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Calculate the capacitance of the Earth. Treat the Earth as an isolated spherical conductor of radius \(6371 \mathrm{~km}\).

Short Answer

Expert verified
Answer: The approximate capacitance of the Earth is 715.4 pF (picoFarads).

Step by step solution

01

Convert radius to meters

First, we need to convert the given radius from kilometers to meters: $$ 6371 \mathrm{~km} \times \frac{1000 \mathrm{~m}}{1 \mathrm{~km}} = 6,371,000 \mathrm{~m} $$ The radius of the Earth in meters is now \(6,371,000 \mathrm{~m}\).
02

Calculate capacitance

Now, we can plug the values into the capacitance formula: $$ C = 4\pi \epsilon_0 R $$ Where \(\epsilon_0 = 8.854\times 10^{-12} \mathrm{F/m}\) is the vacuum permittivity. Substituting the values, we get: $$ C = 4\pi (8.854\times 10^{-12} \mathrm{F/m}) (6,371,000 \mathrm{~m}) $$
03

Compute the result

Now, we can perform the calculations to find the capacitance: $$ C \approx 4 \times 3.14 \times (8.854\times 10^{-12} \mathrm{F/m}) \times (6,371,000 \mathrm{~m}) $$ $$ C \approx 715.4 \times 10^{-12} \mathrm{F} $$ Thus, the capacitance of the Earth can be approximated as \(715.4 \times 10^{-12} \mathrm{F}\) or \(715.4 \mathrm{pF}\) (picoFarads).

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A parallel plate capacitor of capacitance \(C\) is connected to a power supply that maintains a constant potential difference, \(V\). A close-fitting slab of dielectric, with dielectric constant \(\kappa\), is then inserted and fills the previously empty space between the plates. a) What was the energy stored on the capacitor before the insertion of the dielectric? b) What was the energy stored after the insertion of the dielectric? c) Was the dielectric pulled into the space between the plates, or did it have to be pushed in? Explain.

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The Earth is held together by its own gravity. But it is also a charge-bearing conductor. a) The Earth can be regarded as a conducting sphere of radius \(6371 \mathrm{~km},\) with electric field \(\vec{E}=(-150 . \mathrm{V} / \mathrm{m}) \hat{r}\) at its surface, where \(\hat{r}\) is a unit vector directed radially outward. Calculate the total electrostatic potential energy associated with the Earth's electric charge and field. b) The Earth has gravitational potential energy, akin to the electrostatic potential energy. Calculate this energy, treating the Earth as a uniform solid sphere. (Hint: \(d U=-(G m / r) d m\). c) Use the results of parts (a) and (b) to address this question: To what extent do electrostatic forces affect the structure of the Earth?

Must a capacitor's plates be made of conducting material? What would happen if two insulating plates were used instead of conducting plates?

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