Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

It would be mathematically possible, for a region with zero current density, to define a scalar magnetic potential analogous to the electrostatic potential: \(V_{B}(\vec{r})=-\int_{\vec{r}_{0}}^{\vec{r}} \vec{B} \cdot d \vec{s},\) or \(\vec{B}(\vec{r})=-\nabla V_{B}(\vec{r}) .\) However, this has not been done. Explain why not.

Short Answer

Expert verified
Explain. Answer: No, a scalar magnetic potential analogous to the electrostatic potential cannot be defined for regions with zero current density. This is because magnetic fields always have a zero divergence and have a swirling nature that cannot be captured by the gradient of a scalar potential. In some cases, the Laplacian of the scalar potential is non-zero, not fulfilling the requirement \(\nabla \cdot \vec{B} = 0\), and hence, it is not generally applicable to every magnetic field configuration.

Step by step solution

01

Understanding the electrostatic potential

Recall that the electrostatic potential V is defined for a region with a conservative electric field \(\vec{E}\). In this case, the electrostatic potential is represented by the scalar quantity: \(V(\vec{r})=-\int_{\vec{r}_{0}}^{\vec{r}} \vec{E} \cdot d\vec{s}\), where \(\vec{E}(\vec{r})=-\nabla V(\vec{r})\). This means that the electrostatic potential V can be defined for a given region, with the electric field being the gradient of V in that region.
02

Considering the analogous scalar potential for magnetic fields

Now, let's consider whether a similar scalar potential, \(V_B\), could be defined for the magnetic field, \(\vec{B}\), in a region with a zero current density. The proposed potential would be: \(V_{B}(\vec{r})=-\int_{\vec{r}_{0}}^{\vec{r}} \vec{B} \cdot d\vec{s},\) or \(\vec{B}(\vec{r})=-\nabla V_{B}(\vec{r})\).
03

Analyzing the fundamental differences between electric and magnetic fields

One fundamental difference between electric and magnetic fields is that electric fields can be produced by point charges, while magnetic fields are produced by moving charges (currents). Consequently, electric fields can have a divergence, while magnetic fields always have a zero divergence, which is expressed in Maxwell's equations as \(\nabla \cdot \vec{B} = 0\).
04

Explaining why scalar magnetic potential cannot be defined

Having a scalar potential \(V_B\) for \(\vec{B}\) would mean that \(\vec{B}=-\nabla V_{B}\). If true, this would lead to the following mathematical formulation: \(\nabla \cdot \vec{B} = -\nabla \cdot (\nabla V_{B}) = -\nabla^{2} V_{B} = 0\) However, it is not guaranteed that there is always a scalar field \(V_B\) that could satisfy this condition for every possible magnetic field configuration. This is because of the swirling nature of magnetic fields, which cannot be captured by the gradient of a scalar potential. In other words, there can be situations where the Laplacian of the scalar potential is non-zero, and thus, not fulfilling the requirement \(\nabla \cdot \vec{B} = 0\). That is why a scalar magnetic potential cannot be defined analogous to the electrostatic potential. In conclusion, while the scalar potential might work for some specific cases, it is not generally applicable to every magnetic field configuration, which is why it has not been defined for regions with zero current density.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrostatic Potential
Electrostatic potential is a concept that relates to electric fields. In this context, the electrostatic potential, denoted as \( V \), represents the amount of work needed to move a unit positive charge from a reference point to a specific point in the presence of an electric field. This potential is a scalar quantity, meaning it only has magnitude, and is expressed as:

\[V(\vec{r}) = -\int_{\vec{r}_0}^{\vec{r}} \vec{E} \cdot d\vec{s}\]
where \( \vec{E} \) is the electric field, and \( d\vec{s} \) is the differential path element. The negative sign indicates that the work is done against the electric field.

To put it simply, when you calculate the electrostatic potential, it's like measuring the inclination or slope of an electric field, but with numbers rather than angles. This relationship is expressed as:

\( \vec{E}(\vec{r}) = -abla V(\vec{r}) \).
This means that the electric field is essentially the negative gradient of the electrostatic potential.
Magnetic Fields
Magnetic fields are fundamental to understanding electromagnetism. Unlike electric fields, which emanate from stationary or moving charges, magnetic fields are exclusively produced by moving charges or currents.

