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Cosmic rays from space that strike Earth contain some charged particles with energies billions of times higher than any that can be produced in the biggest accelerator. One model that was proposed to account for these particles is shown schematically in the figure. Two very strong sources of magnetic fields move toward each other and repeatedly reflect the charged particles trapped between them. (These magnetic field sources can be approximated as infinitely heavy walls from which charged particles get reflected elastically.) The high- energy particles that strike the Earth would have been reflected a large number of times to attain the observed energies. An analogous case with only a few reflections demonstrates this effect. Suppose a particle has an initial velocity of \(-2.21 \mathrm{~km} / \mathrm{s}\) (moving in the negative \(x\) -direction, to the left), the left wall moves with a velocity of \(1.01 \mathrm{~km} / \mathrm{s}\) to the right, and the right wall moves with a velocity of \(2.51 \mathrm{~km} / \mathrm{s}\) to the left. What is the velocity of the particle after six collisions with the left wall and five collisions with the right wall?

Short Answer

Expert verified
Answer: The final velocity of the charged particle is -2.81 km/s.

Step by step solution

01

Establish the initial conditions

Initially, the particle has a velocity of \(-2.21 \; km/s\), the left wall has a velocity of \(1.01 \; km/s\), and the right wall has a velocity of \(-2.51 \; km/s\).
02

Calculate the relative velocities

Before each collision, we need to calculate the relative velocity of the particle with respect to each wall. The relative velocity of the particle with respect to the left wall is \(v_{p,left} = -2.21\; km/s - 1.01\; km/s = -3.22 \; km/s\). Similarly, the relative velocity of the particle with respect to the right wall is \(v_{p,right} = -2.21\; km/s - (-2.51\; km/s) = 0.3\; km/s\).
03

Reflect the particle after a collision

After each collision, the relative velocity of the particle with respect to the wall is reversed. Hence, after a collision with the left wall, the relative velocity of the particle with respect to the left wall is \(-v_{p,left} = 3.22 \; km/s\). Similarly, after a collision with the right wall, the relative velocity of the particle with respect to the right wall is \(-v_{p,right} = -0.3\; km/s\).
04

Repeat the process for 6 collisions with the left wall and 5 collisions with the right wall

After each collision, we need to add up the relative velocity of the particle with respect to the wall and the velocity of the wall itself to get the velocity of the particle after the collision. We'll do this repeatedly for 6 collisions with the left wall and 5 collisions with the right wall: For 6 collisions with the left wall: \(v_{1} = 3.22 \; km/s + 1.01 \; km/s = 4.23 \; km/s\) \(v_{2} = -3.22 \; km/s + 1.01 \; km/s = -2.21 \; km/s\) \(v_{3} = 3.22 \; km/s + 1.01 \; km/s = 4.23 \; km/s\) \(v_{4} = -3.22 \; km/s + 1.01 \; km/s = -2.21 \; km/s\) \(v_{5} = 3.22 \; km/s + 1.01 \; km/s = 4.23 \; km/s\) \(v_{6} = -3.22 \; km/s + 1.01 \; km/s = -2.21 \; km/s\) For 5 collisions with the right wall: \(v_{1} = -0.3\; km/s + (-2.51 \; km/s) = -2.81 \; km/s\) \(v_{2} = 0.3\; km/s + (-2.51 \; km/s) = -2.21 \; km/s\) \(v_{3} = -0.3\; km/s + (-2.51 \; km/s) = -2.81 \; km/s\) \(v_{4} = 0.3\; km/s + (-2.51 \; km/s) = -2.21 \; km/s\) \(v_{5} = -0.3\; km/s + (-2.51 \; km/s) = -2.81 \; km/s\)
05

