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Can an ideal solenoid, one with no magnetic field outside the solenoid, exist? If not, does that render the derivation of the magnetic field inside the solenoid (Section 28.4) void?

Short Answer

Expert verified
Answer: No, an ideal solenoid with no magnetic field outside cannot exist, as a perfect, infinitely long solenoid with infinite turns per unit length is not possible in reality. However, this fact does not affect the derivation of the magnetic field inside the solenoid. The derivation provides good approximations for practical, relatively long solenoids with a large number of turns per unit length, which are accurate enough for practical applications and understanding their properties.

Step by step solution

01

Concept of an Ideal Solenoid

An ideal solenoid has infinite turns per unit length and is considered infinitely long. In reality, no solenoid can have infinite turns or infinite length, thus an ideal solenoid cannot exist as a practical device.
02

Amperian Loop Argument

If we consider the Amperian loop argument used to derive the magnetic field inside a solenoid, it relies on the fact that the magnetic field inside the solenoid is uniform and that the magnetic field outside the solenoid is negligible. Although it is known that a real solenoid will have some magnetic field outside, the Amperian loop can still be used as an approximation for cases when the solenoid is long and has a high number of turns per unit length.
03

Validity of Magnetic Field Derivation

Even though an ideal solenoid with zero magnetic fields outside cannot exist, the derivation of the magnetic field inside the solenoid is not void. The formulas for the magnetic field from this derivation apply well to solenoids that are relatively long and have a large number of turns per unit length. The results will be approximate but still accurate enough for practical applications because the external field will be small compared to the internal field for such a coil. In conclusion, though an ideal solenoid with no magnetic field outside cannot exist, it doesn't render the derivation of the magnetic field inside the solenoid void. The derivation provides good approximations for practical solenoids, which can be used effectively in understanding and analyzing their properties and applications.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field Inside a Solenoid
The magnetic field inside a solenoid, a type of coil used in various electronic devices, has fascinating characteristics. In an ideal solenoid, which we approximate as being infinitely long with an infinite number of turns, the magnetic field is considered uniform and strong. This is because the turns are so close together that they create a nearly constant magnetic field throughout the inside of the solenoid. By using Ampere's Law, a fundamental theorem in electromagnetism, one can derive the magnetic field inside the solenoid using the formula: \( B = \mu_0 n I \), where \( B \) is the magnetic field, \( \mu_0 \) is the magnetic constant, \( n \) is the number of turns per unit length, and \( I \) is the current.

In real-world applications, although solenoids are not infinite, this model is still useful. Practical solenoids with many closely spaced turns and significant length exhibit a magnetic field inside that is sufficiently uniform for many purposes. This uniformity allows for predictable behavior of the magnetic field and is crucial for the operation of devices like electromagnetic locks, inductors, and valves.
Amperian Loop
The concept of an Amperian loop is a powerful tool in electromagnetic theory, used to calculate the magnetic field in various situations. An Amperian loop is an imaginary closed loop used to apply Ampere's Law, which relates the integrated magnetic field around the loop to the current passing through any surface bounded by the loop. Specifically, for a solenoid, an Amperian loop is chosen such that parts of the loop run parallel to the solenoid's magnetic field inside the coil, and parts outside where the field is assumed to be negligible.

This simplification works well for solenoids that are long and have a high number of turns. The loop aids in visualizing the contributing factors to the magnetic field's existence and is key for deriving the equations that describe the magnetic field strength inside a solenoid. The Amperian loop supports the understanding that the contributions to the magnetic field from sections of the loop outside the solenoid will be close to zero, focusing the analysis on the inside, where the field is strongest.
Uniform Magnetic Field
A uniform magnetic field is one where the field strength and direction are consistent throughout the given space. Inside an ideal solenoid, the magnetic field is remarkably uniform, with a straight-line field pattern, paralleling the axis of the solenoid. This predictability and uniformity are what make solenoids particularly useful in various applications. The existence of a uniform field simplifies calculations and theoretical models for the behavior of charged particles and magnetic materials within the field.

