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Having just learned that there is energy associated with magnetic fields, an inventor sets out to tap the energy associated with the Earth's magnetic field. What volume of space near Earth's surface contains \(1 \mathrm{~J}\) of energy, assuming the strength of the magnetic field to be \(5.0 \cdot 10^{-5} \mathrm{~T} ?\)

Short Answer

Expert verified
Answer: The volume near Earth's surface containing 1 Joule of energy due to the Earth's magnetic field is approximately \(1.01 \cdot 10^{11} \mathrm{m^3}\).

Step by step solution

01

Calculate the energy density of the magnetic field

We can calculate the energy density \(u\) of the Earth's magnetic field using the formula: $$u = \frac{1}{2\mu_0} B^2$$ where \(B = 5.0 \cdot 10^{-5} \mathrm{~T}\) and \(\mu_0 = 4\pi \cdot 10^{-7} \mathrm{~T\cdot m/A}\). Let's find \(u\): $$u = \frac{1}{2 (4\pi \cdot 10^{-7})}\left(5.0 \cdot 10^{-5}\right)^2 \mathrm{J/m^3}$$
02

Calculate the volume containing 1 Joule of energy

Now that we have the energy density \(u\), we can use the formula to find the volume \(V\) that contains 1 Joule of energy: $$V = \frac{1}{u} \cdot E$$ where \(E = 1 \mathrm{~J}\). Plugging in the values: $$V = \frac{1}{(9.8696 \cdot 10^{-12})} \cdot 1 \mathrm{~J}$$
03

Calculate the final volume

To find the final volume, we just need to simplify the expression: $$V = \frac{1}{9.8696 \cdot 10^{-12}} \mathrm{m^3}$$ and the result is: $$V \approx 1.01 \cdot 10^{11} \mathrm{m^3}$$ Thus, the volume near Earth's surface that contains 1 Joule of energy from the Earth's magnetic field is approximately \(1.01 \cdot 10^{11} \mathrm{m^3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Density of Magnetic Field
Understanding the concept of energy density is fundamental when studying magnetic fields. The energy density, represented by the symbol \(u\), is the amount of energy stored in a magnetic field per unit volume. Essentially, it tells us how much magnetic energy is packed into a given space.

The formula for calculating the energy density of a magnetic field is \[u = \frac{1}{2\mu_0} B^2\], where \(B\) represents the magnetic field strength and \(\mu_0\) is the permeability of free space, a constant with the value of \(4\pi \cdot 10^{-7} \mathrm{T\cdot m/A}\). In simpler terms, \(u\) increases with the square of the magnetic field strength, indicating that even small increases in field strength can lead to significant rises in energy density.

When examining the Earth's magnetic field, which is relatively weak, the energy density is accordingly low. This means that to harvest a sizable amount of energy, a large volume of space would be needed. This principle underlies the inventor's quest in the exercise to tap into the energy contained within the Earth's magnetic field.
Magnetic Field Strength
Magnetic field strength, denoted by \(B\), measures the magnitude of the magnetic field at a specific location. It is expressed in Teslas (T), a unit that quantifies the level of magnetism experienced by a charged particle moving through that field. The magnetic field strength around Earth varies, but near its surface, it is typically around \(5.0 \cdot 10^{-5} \mathrm{T}\).

Despite being invisible to the naked eye, the Earth's magnetic field has real effects, such as the protection it provides from solar winds and the guidance it offers to compass needles. In the context of the exercise, \(B\) represents a key variable in calculating the energy density and, subsequently, the volume of space that would need to be utilized to extract a certain amount of energy from the magnetic field.
Magnetic Field Energy Calculation
Calculating the energy contained in a magnetic field involves using the energy density and the volume of the space in question. Once the energy density \(u\) is known, we can find the volume \(V\) that contains a specific amount of energy \(E\) with the formula \[V = \frac{E}{u}\]. The steps provided demonstrate this calculation, leading to the determination that a colossal volume of approximately \(1.01 \cdot 10^{11} \mathrm{m^3}\) is required to harvest merely 1 Joule of energy from Earth's magnetic field.

This exercise illustrates a practical scenario where understanding the theoretical concepts of magnetic field energy is essential. Although Earth's magnetic field provides various ecosystem services, harnessing a significant amount of energy from it is impractical due to the vast spaces involved, reasserting the value of exploring diverse sources of renewable energy.

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Most popular questions from this chapter

A helicopter hovers above the north magnetic pole in a magnetic field of magnitude 0.426 G perpendicular to the ground. The helicopter rotors are \(10.0 \mathrm{~m}\) long, are made of aluminum, and rotate about the hub with a rotational speed of \(10.0 \cdot 10^{4} \mathrm{rpm} .\) What is the potential difference from the hub of the rotor to the end?

An 8 -turn coil has square loops measuring \(0.200 \mathrm{~m}\) along a side and a resistance of \(3.00 \Omega\). It is placed in a magnetic field that makes an angle of \(40.0^{\circ}\) with the plane of each loop. The magnitude of this field varies with time according to \(B=1.50 t^{3}\), where \(t\) is measured in seconds and \(B\) in teslas. What is the induced current in the coil at \(t=2.00 \mathrm{~s} ?\)

A circular coil of wire with 20 turns and a radius of \(40.0 \mathrm{~cm}\) is laying flat on a horizontal table as shown in the figure. There is a uniform magnetic field extending over the entire table with a magnitude of \(5.00 \mathrm{~T}\) and directed to the north and downward, making an angle of \(25.8^{\circ}\) with the horizontal. What is the magnitude of the magnetic flux through the coil?

A wedding ring (of diameter \(2.0 \mathrm{~cm}\) ) is tossed into the air and given a spin, resulting in an angular velocity of 17 rotations per second. The rotation axis is a diameter of the ring. Taking the magnitude of the Earth's magnetic field to be \(4.0 \cdot 10^{-5} \mathrm{~T}\), what is the maximum induced potential difference in the ring?

A student wearing a 15.0 -g gold band with radius \(0.750 \mathrm{~cm}\) (and with a resistance of \(61.9 \mu \Omega\) and a specific heat capacity of \(c=129 \mathrm{~J} / \mathrm{kg}^{\circ} \mathrm{C}\) ) on her finger moves her finger from a region having a magnetic field of \(0.0800 \mathrm{~T}\), pointing along her finger, to a region with zero magnetic field in \(40.0 \mathrm{~ms}\). As a result of this action, thermal energy is added to the band due to the induced current, which raises the temperature of the band. Calculate the temperature rise in the band, assuming all the energy produced is used in raising the temperature.

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