Magnetic fields exhibit distinct characteristics:
  • They are vector fields, possessing both magnitude and direction.
  • They form closed loops, meaning they do not start or end anywhere, unlike electric field lines which start at positive charges and end at negative charges.
  • The concept of divergence is important here, and for magnetic fields, this is always zero: \( abla \cdot \vec{B} = 0 \).This implies that magnetic monopoles do not exist.
The swirling or looping nature of magnetic fields is what makes it impossible to define a simple scalar potential, similar to electric fields.
Maxwell's Equations
Maxwell's Equations form the backbone of classical electromagnetism, describing how electric and magnetic fields interact and propagate. Of particular interest are two equations when considering scalar potentials:
  • Gauss's law for magnetism: \( abla \cdot \vec{B} = 0 \), meaning magnetic fields have no divergence.
  • Faraday's law of induction indicates how electric fields change in time, leading to changing magnetic fields: \[ abla \times \vec{E} = -\frac{\partial \vec{B}}{\partial t} \]
These laws illustrate that:
  • Electric fields can be conservative in static cases, allowing us to define an electrostatic potential.
  • Magnetic fields, however, don't have a simple source and sink model, making it hard to define a scalar potential except in very special circumstantial cases.
The inability to define a scalar magnetic potential is largely due to the intertwined nature that these fields exhibit, as captured by Maxwell's equations. These mathematical formulations reveal the complex relationship between electric and magnetic fields.
Electric Fields
Electric fields are crucial components of electromagnetism and directly related to forces experienced by charges. They can be described as vector fields that exert force per unit charge. Here's what makes electric fields particularly unique:
  • They originate from electric charges and describe how the space around a charge is influenced.
  • Electric fields can be visualized as starting on positive charges and ending on negative charges, resulting in an open line structure.
  • Their behavior can be captured effectively through the concept of electrostatic potential \( V \), because they are conservative fields, meaning there is no energy loss when moving a charge around a closed loop.
The relationship between electric fields and electrostatic potential is:

\[\vec{E}(\vec{r}) = -abla V(\vec{r})\].
This tells us that electric fields are essentially the sharp elevation changes when viewing a potential landscape. The gradient of the potential function gives the electric field's direction and magnitude.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A simple galvanometer is made from a coil that consists of \(N\) loops of wire of area \(A .\) The coil is attached to a mass, \(M\), by a light rigid rod of length \(L\). With no current in the coil, the mass hangs straight down, and the coil lies in a horizontal plane. The coil is in a uniform magnetic field of magnitude \(B\) that is oriented horizontally. Calculate the angle from the vertical of the rigid rod as a function of the current, \(i\), in the coil.

A particle with mass \(m\), charge \(q\), and velocity \(v\) enters a magnetic field of magnitude \(B\) and with direction perpendicular to the initial velocity of the particle. What is the work done by the magnetic field on the particle? How does this affect the particle's motion?

An electron moves in a circular trajectory with radius \(r_{\mathrm{i}}\) in a constant magnetic field. What is the final radius of the trajectory when the magnetic field is doubled? a) \(\frac{r_{i}}{4}\) b) \(\frac{r_{i}}{2}\) c) \(r_{i}\) d) \(2 r_{i}\) e) \(4 r_{\mathrm{i}}\)

A charged particle moves under the influence of an electric field only. Is it possible for the particle to move with a constant speed? What if the electric field is replaced with a magnetic field?

A particle with a charge of \(+10.0 \mu \mathrm{C}\) is moving at \(300 \cdot \mathrm{m} / \mathrm{s}\) in the positive \(z\) -direction. a) Find the minimum magnetic field required to keep it moving in a straight line at constant speed if there is a uniform electric field of magnitude \(100 . \mathrm{V} / \mathrm{m}\) pointing in the positive \(y\) -direction. b) Find the minimum magnetic field required to keep the particle moving in a straight line at constant speed if there is a uniform electric field of magnitude \(100 . \mathrm{V} / \mathrm{m}\) pointing in the positive \(z\) -direction.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free