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Practically everyone who has studied the electromagnetic spectrum has wondered how the world would appear if we could see over a range of frequencies of the ten octaves over which we can hear rather than the less than one octave over which we can see. (An octave refers to a factor of 2 in frequency.) But this is fundamentally impossible. Why?

Short Answer

Expert verified
Answer: It is fundamentally impossible for humans to see over a range of frequencies as wide as the ten octaves in which we can hear because our eyes have evolved to only detect a limited range of electromagnetic radiation (visible light), which is much narrower than the range of audible sound frequencies. Furthermore, the nature of sound waves and electromagnetic waves are fundamentally different, making direct comparisons between their frequency ranges not valid.

Step by step solution

01

Understanding the electromagnetic spectrum and octave ranges

Sound and light are waves that differ in their properties. The range of frequencies of sound waves to which humans can respond (20 Hz to 20,000 Hz) spans ten octaves whereas the visible part of the electromagnetic spectrum (the part we can see) spans a much smaller range of around 400 THz to 800 THz, which is less than one octave.
02

Wavelengths in the Electromagnetic Spectrum

The electromagnetic spectrum is a range of all possible frequencies of electromagnetic radiation, including radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. Each of these waves has its specific wavelength range and properties. Visible light, which is the part of the electromagnetic spectrum that we can see, has a wavelength range of ~400 nm to ~700 nm.
03

Discussing the limitations of the human eye

The human eye consists of various types of cells that detect light of different wavelengths and process the signals to perceive color. The retina contains two types of photoreceptor cells: rods and cones. Cones allow us to see color and are sensitive to a range of wavelengths covering a small part of the electromagnetic spectrum - the visible light range. Rods, on the other hand, are responsible for our peripheral and night vision but are not as effective in detecting colors. Since the human eye has evolved to detect only a limited range of electromagnetic radiation frequencies (visible light), it is biologically impossible for our eyes to perceive radiation beyond the visible light range.
04

Difference in properties of light and sound waves

Sound waves are pressure waves propagating through a medium, such as air, water, or solids, while electromagnetic waves, including visible light, are characterized by electric and magnetic fields that do not require any medium to propagate. Because of the fundamental difference in their nature, it is not valid to make direct comparisons between the ranges of frequencies of sound waves and electromagnetic waves.
05

Conclusion

It is fundamentally impossible for humans to see over a range of frequencies as wide as the ten octaves in which we can hear because our eyes have evolved to only detect a limited range of electromagnetic radiation (visible light), which is much narrower than the range of audible sound frequencies. Furthermore, the nature of sound waves and electromagnetic waves are fundamentally different, making direct comparisons between their frequency ranges not valid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Octave in Frequency
An 'octave' in the context of frequency refers to a doubling of frequency. For example, if you start at a fundamental frequency, like a musical note at 440 Hz (the standard pitch for the note 'A' above middle C), one octave higher would be 880 Hz, and one octave lower would be 220 Hz. This concept is essential to not just music, but to understanding the electromagnetic spectrum and how we perceive different frequencies.

Electromagnetic waves span a vast spectrum of frequencies, and this range is divided into various bands, each with unique properties. While our ears can hear sounds ranging from approximately 20 Hz to 20,000 Hz, a span of ten octaves, our eyes are only equipped to see light within a fraction of an octave, roughly between 400 terahertz (THz) and 800 THz. This difference illustrates the broader capability of our hearing range compared to our visual spectrum. Sound waves require a medium to travel through, while light waves, being part of the electromagnetic spectrum, do not.
Wavelengths of Electromagnetic Radiation
The electromagnetic spectrum encompasses all wavelengths of electromagnetic radiation, which include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. Each type of radiation within the spectrum has a different wavelength. Wavelength is inversely proportional to frequency: the higher the frequency, the shorter the wavelength, and vice versa.

