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Coherent monochromatic light passes through parallel slits and then onto a screen that is at a distance \(L=2.40 \mathrm{~m}\) from the slits. The narrow slits are a distance \(d=2.00 \cdot 10^{-5} \mathrm{~m}\) apart. If the minimum spacing between bright spots is \(y=6.00 \mathrm{~cm},\) find the wavelength of the light.

Short Answer

Expert verified
Answer: The wavelength of the light is 10 nm.

Step by step solution

01

Finding the angle θ using the minimum spacing between bright spots, y

We'll use the small angle approximation formula: $$ \theta \approx tan(\theta) = \frac{y}{L} $$ where \(L\) is the distance from the slits to the screen, and \(y\) is the minimum spacing between bright spots. Plugging the given values: $$ \theta = \frac{6.00 \times 10^{-2} \mathrm{~m}}{2.40 \mathrm{~m}} $$ Calculate the value of \(\theta\): $$ \theta = 0.025 $$
02

Finding the order m for the first minimum using the angle θ

For the first minimum (dark spot) in the interference pattern, the path difference between two rays is half a wavelength. Therefore, the corresponding angle will be: $$ \sin(\theta') = \frac{\lambda}{2d} $$ Using the small angle approximation and knowing that \(\theta' = \theta\), $$ \theta' \approx \frac{\lambda}{2d} $$ We can now find the order of the bright spot \(m\) by multiplying both sides of the equation by \(2\): $$ m = 2\theta' = \frac{\lambda}{d} $$ By using the value of \(\theta\) calculated in Step 1, $$ m = 2 \times 0.025 = 0.05 $$
03

Finding the wavelength λ using the constructive interference formula

Now, we can use the constructive interference formula to find the wavelength of the light: $$ \sin(\theta) = \frac{m\lambda}{d} $$ Plugging the calculated values for \(m\), \(d\), and \(\theta\): $$ 0.025 = \frac{0.05\lambda}{2.00 \times 10^{-5} \mathrm{~m}} $$ Solve for \(\lambda\): $$ \lambda = \frac{0.025 \times 2.00 \times 10^{-5} \mathrm{~m}}{0.05} $$ Calculate the value of \(\lambda\): $$ \lambda = 1.00 \times 10^{-5} \mathrm{~m} $$ So, the wavelength of the light is \(1.00 \times 10^{-5} \mathrm{~m}\) or \(10\,\mathrm{nm}\).

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Most popular questions from this chapter

A double slit is opposite the center of a 1.8 -m wide screen \(2.0 \mathrm{~m}\) from the slits. The slit separation is \(24 \mu \mathrm{m}\) and the width of each slit is \(7.2 \mu \mathrm{m}\). How many fringes are visible on the screen if the slit is illuminated by \(600 .-\mathrm{nm}\) light?

The Michelson interferometer is used in a class of commercially available optical instruments called wavelength meters. In a wavelength meter, the interferometer is illuminated simultaneously with the parallel beam of a reference laser of known wavelength and that of an unknown laser. The movable mirror of the interferometer is then displaced by a distance \(\Delta d,\) and the number of fringes produced by each laser and passing by a reference point (a photo detector) is counted. In a given wavelength meter, a red He-Ne laser \(\left(\lambda_{\mathrm{Red}}=632.8 \mathrm{nm}\right)\) is used as a reference laser. When the movable mirror of the interferometer is displaced by a distance \(\Delta d\), a number \(\Delta N_{\text {Red }}=6.000 \cdot 10^{4}\) red fringes and \(\Delta N_{\text {unknown }}=7.780 \cdot 10^{4}\) fringes pass by the reference photodiode. a) Calculate the wavelength of the unknown laser. b) Calculate the displacement, \(\Delta d\), of the movable mirror.

A Michelson interferometer is illuminated with a 600.-nm light source. How many fringes are observed if one of the mirrors of the interferometer is moved a distance of 200. \(\mu \mathrm{m} ?\)

Which close binary pair of stars will be more easily resolvable with a telescope - two red stars, or two blue ones? Assume the binary star systems are the same distance from Earth and are separated by the same angle.

What would happen to a double-slit interference pattern if a) the wavelength is increased? b) the separation distance between the slits is increased? c) the apparatus is placed in water?

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