the distance between them will be equal to the distance between the points of attachment to the ceiling. Now imagine the car making a sharp turn. As it does so, both masses will swing away from the center of the turn due to the centripetal force acting on them. Our goal is to determine whether they will be farther apart, closer together, or the same distance apart as they were when the car wasn't turning.
02

Analyze the forces on the masses

Let's consider the forces acting on the masses during the turn. Each mass will experience two forces: gravitational force (Fg) acting vertically downward and the centripetal force (Fc) acting horizontally towards the center of the turn. The net force (Fnet) acting on each mass will be the vector sum of these two forces.
03

Determine the direction of net force

The net force (Fnet) will act at an angle with respect to the vertical direction since it is the vector sum of the gravitational force (Fg) and the centripetal force (Fc) which act perpendicular to each other. This will cause the masses to swing away from the center of the turn, and the angle between the strings and the vertical direction will increase. This angle can be denoted as theta (θ).
04

Analyze the change in distance

Since both masses are swinging away from the center of the turn due to net forces acting on them, their horizontal components of displacement are in the same direction. The vertical components of displacement (strings length) remain constant. Therefore, the distance between the masses in their resulting positions will be greater than their original distance when the car was not turning.
05

Conclusion

After the car makes a sharp turn, the two masses hanging from the strings will be farther apart than they were when the car wasn't turning due to the net force causing them to swing away from the center of the turn.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Mars orbits the Sun at a mean distance of 228 million \(\mathrm{km},\) in a period of 687 days. The Earth orbits at a mean distance of 149.6 million \(\mathrm{km},\) in a period of 365.26 days. a) Suppose Earth and Mars are positioned such that Earth lies on a straight line between Mars and the Sun. Exactly 365.26 days later, when the Earth has completed one orbit, what is the angle between the Earth-Sun line and the Mars-Sun line? b) The initial situation in part (a) is a closest approach of Mars to Earth. What is the time, in days, between two closest approaches? Assume constant speed and circular orbits for both Mars and Earth. c) Another way of expressing the answer to part (b) is in terms of the angle between the lines drawn through the Sun, Earth, and Mars in the two closest approach situations. What is that angle?

A vinyl record that is initially turning at \(33 \frac{1}{3}\) rpm slows uniformly to a stop in a time of \(15 \mathrm{~s}\). How many rotations are made by the record while stopping?

A race car is making a U-turn at constant speed. The coefficient of friction between the tires and the track is \(\mu_{\mathrm{s}}=1.20 .\) If the radius of the curve is \(10.0 \mathrm{~m},\) what is the maximum speed at which the car can turn without sliding? Assume that the car is performing uniform circular motion.

A rock attached to a string moves clockwise in uniform circular motion. In which direction from point \(A\) is the rock thrown off when the string is cut? a) centrifugal b) normal c) gravity d) tension

A top spins for 10.0 min, beginning with an angular speed of 10.0 rev/s. Determine its angular acceleration, assuming it is constant, and its total angular displacement.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free