Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Must a capacitor's plates be made of conducting material? What would happen if two insulating plates were used instead of conducting plates?

Short Answer

Expert verified
Answer: Yes, a capacitor's plates must be made of conducting material to allow the storage of electric charge and displacement when a voltage is applied across the plates. Using insulating plates would render the capacitor incapable of storing and releasing electrical energy due to the lack of charge movement and electric field formation between the plates.

Step by step solution

01

Understanding the function of a capacitor

A capacitor is an electrical component that stores and releases electrical energy by storing and displacing electric charge. It consists of two conducting plates separated by an insulating material known as a dielectric. When an electric potential difference (voltage) is applied across the plates, the plates will store equal and opposite charges. The stored energy in a capacitor can be utilized later in various applications, such as power supplies and signal filtering.
02

The role of conducting materials in capacitors

Conductive materials like metals allow the movement of electrons, which is essential for storing electric charge in a capacitor. When a voltage is applied to the capacitor, electrons move from one plate to the other, creating a net charge separation and building up an electric field across the insulator between the plates. This electric field represents the stored energy in the capacitor. The ability of a capacitor to store charge, also known as capacitance, depends on the surface area of the conducting plates, the distance between the plates, and the properties of the insulating material between them.
03

What happens if insulating plates are used?

If the plates of a capacitor were made of insulating materials instead of conducting materials, the capacitor would not function properly. Insulating materials do not allow free movement of electrons, so it would be nearly impossible for the capacitor to store or displace electric charge. Consequently, no electric field would form between the plates, and the capacitor would not store any energy. In conclusion, a capacitor's plates must be made of conducting material to allow the storage of electric charge and displacement when a voltage is applied across the plates. Using two insulating plates would render the capacitor incapable of storing and releasing electrical energy due to the lack of charge movement and electric field formation between the plates.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fifty parallel plate capacitors are connected in series. The distance between the plates is \(d\) for the first capacitor, \(2 d\) for the second capacitor, \(3 d\) for the third capacitor, and so on. The area of the plates is the same for all the capacitors. Express the equivalent capacitance of the whole set in terms of \(C_{1}\) (the capacitance of the first capacitor).

The capacitance of a spherical capacitor consisting of two concentric conducting spheres with radii \(r_{1}\) and \(r_{2}\) \(\left(r_{2}>r_{1}\right)\) is given by \(C=4 \pi \epsilon_{0} r_{1} r_{2} /\left(r_{2}-r_{1}\right) .\) Suppose that the space between the spheres, from \(r,\) up to a radius \(R\) \(\left(r_{1}

You have an electric device containing a \(10.0-\mu \mathrm{F}\) capacitor, but an application requires an \(18.0-\mu \mathrm{F}\) capacitor. What modification can you make to your device to increase its capacitance to \(18.0-\mu \mathrm{F} ?\)

A parallel plate capacitor is connected to a battery for charging. After some time, while the battery is still connected to the capacitor, the distance between the capacitor plates is doubled. Which of the following is (are) true? a) The electric field between the plates is halved. b) The potential difference of the battery is halved. c) The capacitance doubles. d) The potential difference across the plates does not change. e) The charge on the plates does not change.

A parallel plate capacitor is constructed from two plates of different areas. If this capacitor is initially uncharged and then connected to a battery, how will the amount of charge on the big plate compare to the amount of charge on the small plate?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free