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If I look in a mirror while wearing a blue shirt, I see a blue shirt in my reflection, not a red shirt. But according to the Compton effect, the photons that bounce back should have a lower energy and therefore a longer wavelength. Explain why my reflection shows the same color shirt as am wearing.

Short Answer

Expert verified
Short Answer: The Compton effect does not apply to mirror reflections because the reflection in a mirror involves surface (specular) reflection and not scattering off charged particles like electrons. The specular reflection maintains the integrity of the light waves and does not cause a noticeable change in the wavelength or color of the reflected photons. As a result, you see the same color shirt in your reflection as the one you are wearing.

Step by step solution

01

Understanding the Compton Effect

The Compton Effect is a phenomenon in which a photon scatters off a charged particle (typically an electron). As a result, the scattered photon has a lower energy and a longer wavelength compared to its initial state. The energy loss results in a change in the color of the light.
02

Wavelength Shift and Colors

As per the Compton effect, the scattered photons should have a longer wavelength and a lower energy, which causes a shift in the color of light. For instance, if the initial color was blue (shorter wavelength), it would shift towards a red color (longer wavelength) if the Compton effect was responsible for the color change in the mirror reflection.
03

Reflection in Mirror

When you see your reflection in a mirror, the photons from the surface of the shirt reach the mirror and then reflect back to your eyes. The reflection occurs because the mirror has a smooth surface that allows light to bounce off with minimal energy loss.
04

Why the Compton Effect Doesn't Apply

In the scenario given, the Compton effect does not play a significant role because the mirror reflection involves surface (specular) reflection and not scattering off charged particles like electrons. Specular reflection maintains the integrity of the light waves and does not cause a noticeable change in the wavelength or color of the reflected photons. Therefore, the Compton effect does not apply to mirror reflections, and you will see the same color shirt as you are wearing. In summary, although the Compton effect causes a wavelength shift in scattered photons, this phenomenon does not apply to mirror reflections. The specular reflection in the mirror ensures that the reflected light maintains its original wavelength and color, allowing you to observe the same color shirt in your reflection as the one you are wearing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specular Reflection
The phenomenon of specular reflection is akin to what you experience when you gaze into a mirror. It refers to the reflection of light from a smooth surface, where the reflected rays are parallel if the incident rays are parallel. This is different from diffuse reflection, where the surface is rough, scattering light in many directions, often making the reflected light appear dimmer.

A mirror's surface is highly polished and thus facilitates specular reflection. When light encounters such a smooth surface, it bounces back at an angle equal to the angle of incidence, much like a tennis ball thrown straight onto the floor. Moreover, the energy of the light and its inherent properties, such as wavelength and color, remain largely unchanged during this process.

One might wonder how this type of reflection relates to observing colors in a mirror. Essentially, when your shirt reflects blue light, this light hits the mirror and undergoes specular reflection, maintaining its blue hue and wavelength, allowing you to perceive your shirt as blue.
Photon Scattering
Photon scattering is a fundamental concept in understanding many optical effects, including the aforementioned Compton effect. It involves the bouncing off of photons—particles of light—when they interact with other particles, such as electrons. In contrast to specular reflection, scattering processes often result in changes to the properties of the photons.

The Compton effect is one such instance where photon scattering leads to a longer wavelength and lower energy. However, this scattering process occurs at the microscopic level when photons collide with individual charged particles. The change in wavelength (and color) after such a collision is observable under specific scientific conditions and is not a common occurrence in everyday life.

The reason your shirt looks the same color in the mirror as it does in reality is because the light from your shirt is not undergoing photon scattering with subatomic particles in the mirror. Instead, it is being specularly reflected, a process that preserves the characteristics of the light, including its color.
Wavelength and Color Relationship
The colors that we perceive are intrinsically connected to the wavelengths of light. Blue light has a shorter wavelength, while red light has a longer wavelength. When white light strikes an object—such as your shirt—certain wavelengths are absorbed while others are reflected. Your blue shirt appears blue because it reflects blue light and absorbs other colors.

In terms of physics, when photons encounter an object, their wavelength determines the color seen by the human eye. A blue shirt appears blue under normal lighting conditions because the photons corresponding to blue wavelengths are the ones predominantly reflected from the shirt's surface. In the case of the Compton effect, if photon scattering were to occur and these photons were to be transferred to a lower energy state, it might result in a longer wavelength, potentially altering the perceived color of your shirt.

However, as illuminated in the Compton effect exercise, specular reflection in mirrors does not change the wavelength of the photons significantly. Thus, no shift in the color occurs, and you see the blue shirt with the same blue color when looking in the mirror.

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Most popular questions from this chapter

What would a classical physicist expect would be the result of shining a brighter UV lamp on a metal surface, in terms of the energy of emitted electrons? How does this differ from what the theory of the photoelectric effect predicts?

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Consider an electron whose de Broglie wavelength is equal to the wavelength of green light (about \(550 \mathrm{nm}\) ). a) Treating the electron nonrelativistically, what is its speed? b) Does your calculation confirm that a nonrelativistic treatment is sufficient? c) Calculate the kinetic energy of the electron in \(\mathrm{eV}\).

Now consider de Broglie waves for a (relativistic) particle of mass \(m\), momentum \(p=m v \gamma\), and total energy \(E=m c^{2} \gamma\), with \(\gamma=\left[1-(v / c)^{2}\right]^{-1 / 2}\). The waves have wavelength \(\lambda=h / p\) and frequency \(f=E / h\) as before, but with the relativistic momentum and energy. a) Calculate the dispersion relation for these waves. b) Calculate the phase and group velocities of these waves. Now which corresponds to the classical velocity of the particle?

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