However, achieving a perfect uniform magnetic field is not possible in practical situations due to fringe effects at the ends of real solenoids. The closer a solenoid is to the ideal (infinite length and turns), the more uniform the field will be. Engineers and designers of electronic components take this into consideration, maximizing the solenoid's length relative to its diameter to achieve near-uniform fields that provide consistent results.
Practical Applications of Solenoids
Solenoids find use in a multitude of devices due to their ability to convert electrical energy into mechanical energy. Some common applications include use in relays, which are electrically operated switches, and starter motors of cars, where a solenoid acts to engage the gears. Additionally, solenoids also feature in electric door locks, pneumatic and hydraulic control systems, and even in scientific equipment such as the mass spectrometers.

Medical devices, such as certain types of MRI machines, also rely on solenoids or solenoid-like components to generate the strong, uniform magnetic fields necessary for imaging. In manufacturing, solenoids are used to control actuators, valves, and clutches. The underlying principle in all these applications is the relationship between electric current, the solenoid's coil, and the magnetic field generated to perform work. Understanding how an ideal solenoid functions supports better design and utilization of real solenoids in these practical applications.

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Most popular questions from this chapter

A hairpin configuration is formed of two semiinfinite straight wires that are \(2.00 \mathrm{~cm}\) apart and joined by a semicircular piece of wire (whose radius must be \(1.00 \mathrm{~cm}\) and whose center is at the origin of \(x y z\) -coordinates). The top straight wire is along the line \(y=1.00 \mathrm{~cm},\) and the bottom straight wire is along the line \(y=-1.00 \mathrm{~cm} ;\) these two wires are in the left side \((x<0)\) of the \(x y\) -plane. The current in the hairpin is \(3.00 \mathrm{~A},\) and it is directed toward the right in the top wire, clockwise around the semicircle, and to the left in the bottom wire. Find the magnetic field at the origin of the coordinate system.

An electron has a spin magnetic moment of magnitude \(\mu=9.285 \cdot 10^{-24} \mathrm{~A} \mathrm{~m}^{2}\). Consequently, it has energy associated with its orientation in a magnetic field. If the difference between the energy of an electron that is "spin up" in a magnetic field of magnitude \(B\) and the energy of one that is "spin down" in the same magnetic field (where "up" and "down" refer to the direction of the magnetic field) is \(9.460 \cdot 10^{-25} \mathrm{~J}\), what is the field magnitude, \(B\) ?

Consider a model of the hydrogen atom in which an electron orbits a proton in the plane perpendicular to the proton's spin angular momentum (and magnetic dipole moment) at a distance equal to the Bohr radius, \(a_{0}=5.292 \cdot 10^{-11} \mathrm{~m} .\) (This is an oversimplified classical model.) The spin of the electron is allowed to be either parallel to the proton's spin or antiparallel to it; the orbit is the same in either case. But since the proton produces a magnetic field at the electron's location, and the electron has its own intrinsic magnetic dipole moment, the energy of the electron differs depending on its spin. The magnetic field produced by the proton's spin may be modeled as a dipole field, like the electric field due to an electric dipole discussed in Chapter 22 Calculate the energy difference between the two electronspin configurations. Consider only the interaction between the magnetic dipole moment associated with the electron's spin and the field produced by the proton's spin.

What is the magnitude of the magnetic field inside a long, straight tungsten wire of circular cross section with diameter \(2.4 \mathrm{~mm}\) and carrying a current of \(3.5 \mathrm{~A}\), at a distance of \(0.60 \mathrm{~mm}\) from its central axis?

A wire of radius \(R\) carries current \(i\). The current density is given by \(J=J_{0}(1-r / R),\) where \(r\) is measured from the center of the wire and \(J_{0}\) is a constant. Use Ampere's Law to find the magnetic field inside the wire at a distance \(r

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