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Calculate and compare the angular resolutions of the Hubble Space Telescope (aperture diameter \(2.40 \mathrm{~m}\), wavelength \(450 . \mathrm{nm}\); illustrated in the text), the Keck Telescope (aperture diameter \(10.0 \mathrm{~m}\), wavelength \(450 . \mathrm{nm}\) ), and the Arecibo radio telescope (aperture diameter \(305 \mathrm{~m}\), wavelength \(0.210 \mathrm{~m}\) ). Assume that the resolution of each instrument is diffraction limited.

Short Answer

Expert verified
Answer: The order of image quality from highest to lowest is: Keck Telescope, Hubble Space Telescope, and Arecibo Radio Telescope.

Step by step solution

01

Hubble Space Telescope Resolution

To calculate the angular resolution of the Hubble Space Telescope, we will use the given values for the aperture diameter (D) as \(2.40 \mathrm{m}\) and the wavelength (λ) as \(450 \mathrm{nm}\). Plug these values into the formula and convert the wavelength to meters for consistency: $$ \theta_{Hubble} = 1.22\frac{450 \times 10^{-9} m}{2.4 m} $$
02

Keck Telescope Resolution

To calculate the angular resolution of the Keck Telescope, we will use the given values for the aperture diameter (D) as \(10.0 \mathrm{m}\) and the wavelength (λ) as \(450 \mathrm{nm}\). Plug these values into the formula and convert the wavelength to meters for consistency: $$ \theta_{Keck} = 1.22\frac{450 \times 10^{-9} m}{10.0 m} $$
03

Arecibo Radio Telescope Resolution

To calculate the angular resolution of the Arecibo Radio Telescope, we will use the given values for the aperture diameter (D) as \(305 \mathrm{m}\) and the wavelength (λ) as \(0.210 \mathrm{m}\). Plug these values into the formula: $$ \theta_{Arecibo} = 1.22\frac{0.210 m}{305 m} $$
04

Calculate The Resolutions

Now, calculate the angular resolutions for each telescope: $$ \theta_{Hubble} = 2.275 \times 10^{-7} radians \\ \theta_{Keck} = 5.46 \times 10^{-8} radians \\ \theta_{Arecibo} = 8.524 \times 10^{-4} radians $$
05

Compare The Resolutions

Now that we have the angular resolutions for each telescope, we can compare them. Lower angular resolution means better image quality. From the calculated values, we can see that the order of image quality (from highest to lowest) is: Keck Telescope, Hubble Space Telescope, and Arecibo Radio Telescope.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diffraction Limit
In the fascinating world of telescopes, the concept of the **diffraction limit** is crucial. It defines the best possible resolution an optical instrument can achieve due to the wave nature of light. When light passes through an aperture (like the opening of a telescope), it spreads out. This spreading, known as diffraction, limits the detail visible.

The diffraction limit is defined mathematically by the formula: \[ \theta = 1.22 \frac{\lambda}{D} \] where:
  • \( \theta \) represents the angular resolution in radians, which indicates the smallest angle over which details can be distinguished.
  • \( \lambda \) is the wavelength of light.
  • \( D \) is the aperture diameter of the telescope or optical device.

The factor 1.22 comes from calculations involving a circular aperture’s point spread function. Diffraction limits real-world performance, meaning even with larger apertures, the observed resolution cannot surpass this physical barrier. Understanding this limitation helps astronomers and engineers optimize telescope designs for specific wavelengths to achieve the closest to the diffraction limit possible.
Aperture Diameter
The **aperture diameter** of a telescope is the diameter of its main lens or mirror. It's a critical parameter as it determines the amount of light the telescope can gather and its resolution potential.

A larger aperture allows for a greater capacity to collect light. This results in improved clarity and detail of the observed objects. In astronomical terms, a large aperture means more brightness and better angular resolution.

Here's why aperture diameter is so vital:
  • **Light Gathering:** A bigger aperture collects more light, making faint celestial objects visible.
  • **Resolution Power:** As per the formula \( \theta = 1.22 \frac{\lambda}{D} \), a larger aperture \( D \) reduces the angle \( \theta \), indicating better resolution.

To illustrate, consider the Arecibo Radio Telescope, which has a massive aperture diameter of 305 meters, providing fantastic radio observation capabilities, albeit at longer wavelengths where its resolution is naturally lower.
Wavelength
Wavelength is a fundamental aspect of light and an essential concept in understanding telescope resolutions. **Wavelength** refers to the distance between successive peaks of a wave and is usually measured in nanometers (nm) for visible light or meters for radio waves.

In terms of telescopes, the light's wavelength directly affects resolution limits due to diffraction. Shorter wavelengths, like blue light (450 nm), generally provide better resolution, while longer wavelengths, found in radio waves, result in poorer resolution for the same aperture size.

Here’s how wavelength influences telescope performance:
  • **Resolution Dependence:** A shorter wavelength offers higher resolution for a given aperture diameter. This is why the Hubble Space Telescope can capture sharp images using visible light.
  • **Choice of Instrument:** Different telescopes are designed to operate optimally at specific wavelengths— optical telescopes focus on shorter wavelengths, while radio telescopes suit longer ones.

Understanding the influence of wavelength allows astronomers to select the right telescopes and technologies to study celestial phenomena, ensuring the clearest vision of the universe's mysteries.

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Most popular questions from this chapter

White light shines on a sheet of mica that has a uniform thickness of \(1.30 \mu \mathrm{m} .\) When the reflected light is viewed using a spectrometer, it is noted that light with wavelengths of \(433.3 \mathrm{nm}, 487.5 \mathrm{nm}, 557.1 \mathrm{nm}, 650.0 \mathrm{nm}\), and \(780.0 \mathrm{nm}\) is not present in the reflected light. What is the index of refraction of the mica?

A laser beam with wavelength \(633 \mathrm{nm}\) is split into two beams by a beam splitter. One beam goes to Mirror \(1,\) a distance \(L\) from the beam splitter, and returns to the beam splitter, while the other beam goes to Mirror \(2,\) a distance \(L+\Delta x\) from the beam splitter, and returns to the same beam splitter. The beams then recombine and go to a detector together. If \(L=1.00000 \mathrm{~m}\) and \(\Delta x=1.00 \mathrm{~mm},\) which best describes the kind of interference at the detector? (Hint: To doublecheck your answer, you may need to use a formula that was originally intended for combining two beams in a different geometry, but which still is applicable here.) a) purely constructive b) purely destructive c) mostly constructive d) mostly destructive e) neither constructive nor destructive

The irradiance pattern observed in a two-slit interference-diffraction experiment is presented in the figure. The red line represents the actual intensity measured as a function of angle, while the green line represents the envelope of the interference patterns. a) Determine the slit width \(a\) in terms of the wavelength \(\lambda\) of the light used in the experiment. b) Determine the center-to-center slit separation \(d\) in terms of the wavelength \(\lambda\). c) Using the information in the graph, determine the ratio of slit width \(a\) to the center-to-center separation between the slits, \(d\). d) Can you calculate the wavelength of light, actual slit separation, and slit width?

Why are radio telescopes so much larger than optical telescopes? Would an \(X\) -ray telescope also have to be larger than an optical telescope?

A diffraction grating with exactly 1000 lines per centimeter is illuminated by a He-Ne laser of wavelength \(633 \mathrm{nm}\). a) What is the highest order of diffraction that could be observed with this grating? b) What would be the highest order if there were exactly 10,000 lines per centimeter?

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