Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A hook above a stage is rated to support 150. lb. A 3 -lb rope is attached to the hook, and a 147 -lb actor is going to attempt to swing across the stage on the rope. Will the hook hold the actor up during the swing?

Short Answer

Expert verified
Answer: Yes, the hook can support the combined weight of the rope and the actor during the swing.

Step by step solution

01

Determine the total weight of the rope and actor

First, we need to find the total weight of the rope and actor. To do this, we simply add the weight of the rope (3lb) to the weight of the actor (147lb). So, the total weight is: Total weight = Weight of rope + Weight of actor
02

Calculate the total weight

Now we can insert the given values and calculate the total weight. Total weight = 3lb + 147lb Total weight = 150lb
03

Compare the total weight to the hook's weight limit

Now, we need to compare the total weight (150lb) to the weight limit of the hook (also 150lb). We want to know if the hook can support this weight, so we must see if the total weight is less than or equal to the weight limit of the hook.
04

Determine if the hook can hold the actor up during the swing

Since the total weight (150lb) is equal to the weight limit of the hook (150lb), the hook will be able to hold the actor up during the swing. The hook will be under its maximum rated weight, and thus should be able to safely support the actor and rope.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Weight Calculation
Understanding weight calculation is crucial when determining the stress and maximum load capacity of objects in everyday scenarios. Calculating weight involves summing up individual weights of all components involved. For instance, in this problem, we need to find the weight exerted by both the rope and the actor acting on the hook.
  • The rope weighs 3 pounds.
  • The actor weighs 147 pounds.
Adding these together, we arrive at a total weight: Total weight = 3 lb (rope) + 147 lb (actor) = 150 lb. It’s essential to perform these calculations prior to placing any load on a supporting structure to ensure safety and prevent overloading.
Force and Weight Limits
Force is the push or pull acting upon an object. When considering weight limits, it's important to determine whether the force exerted by a mass (in this case, the combined weight of the rope and the actor) exceeds the maximum capacity of the object supporting it—here, the hook. Generally, this maximum capacity is referred to as the weight limit. To assess the hook's ability:
  • We calculate the total weight: 150 lb.
  • We compare this with the hook's weight limit: 150 lb.
If the load is equal to or less than the weight limit, the structure is considered safe. In our case, the hook can hold 150 lb, which matches the combined weight of the rope and actor. Although this indicates the hook should hold, it’s important to consider safety margins, especially if dynamic or additional forces come into play during the swing, such as increased tension.
Static Equilibrium
Static equilibrium occurs when all forces acting on a system balance out such that the system remains stable and at rest. In terms of a hanging object like our stage scenario, this means the upward forces need to equal the downward forces. For the hook to maintain static equilibrium:
  • Downward force (weight of rope and actor) must equal the upward force (capacity of the hook).
  • If both are balanced, as they are here at 150 lb each, the actor can safely swing.
However, it's essential to note that equilibrium doesn't guarantee safety if close to limits. External factors such as sudden jerks or swings could introduce additional forces, taking the setup out of equilibrium. Therefore, engineers often design systems with safety factors beyond static equilibrium conditions to assure reliability under various conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 20.0 -g metal cylinder is placed on a turntable, with its center 80.0 cm from the turntable's center. The coefficient of static friction between the cylinder and the turntable's surface is μs=0.800. A thin, massless string of length 80.0 cm connects the center of the turntable to the cylinder, and initially, the string has zero tension in it. Starting from rest, the turntable very slowly attains higher and higher angular velocities, but the turntable and the cylinder can be considered to have uniform circular motion at any instant. Calculate the tension in the string when the angular velocity of the turntable is 60.0 rpm (rotations per minute).

A particular Ferris wheel takes riders in a vertical circle of radius 9.0 m once every 12.0 s. a) Calculate the speed of the riders, assuming it to be constant. b) Draw a free-body diagram for a rider at a time when she is at the bottom of the circle. Calculate the normal force exerted by the seat on the rider at that point in the ride. c) Perform the same analysis as in part (b) for a point at the top of the ride.

Two skaters, A and B, of equal mass are moving in clockwise uniform circular motion on the ice. Their motions have equal periods, but the radius of skater A's circle is half that of skater B's circle a) What is the ratio of the speeds of the skaters? b) What is the ratio of the magnitudes of the forces acting on each skater?

A small block of mass m is in contact with the inner wall of a large hollow cylinder. Assume the coefficient of static friction between the object and the wall of the cylinder is μ. Initially, the cylinder is at rest, and the block is held in place by a peg supporting its weight. The cylinder starts rotating about its center axis, as shown in the figure, with an angular acceleration of α. Determine the minimum time interval after the cylinder begins to rotate before the peg can be removed without the block sliding against the wall.

A carousel at a carnival has a diameter of 6.00 m. The ride starts from rest and accelerates at a constant angular acceleration to an angular speed of 0.600 rev/s in 8.00 s. a) What is the value of the angular acceleration? b) What are the centripetal and angular accelerations of a seat on the carousel that is 2.75 m from the rotation axis? c) What is the total acceleration, magnitude and direction, 8.00 s after the angular acceleration starts?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free