Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A Wheatstone bridge is constructed using a \(1.00-\mathrm{m}-\) long Nichrome wire (the purple line in the figure) with a conducting contact that can slide along the wire. A resistor, \(R_{1}=\) \(100 . \Omega\), is placed on one side of the bridge, and another resistor, \(R,\) of unknown resistance, is placed on the other side. The contact is moved along the Nichrome wire, and it is found that the ammeter reading is zero for \(L=25.0 \mathrm{~cm} .\) Knowing that the wire has a uniform cross section throughout its length, determine the unknown resistance.

Short Answer

Expert verified
Answer: The unknown resistance (R) in the Wheatstone Bridge is 300 Ω.

Step by step solution

01

Write down the balanced condition of Wheatstone Bridge

In a balanced Wheatstone Bridge, the ratio of resistances across opposite sides of the bridge is equal. So, if we denote the two lengths of the Nichrome wire where the ammeter reads zero as \(L_{1}\) and \(L_{2}\), then we have: \(\frac{R_{1}}{R} = \frac{L_{1}}{L_{2}}\).
02

Substitute the given values

We are given that \(R_{1} = 100\,\Omega\) and the total length of the wire is \(1.00\,\mathrm{m}\). We are also told that the ammeter reads zero when the contact is at \(L = 25.0\,\mathrm{cm}\). So, \(L_{1} = 0.25\,\mathrm{m}\). Then, \(L_{2} = 1.00\,\mathrm{m} - 0.25\,\mathrm{m} = 0.75\,\mathrm{m}\).
03

Solve for the unknown resistance R

Now we can solve the balanced Wheatstone Bridge equation for the unknown resistance \(R\). Using the values of \(R_{1}\), \(L_{1}\), and \(L_{2}\), we get: \(\frac{100\,\Omega}{R} = \frac{0.25\,\mathrm{m}}{0.75\,\mathrm{m}}\) Rearranging the equation to solve for \(R\): \(R = 100\,\Omega \cdot \frac{0.75\,\mathrm{m}}{0.25\,\mathrm{m}}\)
04

Calculate the value of unknown resistance

Now we calculate the unknown resistance \(R\): \(R = 100\,\Omega \cdot 3\) \(R = 300\,\Omega\) So, the unknown resistance \(R\) in the Wheatstone Bridge is \(300\,\Omega\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Circuits
Electric circuits form the foundation of modern technology, allowing us to channel electrical energy in controlled ways to perform work, from lighting our homes to powering complex computer systems. What is fundamental to any electrical circuit is the path through which current flows. This path is created by connecting electrical components in various configurations, commonly in series or parallel.

In the example of the Wheatstone Bridge, a classic electric circuit, resistors are arranged in a diamond shape to precisely measure resistance. The primary advantage of this circuit is its capability to detect very small differences in resistance, which is why it's often used in sensor applications. The principle of a balanced Wheatstone Bridge—as seen in the exercise—is particularly important: when the bridge is balanced, the current through the ammeter is zero, implying no potential difference between the midpoints of the two resistor pairs. This technique, when wielded skilfully, can provide accurate measurements within electrical systems.
Resistance Calculations
Resistance calculations are vital in designing and understanding electric circuits. The resistance of an electrical component determines how much it resists the flow of electric current, similar to how a narrow pipe might restrict the flow of water. Ohm's Law, which states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance, is often used for these calculations.

In the context of our Wheatstone Bridge problem, calculations become straightforward when the bridge is balanced. The pivotal equation \( \frac{R_{1}}{R} = \frac{L_{1}}{L_{2}} \) is an expression of this balance. By carefully substituting known lengths from our Nichrome wire example and the known resistance, we can isolate and determine the unknown resistance. The simplification of this relationship into a neat, solvable equation highlights the elegance and power of resistance calculations in electrical engineering.
Nichrome Wire Properties
Nichrome, an alloy of nickel and chromium, is known for its high electrical resistance, durability, and ability to withstand high temperatures, making it an ideal material for heating elements and resistors in appliances like toasters and hair dryers. Nichrome wires exhibit a relatively stable resistance over a wide temperature range, which is why they are used in precision applications such as in the Wheatstone Bridge from our exercise.

For accurate experimental results, the uniform cross-section of the Nichrome wire ensures that the resistance per unit length remains consistent along the wire. This property allows us to infer that when we have a balanced Wheatstone Bridge, the ratio of the lengths of the wire segments directly correlates to the ratio of their resistances. This kind of predictability is paramount when conducting resistance calculations and designing circuits that rely on precision and repeatable outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a series \(\mathrm{RC}\) circuit with \(R=10.0 \Omega\) \(C=10.0 \mu \mathrm{F}\) and \(V=10.0 \mathrm{~V}\) a) How much time, expressed as a multiple of the time constant, does it take for the capacitor to be charged to half of its maximum value? b) At this instant, what is the ratio of the energy stored in the capacitor to its maximum possible value? c) Now suppose the capacitor is fully charged. At time \(t=\) 0 , the original circuit is opened and the capacitor is allowed to discharge across another resistor, \(R^{\prime}=1.00 \Omega\), that is connected across the capacitor. What is the time constant for the discharging of the capacitor? d) How many seconds does it take for the capacitor to discharge half of its maximum stored charge, \(Q\) ?

Voltmeters are always connected in parallel with a circuit component, and ammeters are always connected in series. Explain why.

In the movie Back to the Future, time travel is made possible by a flux capacitor, which generates 1.21 GW of power. Assuming that a 1.00 - F capacitor is charged to its maximum capacity with a \(12.0-\mathrm{V}\) car battery and is discharged through a resistor, what resistance is necessary to produce a peak power output of 1.21 GW in the resistor? How long would it take for a \(12.0-\mathrm{V}\) car battery to charge the capacitor to \(90.0 \%\) of its maximum capacity through this resistor?

Explain why the time constant for an \(\mathrm{RC}\) circuit increases with \(R\) and with \(C\). (The answer "That's what the formula says" is not sufficient.)

A circuit consists of a source of emf, a resistor, and a capacitor, all connected in series. The capacitor is fully charged. How much current is flowing through it? a) \(i=V / R\) b) zero c) neither (a) nor (b)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free