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In the age of interstellar travel, an expedition is mounted to an interesting star 2000.0 light-years from Earth. To make it possible to get volunteers for the expedition, the planners guarantee that the round trip to the star will take no more than \(10.000 \%\) of a normal human lifetime. (At that time the normal human lifetime is 400.00 years.) What is the minimum speed the ship carrying the expedition must travel?

Short Answer

Expert verified
Based on the given information, find the minimum speed of the spaceship for the round trip to take no more than 10% of a normal human lifetime, assuming the distance to the star is 2000 light-years and a human lifetime is 400 years.

Step by step solution

01

Find the maximum time allowed for the trip

The maximum time for the trip is supposed to be 10% of the normal human lifetime (400 years). So, we need to find 10% of 400 years: Maximum time allowed = (10/100) × 400 years
02

Calculate the round-trip distance

Since the spaceship is going to the star 2000 light-years away and coming back, the round-trip distance will be double the one-way distance: Round-trip distance = 2 × 2000 light-years
03

Convert light-years to km

To calculate the minimum speed, we need to convert the distance from light-years to km. 1 light-year is approximately 9.461 × 10^12 km. So we can calculate the round-trip distance in km: Round-trip distance in km = (2 × 2000 light-years) × (9.461 × 10^12 km/light-year)
04

Find the maximum time allowed in seconds

To find the minimum speed, we need the time in seconds. There are 86400 seconds in a day, 365 days in a year. So, we can convert the maximum time allowed in years to seconds: Maximum time allowed in seconds = Maximum time allowed in years × 365 days/year × 86400 seconds/day
05

Calculate the minimum speed

Now we have the round-trip distance in km and the maximum time allowed in seconds, so we can calculate the minimum speed by dividing the distance by the time: Minimum speed = Round-trip distance in km / Maximum time allowed in seconds

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Light-Year Conversion
The concept of a light-year is foundational when discussing interstellar travel. A light-year is the distance that light travels in a vacuum in one year, which equates to approximately 9.461 × 10^12 kilometers. To put that in perspective, it's about 63,241 times the distance between the Earth and the Sun.

When working with interstellar distances, converting light-years to a more familiar unit like kilometers helps us to understand the staggering scales involved in space travel. In our problem, the star is 2000 light-years away, meaning the round-trip covers 4000 light-years. By converting this distance into kilometers, we can then proceed to calculate meaningful values for the journey, like the speed of a spaceship.

So, to convert a light-year to kilometers, we use the formula: Distance in km = Distance in light-years × 9.461 × 10^12 km/light-year. Through this equation, we can bridge the gap between astronomical measurements and more conventional units of distance that relate to our everyday experiences.
Time Dilation in Physics
When delving into the realm of interstellar travel, one cannot overlook the fascinating effect of time dilation as predicted by Einstein's theory of relativity. Time dilation is a consequence of the relative nature of time, which is affected by speed. As an object moves closer to the speed of light, time slows down for it relative to an observer at rest.

This becomes significant when discussing space travel at relativistic speeds, meaning speeds that are a significant fraction of the speed of light. For the brave travelers journeying to a distant star, time aboard the spacecraft would not pass at the same rate as it does for those staying on Earth. The faster the spacecraft travels, the more pronounced this time dilation effect becomes.

Understanding time dilation is crucial for planning such expeditions because the objective is to minimize the time experienced by the crew, ensuring they age much less during the journey than they would if they remained on Earth. For a spacecraft to achieve this, it must travel at a significant fraction of the speed of light, leading to relativistic effects that become a central factor in calculating the required travel velocity.
Relativistic Speed Calculation
The term 'relativistic speed' refers to velocities that approach the speed of light, resulting in the need to consider Einstein's Special Theory of Relativity in our calculations. As we discuss interstellar travel, calculating the minimum speed for a spacecraft requires not only physics but an understanding of these relativistic effects.

In our textbook problem, we are aiming to solve for the minimum speed the ship must travel. We already established the round-trip distance in kilometers and the maximum time allowed in seconds. The final step is to use the formula: Minimum speed = Distance / Time, bearing in mind that the speed obtained must be practical within the framework of relativity.

This implies considering the maximum time dilated lifespan of the astronauts, a product of the ship's velocity, thereby ensuring that their round trip does not exceed 10% of their lifetime. Relativistic speed calculations help ensure the feasibility of interstellar trips, a concept that pushes the boundaries of current technology and inspires future advancements in space travel.

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Most popular questions from this chapter

Consider motion in one spatial dimension. For any velocity \(v,\) define parameter \(\theta\) via the relation \(v=c \tanh \theta\) where \(c\) is the vacuum speed of light. This quantity is variously called the velocity parameter or the rapidity corresponding to velocity \(v\). a) Prove that for two velocities, which add according to the Lorentzian rule, the corresponding velocity parameters simply add algebraically, that is, like Galilean velocities. b) Consider two reference frames in motion at speed \(v\) in the \(x\) -direction relative to one another, with axes parallel and origins coinciding when clocks at the origin in both frames read zero. Write the Lorentz transformation between the two coordinate systems entirely in terms of the velocity parameter corresponding to \(v\), and the coordinates.

Show that \(E^{2}-p^{2} c^{2}=E^{2}-p^{2} c^{2},\) that is, that \(E^{2}-p^{2} c^{2}\) is a Lorentz invariant. Hint: Look at derivation showing that the space-time interval is a Lorentz invariant.

Consider a positively charged particle moving at constant speed parallel to a current-carrying wire, in the direction of the current. As you know (after studying Chapters 27 and 28), the particle is attracted to the wire by the magnetic force due to the current. Now suppose another observer moves along with the particle, so according to him the particle is at rest. Of course, a particle at rest feels no magnetic force. Does that observer see the particle attracted to the wire or not? How can that be? (Either answer seems to lead to a contradiction: If the particle is attracted, it must be by an electric force because there is no magnetic force, but there is no electric field from a neutral wire; if the particle is not attracted, you see that the particle is, in fact, moving toward the wire.)

You are driving down a straight highway at a speed of \(v=50.0 \mathrm{~m} / \mathrm{s}\) relative to the ground. An oncoming car travels with the same speed in the opposite direction. With what relative speed do you observe the oncoming car?

You shouldn't invoke time dilation due to your relative motion with respect to the rest of the world as an excuse for being late to class. While it is true that relative to those at rest in the classroom, your time runs more slowly, the difference is likely to be negligible. Suppose over the weekend you drove from your college in the Midwest to New York City and back, a round trip of \(2200 .\) miles, driving for 20.0 hours each direction. By what amount, at most, would your watch differ from your professor's watch?

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