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A current element produces a magnetic field in the region surrounding it. At any point in space, the magnetic field produced by this current element points in a direction that is a) radial from the current element to the point in space. b) parallel to the current element. c) perpendicular to the current element and to the radial direction.

Short Answer

Expert verified
Answer: The correct direction of the magnetic field produced by a current element is perpendicular to the current element and to the radial direction.

Step by step solution

01

Recall the Biot-Savart Law

The Biot-Savart Law is given by the formula: $$ dB = \frac{\mu_0}{4\pi}\frac{I d\vec{l} \times \vec{r}}{r^3} $$ where \(dB\) is the infinitesimal magnetic field, \(\mu_0\) is the permeability of free space, \(I\) is the current passing through the current element, \(d\vec{l}\) is the current element vector, \(\vec{r}\) is the position vector from the current element to the point in space where we want to find the magnetic field, and \(r\) is the distance from the current element to that point.
02

Analyze the Biot-Savart Law formula

The direction of the magnetic field \(dB\) is determined by the cross product of the current element vector \(d\vec{l}\) and the position vector \(\vec{r}\): $$ dB \propto d\vec{l} \times \vec{r} $$
03

Check each given option

Now we can analyze each given option to see which one is consistent with the direction provided by the Biot-Savart Law. a) Radial from the current element to the point in space: This option suggests that the magnetic field is in the same direction as the position vector \(\vec{r}\). However, the cross product in the Biot-Savart Law implies that the magnetic field is perpendicular to both \(d\vec{l}\) and \(\vec{r}\). Therefore, this option is not correct. b) Parallel to the current element: This option suggests that the magnetic field is in the same direction as the current element vector \(d\vec{l}\). Again, the cross product in the Biot-Savart Law implies that the magnetic field is perpendicular to both \(d\vec{l}\) and \(\vec{r}\). Hence, this option is also incorrect. c) Perpendicular to the current element and to the radial direction: As we have analyzed, the cross product in the Biot-Savart Law indicates that the magnetic field is indeed perpendicular to both \(d\vec{l}\) and \(\vec{r}\). This option is consistent with the formula, so it is the correct answer.
04

Conclusion

The direction of the magnetic field produced by a current element is perpendicular to the current element and to the radial direction, which corresponds to option (c).

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Most popular questions from this chapter

You are standing at a spot where the magnetic field of the Earth is horizontal, points due northward, and has magnitude \(40.0 \mu \mathrm{T}\). Directly above your head, at a height of \(12.0 \mathrm{~m},\) a long, horizontal cable carries a steady \(\mathrm{DC}\) current of 500.0 A due northward. Calculate the angle \(\theta\) by which your magnetic compass needle is deflected from true magnetic north by the effect of the cable. Don't forget the sign of \(\theta-\) is the deflection eastward or westward?

The magnetic force cannot do work on a charged particle since the force is always perpendicular to the velocity. How then can magnets pick up nails? Consider two parallel current-carrying wires. The magnetic fields cause attractive forces between the wires, so it appears that the magnetic field due to one wire is doing work on the other wire. How is this explained? a) The magnetic force can do no work on isolated charges; this says nothing about the work it can do on charges confined in a conductor. b) Since only an electric field can do work on charges, it is actually the electric fields doing the work here. c) This apparent work is due to another type of force.

What is a good rule of thumb for designing a simple magnetic coil? Specifically, given a circular coil of radius \(\sim 1 \mathrm{~cm},\) what is the approximate magnitude of the magnetic field, in gauss per amp per turn? (Note: \(1 \mathrm{G}=0.0001 \mathrm{~T}\).) a) \(0.0001 \mathrm{G} /(\mathrm{A}\) -turn \()\) b) \(0.01 \mathrm{G} /(\) A-turn \()\) c) \(1 \mathrm{G} /(\mathrm{A}\) -turn \()\) d) \(100 \mathrm{G} /(\mathrm{A}\) -turn \()\)

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The current density in a cylindrical conductor of radius \(R\), varies as \(J(r)=J_{0} r / R\) (in the region from zero to \(R\) ). Express the magnitude of the magnetic field in the regions \(rR .\) Produce a sketch of the radial dependence, \(B(r)\)

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