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A 3.0 -kg ball of clay with a speed of 21 m/s is thrown against a wall and sticks to the wall. What is the magnitude of the impulse exerted on the ball?

Short Answer

Expert verified
Answer: The magnitude of the impulse exerted on the ball is 63 kg m/s.

Step by step solution

01

Identify the given quantities

In this problem, we are given the mass (m) of the ball of clay as 3.0 kg and its initial velocity (v_initial) as 21 m/s. The ball sticks to the wall, which means that its final velocity (v_final) will be 0 m/s.
02

Calculate the initial momentum of the ball

The momentum is given by mass times velocity: momentum=m×v. To find the initial momentum, we plug in the values for mass and initial velocity: momentuminitial=m×vinitial momentuminitial=3.0kg×21m/s momentuminitial=63kgm/s
03

Calculate the final momentum of the ball

As the ball sticks to the wall, its final velocity is 0 m/s. Therefore, the final momentum will also be 0: momentumfinal=m×vfinal momentumfinal=3.0kg×0m/s momentumfinal=0kgm/s
04

Calculate the change in momentum

The change in momentum (or impulse) is the difference between the final and initial momentums: I=momentumfinalmomentuminitial I=0kgm/s63kgm/s I=63kgm/s
05

Find the magnitude of the impulse

The magnitude of the impulse is the absolute value of the impulse: |I|=|63kgm/s| |I|=63kgm/s The magnitude of the impulse exerted on the ball is 63 kg m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
Conservation of momentum is a fundamental principle in physics stating that the total momentum of a closed system remains constant, provided no external forces act on it. In simpler terms, it's like ensuring that the account balance is unchanged, no matter how money gets transferred among accounts, as long as there is no deposit or withdrawal.
In our exercise, the ball of clay initially has momentum due to its motion towards the wall. When the ball hits the wall and sticks, an external force applies a change to its momentum. Thus, the total system here isn't entirely closed because the wall exerts an external force to stop the ball, affecting its momentum.
While the concept generally applies to isolated systems, understanding the interaction between the ball and the wall helps in visualizing real-world applications of momentum conservation.
Impulse-Momentum Theorem
The impulse-momentum theorem is a crucial concept in dynamics, relating the impulse applied to an object to its change in momentum. Impulse is essentially a measure of how much the momentum changes and is calculated by the product of force and the time during which the force acts.
  • Impulse: Change in momentum
  • Mathematically: \ I = \Delta p
  • Δp=pfinalpinitial
In our clay exercise, the impulse exerted by the wall on the ball is equal to the negative change in the ball's momentum. The negative sign indicates that the ball's direction changed as it goes from moving towards the wall to stopping.
Understanding this relationship allows you to see how force over time can drastically affect how objects speed up or slow down.
Physics Problem Solving
When it comes to solving physics problems like the one in this exercise, it's all about breaking down the problem into small, manageable steps:
  • Identify what is given and what needs to be found.
  • Use logical reasoning and equations relevant to the problem.
  • Perform calculations meticulously to avoid small mistakes.
  • Interpret the result and ensure it makes sense within the problem context.
In the case of the clay ball impacting the wall, the process involves clearly outlining the given variables, calculating initial and final momentum, and then determining impulse. Each step leads logically to the next, ensuring a systematic approach that meets the desired outcome.
Thus, honing these skills can make seemingly intricate physics exercises more navigable and less daunting.
Collision Dynamics
Collision dynamics examines the forces and interactions occurring during collisions, focusing on momentum changes, impacts, and energy exchange. In our clay example, the ball's sudden stop upon reaching the wall illustrates an inelastic collision, where two objects stick together post-impact, and kinetic energy is not conserved.
  • Momentum before impact: Ball has significant momentum.
  • During impact: Wall exerts a force, changing momentum.
  • After impact: Ball's momentum is zero, highlighting energy dissipation.
The study of different collision types clarifies how objects behave when they meet. Understanding these principles is fundamental to analyzing real-world interactions, from simple classroom physics problems to complex traffic accident reconstructive studies.

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Most popular questions from this chapter

A small car of mass 1000 . kg traveling at a speed of 33.0 m/s collides head on with a large car of mass 3000 kg traveling in the opposite direction at a speed of 30.0 m/s. The two cars stick together. The duration of the collision is 100.ms. What acceleration (in g ) do the occupants of the small car experience? What acceleration (in g ) do the occupants of the large car experience?

An 83.0 -kg running back leaps straight ahead toward the end zone with a speed of 6.50 m/s. A 115 -kg linebacker, keeping his feet on the ground, catches the running back and applies a force of 900.N in the opposite direction for 0.750 s before the running back's feet touch the ground. a) What is the impulse that the linebacker imparts to the running back? b) What change in the running back's momentum does the impulse produce? c) What is the running back's momentum when his feet touch the ground? d) If the linebacker keeps applying the same force after the running back's feet have touched the ground, is this still the only force acting to change the running back's momentum?

Although they don't have mass, photons-traveling at the speed of light-have momentum. Space travel experts have thought of capitalizing on this fact by constructing solar sails-large sheets of material that would work by reflecting photons. Since the momentum of the photon would be reversed, an impulse would be exerted on it by the solar sail, and-by Newton's Third Law-an impulse would also be exerted on the sail, providing a force. In space near the Earth, about 3.841021 photons are incident per square meter per second. On average, the momentum of each photon is 1.301027 kg m/s. For a 1000.kg spaceship starting from rest and attached to a square sail 20.0 m wide, how fast could the ship be moving after 1 hour? One week? One month? How long would it take the ship to attain a speed of 8000.m/s, roughly the speed of the space shuttle in orbit?

Tennis champion Venus Williams is capable of serving a tennis ball at around 127 mph. a) Assuming that her racquet is in contact with the 57.0 -g ball for 0.250 s, what is the average force of the racquet on the ball? b) What average force would an opponent's racquet have to exert in order to return Williams's serve at a speed of 50.0mph, assuming that the opponent's racquet is also in contact with the ball for 0.250 s?

NASA has taken an increased interest in near Earth asteroids. These objects, popularized in recent blockbuster movies, can pass very close to Earth on a cosmic scale, sometimes as close as 1 million miles. Most are small-less than 500 m across and while an impact with one of the smaller ones could be dangerous, experts believe that it may not be catastrophic to the human race. One possible defense system against near Earth asteroids involves hitting an incoming asteroid with a rocket to divert its course. Assume a relatively small asteroid with a mass of 2.101010 kg is traveling toward the Earth at a modest speed of 12.0 km/s. a) How fast would a large rocket with a mass of 8.00104 kg have to be moving when it hit the asteroid head on in order to stop the asteroid? b) An alternative approach would be to divert the asteroid from its path by a small amount to cause it to miss Earth. How fast would the rocket of part (a) have to be traveling at impact to divert the asteroid's path by 1.00 ? In this case, assume that the rocket hits the asteroid while traveling along a line perpendicular to the asteroid's path.

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