Determine the final velocity of the particle

After six collisions with the left wall, the particle has a velocity of \(-2.21 \; km/s\). After five collisions with the right wall, the particle has a velocity of \(-2.81 \; km/s\). Therefore, the final velocity of the particle is \(-2.81\; km/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Charged Particles
Charged particles, like the ones found in cosmic rays, are particles that carry an electrical charge. These particles can be electrons or protons, and their charge makes them susceptible to electromagnetic forces. Charged particles are accelerated by electric fields and deflected by magnetic fields. When they are caught between two moving magnetic fields, their behavior becomes particularly interesting.
Understanding how these particles interact with fields is crucial because it helps explain phenomena from everyday technology to cosmic events. Charged particles are not only theoretical constructs but are involved in practical applications like cathode-ray tubes and particle accelerators.
Magnetic Fields
Magnetic fields are invisible forces generated by magnetic objects, such as magnetic field sources in the exercise. These fields exert a force on charged particles, causing them to move in circular or spiral paths.
Magnetic fields are typically described by field lines that illustrate the direction and strength of the magnetic force. They impact charged particles by changing their direction, not their speed, which can explain why particles reflect off the fields as if hitting a wall. This effect is paramount in many physics applications, including keeping particles within paths in accelerators and protecting Earth from cosmic radiation.
Velocity Calculation
Velocity is a vector quantity that has both magnitude and direction. When calculating velocities, especially in elastic collisions, knowing the relative velocity between objects is essential.
In this exercise, the velocity of the particle changes due to the movement of magnetic fields, likened to walls. The steps involve calculating the velocity of the particle relative to each wall before and after collisions.
Use the formula:
  • Relative velocity before collision = velocity of particle - velocity of wall
  • Relative velocity after collision = - (relative velocity before collision)
This equation helps in determining how velocities change due to interactions between particles and walls, verifying the principle of conservation of momentum in elasticity.
Elastic Collisions
An elastic collision is a type of collision where the total kinetic energy of the system is conserved. This means that the sum of the kinetic energy before the collision is equal to the sum after the collision.
In the given problem, particles collide elastically with moving magnetic field sources.
Key points of elastic collisions include:
  • Conservation of kinetic energy
  • Absence of permanent deformation or generation of heat
  • Reversal of relative velocity across colliding surfaces
For instance, in elastic collisions between the charged particle and the magnetic walls, the speed doesn't change although kinetic energy and momentum are transferred. This ability to conserve energy allows cosmic particles to gain significant energy after numerous reflections, explaining their high energies when striking the Earth.

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Most popular questions from this chapter

An automobile with a mass of \(1450 \mathrm{~kg}\) is parked on a moving flatbed railcar; the flatbed is \(1.5 \mathrm{~m}\) above the ground. The railcar has a mass of \(38,500 \mathrm{~kg}\) and is moving to the right at a constant speed of \(8.7 \mathrm{~m} / \mathrm{s}\) on a frictionless rail. The automobile then accelerates to the left, leaving the railcar at a speed of \(22 \mathrm{~m} / \mathrm{s}\) with respect to the ground. When the automobile lands, what is the distance \(D\) between it and the left end of the railcar? See the figure.

A satellite with a mass of \(274 \mathrm{~kg}\) approaches a large planet at a speed \(v_{i, 1}=13.5 \mathrm{~km} / \mathrm{s}\). The planet is moving at a speed \(v_{i, 2}=10.5 \mathrm{~km} / \mathrm{s}\) in the opposite direction. The satellite partially orbits the planet and then moves away from the planet in a direction opposite to its original direction (see the figure). If this interaction is assumed to approximate an elastic collision in one dimension, what is the speed of the satellite after the collision? This so-called slingshot effect is often used to accelerate space probes for journeys to distance parts of the solar system (see Chapter 12).

Three birds are flying in a compact formation. The first bird, with a mass of \(100 . \mathrm{g}\) is flying \(35.0^{\circ}\) east of north at a speed of \(8.00 \mathrm{~m} / \mathrm{s}\). The second bird, with a mass of \(123 \mathrm{~g}\), is flying \(2.00^{\circ}\) east of north at a speed of \(11.0 \mathrm{~m} / \mathrm{s}\). The third bird, with a mass of \(112 \mathrm{~g}\), is flying \(22.0^{\circ}\) west of north at a speed of \(10.0 \mathrm{~m} / \mathrm{s}\). What is the momentum vector of the formation? What would be the speed and direction of a \(115-\mathrm{g}\) bird with the same momentum?

Although they don't have mass, photons-traveling at the speed of light-have momentum. Space travel experts have thought of capitalizing on this fact by constructing solar sails-large sheets of material that would work by reflecting photons. Since the momentum of the photon would be reversed, an impulse would be exerted on it by the solar sail, and-by Newton's Third Law-an impulse would also be exerted on the sail, providing a force. In space near the Earth, about \(3.84 \cdot 10^{21}\) photons are incident per square meter per second. On average, the momentum of each photon is \(1.30 \cdot 10^{-27} \mathrm{~kg} \mathrm{~m} / \mathrm{s}\). For a \(1000 .-\mathrm{kg}\) spaceship starting from rest and attached to a square sail \(20.0 \mathrm{~m}\) wide, how fast could the ship be moving after 1 hour? One week? One month? How long would it take the ship to attain a speed of \(8000 . \mathrm{m} / \mathrm{s}\), roughly the speed of the space shuttle in orbit?

A golf ball is released from rest from a height of \(0.811 \mathrm{~m}\) above the ground and has a collision with the ground, for which the coefficient of restitution is \(0.601 .\) What is the maximum height reached by this ball as it bounces back up after this collision?

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