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A wire of radius R carries current i. The current density is given by J=J0(1r/R), where r is measured from the center of the wire and J0 is a constant. Use Ampere's Law to find the magnetic field inside the wire at a distance \(r

Short Answer

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Question: Find the magnetic field inside a wire with a radius R and a current density equation J = J0 (1 - r/R), where r is the distance from the central axis. Answer: The magnetic field inside the wire at a distance r<R from the central axis is given by the expression: B=μ0J0(12r13r3R)

Step by step solution

01

Ampere's Law

Ampere's Law relates the magnetic field and enclosed current as follows: Bdl=μ0Ienc For a wire of radius R, to find the magnetic field inside the wire at a distance r<R from the central axis, we apply Ampere's law to a circular path of radius r with B and dl being tangential to the circular path: Bdl=μ0Ienc; or B(2πr)=μ0Ienc where Ienc is the current enclosed by the circular path. Then, the magnetic field is given by: B=μ0Ienc2πr
02

Differential Current

In this step, we find the differential current di inside the wire using the current density J equation. The current flowing through a thin cylindrical shell of radius r and thickness dr can be given by multiplying the current density by the area of the shell: di=JdA where dA=2πrdr is the area of the cylindrical shell. The current density J is given by: J=J0(1rR) Then, di=J0(1rR)2πrdr
03

Total Enclosed Current

In order to find the total current enclosed within the circular path of radius r, we integrate the differential current from 0 to r: Ienc=0rdi=0rJ0(1rR)2πrdr Ienc=2πJ00r(rr2R)dr After integrating this expression, we have: Ienc=2πJ0(12r213r3R)
04

Magnetic Field Inside the Wire

Now, using the equation for the magnetic field from Step 1, and substituting the expression for the enclosed current found in Step 3, we can find the magnetic field inside the wire: B=μ02πr2πJ0(12r213r3R) Simplifying the equation, we get: B=μ0J0(12r13r3R) This is the expression for the magnetic field inside the wire at a distance r<R from the central axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Current Density
Imagine you have a hose with water flowing through it. The amount of water flowing through a specific section of the hose each second is like the electric current in a wire. However, if we want to understand the flow of current in more detail, we'll look at current density, which tells us how much current flows through a specific area. Just like you could measure how many gallons per minute flow through one square inch of the hose, current density measures the current flow through each square meter (or other unit area) of a conductor.

Mathematically, current density is denoted as \textbf{J} and in the case of our textbook problem, it's given by the formula:
J=J0(1rR),
where J0 is the maximum current density at the center of the wire (r=0), and r is the distance from the center, while R is the total radius. What's interesting here is that this formula shows us the current density decreases as you move away from the center towards the edge of the wire—an insightful detail about how current distribution isn't uniform in all conductors, which could have implications for the wire's electrical behavior. To give an example, if you have a long, cylindrical wire, the current density is like a gradient, denser (more current) in the middle and less dense (less current) towards the outside.
Magnetic Field Inside a Conductor
Now let's talk about the magic that happens around a conductor carrying current: the creation of a magnetic field. A basic principle of electromagnetism is that electric currents produce magnetic fields. If you've ever used a compass, you've seen this magnetic field in action—the Earth's core is essentially a giant conductor that generates a magnetic field!

In our exercise, we are examining the magnetic field inside a circular wire. This is where Ampere's Law comes into play, which states that the magnetic field in space can be calculated by measuring how much electric current is enclosed by a loop. With a formula like:
B=μ02πrIenc,
we can calculate the strength and direction of the magnetic field at any point inside the wire. μ0 is a constant called the permeability of free space, and it's the measure of the ability of a material (in this case, space or air) to support the formation of a magnetic field within itself. The enclosed current, Ienc, is the total current flowing through the area inside the curve we're considering—in our case, a circle of radius r inside the wire.

This formula shows that closer to the wire's center, you have a stronger magnetic field, and as you move out towards the edge of the wire, the magnetic field gets weaker. This explains why things like transformers and motors, which rely on magnetic fields, are designed very carefully to manage these field strengths.
Cylindrical Coordinates in Electromagnetism
In our daily life, we often describe the location of an object by saying how far left or right, forward or backward, and up or down it is—that's Cartesian coordinates. But for cases like wires, where things are circular, it's easier to use cylindrical coordinates. These are like the coordinates someone on a merry-go-round would use: how far from the center you are (the radius r), your angle around the center (the angle θ), and how high up you are (the height z).

When we deal with currents in wires or any phenomenon that is circular or cylindrical in nature, cylindrical coordinates become a really powerful tool in our mathematical toolkit. They let us describe physical laws in a way that lines up with the object's shape, which often simplifies our calculations. In electromagnetism, this is incredibly useful—wires are often circular and their magnetic fields curl around them. So, we use these coordinates to not only describe the location of points in relation to a circular shape but also to understand how fields like magnetic fields behave in such an environment.

For example, when we calculate the magnetic field inside our wire using Ampere's Law, we do so at a certain radius (r) from the wire's center, which directly relates to our cylindrical coordinate system. This harmonious marriage between the physical world and mathematical description helps students and engineers alike comprehend and apply these concepts to real-world problems.

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Most popular questions from this chapter

Two long, straight wires are parallel to each other. The wires carry currents of different magnitudes. If the amount of current flowing in each wire is doubled, the magnitude of the force between the wires will be a) twice the magnitude of the original force. b) four times the magnitude of the original force. c) the same as the magnitude of the original force. d) half of the magnitude of the original force.

A current element produces a magnetic field in the region surrounding it. At any point in space, the magnetic field produced by this current element points in a direction that is a) radial from the current element to the point in space. b) parallel to the current element. c) perpendicular to the current element and to the radial direction.

A horizontally oriented coil of wire of radius 5.00 cm and carrying a current, i, is being levitated by the south pole of a vertically oriented bar magnet suspended above the center of the coil. If the magnetic field on all parts of the coil makes an angle θ of 45.0 with the vertical, determine the magnitude and the direction of the current needed to keep the coil floating in midair. The magnitude of the magnetic field is B=0.0100 T, the number of turns in the coil is N=10.0, and the total coil mass is 10.0 g.

In a coaxial cable, the solid core carries a current i The sheath also carries a current i but in the opposite direction and has an inner radius a and an outer radius b. The current density is equally distributed over each conductor. Find an expression for the magnetic field at a distance \(a

In a magneto-optic experiment, a liquid sample in a 10 -mL spherical vial is placed in a highly uniform magnetic field, and a laser beam is directed through the sample. Which of the following should be used to create the uniform magnetic field required by the experiment? a) a 5-cm-diameter flat coil consisting of one turn of 4-gauge wire b) a 10 -cm-diameter, 20 turn, single layer, tightly wound coil made of 18 -gauge wire c) a 2 -cm-diameter, 10 -cm long, tightly wound solenoid made of 18 -gauge wire d) a set of two coaxial 10 -cm-diameter coils at a distance of 5 cm apart, each consisting of one turn of 4 -gauge wire

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