Visible light, which forms a tiny part of the electromagnetic spectrum, ranges from about 380 nanometers (nm) for violet light to about 740 nm for red light. This narrow band is what our eyes are equipped to detect. This visible spectrum falls right in the middle of the entire range of electromagnetic wavelengths, with longer wavelengths like those of radio waves on one end and shorter wavelengths like X-rays on the other.
Limitations of the Human Eye
The human eye is a remarkable organ, but it has its limitations. While it is finely tuned to respond to visible light, it cannot detect waves outside this narrow band known as the visible spectrum. The retina in our eyes houses two types of photoreceptor cells: rods and cones. Cones are involved in color vision and are sensitive to different wavelengths, enabling us to see a spectrum of colors, though limited to a small portion of the electromagnetic spectrum. Rods are more abundant and are sensitive to light intensity, contributing to our night vision but do not provide color differentiation.

Because our eyes have evolved for survival, they are adapted specifically to the range of wavelengths that the Sun emits most strongly. Other wavelengths, like ultraviolet (UV) or infrared (IR), are invisible to us without the aid of special instruments. This biological specialization is why we cannot naturally perceive frequencies beyond the visible spectrum; our eyes simply lack the necessary receptor mechanisms.
Difference Between Light and Sound Waves
Light waves and sound waves differ fundamentally in nature. Sound is a mechanical wave, meaning it requires a medium such as air, water, or solid materials, to travel through; it is essentially the movement of molecules in a pattern of highs and lows in pressure that our ears interpret as sound. Light waves, or electromagnetic waves, are different; they consist of oscillating electric and magnetic fields that can travel through a vacuum, like space, without a medium.

These inherent differences explain why the two types of waves have different ranges of perception; they are not directly comparable. The human ear is designed to detect pressure differences in a medium, while the eye is designed to respond to the energy level of electromagnetic waves within a certain frequency range. Therein lies the distinct perceptual experiences provided by our senses of hearing and sight, each with its limitations and capabilities.

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Most popular questions from this chapter

What is the radiation pressure due to Betelgeuse (which has a luminosity, or power output, 10,000 times that of the Sun) at a distance equal to that of Uranus's orbit from it?

A voltage, \(V\), is applied across a cylindrical conductor of radius \(r\), length \(L\), and resistance \(R\). As a result, a current, \(i\), is flowing through the conductor, which gives rise to a magnetic field, \(B\). The conductor is placed along the \(y\) -axis, and the current is flowing in the positive \(y\) -direction. Assume that the electric field is uniform throughout the conductor. a) Find the magnitude and the direction of the Poynting vector at the surface of the conductor. b) Show that \(\int \vec{S} \cdot d \vec{A}=i^{2} R\)

Which of the following exerts the largest amount of radiation pressure? a) a \(1-\mathrm{mW}\) laser pointer on a \(2-\mathrm{mm}\) -diameter spot \(1 \mathrm{~m}\) away b) a 200-W light bulb on a 4 -mm-diameter spot \(10 \mathrm{~m}\) away c) a 100 -W light bulb on a 2 -mm-diameter spot 4 m away d) a 200 - \(\mathrm{W}\) light bulb on a 2 -mm-diameter spot \(5 \mathrm{~m}\) away e) All of the above exert the same pressure.

Calculate the average value of the Poynting vector, \(S_{\text {ave }}\) for an electromagnetic wave having an electric field of amplitude \(100 . \mathrm{V} / \mathrm{m}\) a) What is the average energy density of this wave? b) How large is the amplitude of the magnetic field?

Scientists have proposed using the radiation pressure of sunlight for travel to other planets in the Solar System. If the intensity of the electromagnetic radiation produced by the Sun is about \(1.40 \mathrm{~kW} / \mathrm{m}^{2}\) near the Earth, what size would a sail have to be to accelerate a spaceship with a mass of 10.0 metric tons at \(1.00 \mathrm{~m} / \mathrm{s}^{2} ?\) a) Assume that the sail absorbs all the incident radiation. b) Assume that the sail perfectly reflects all the incident radiation.

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