Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Four charges are placed in a three-dimensional space. The charges have magnitudes \(+3 q,-q,+2 q,\) and \(-7 q .\) If a Gaussian surface encloses all the charges, what will be the electric flux through that surface?

Short Answer

Expert verified
Answer: The electric flux through the Gaussian surface is \(\frac{-3q}{\varepsilon_0}\).

Step by step solution

01

Determine the net charge enclosed by the Gaussian surface

To find the net charge enclosed by the Gaussian surface, we will sum all the charges within the surface: \((+3q) + (-q) + (+2q) + (-7q)\).
02

Calculate the net charge

Now we will calculate the total charge: \(+3q - q + 2q - 7q = -3q\).
03

Apply Gauss's Law

With the net charge enclosed by the Gaussian surface, we can find the electric flux using Gauss's Law: \(\Phi_E = \frac{Q_{enclosed}}{\varepsilon_0}\).
04

Calculate the electric flux

The net charge is \(-3q\), so the electric flux through the Gaussian surface is: \(\Phi_E = \frac{-3q}{\varepsilon_0}\). Thus, the electric flux through the Gaussian surface is \(\frac{-3q}{\varepsilon_0}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Flux
Electric flux is a measure of the amount of electric field passing through a given area. Imagine it like the number of electric field lines crossing a surface. It tells us how the electric field "flows" through a surface, like water flowing through a net. The more field lines crossing perpendicularly, the greater the flux.
Electric flux (\(\Phi_E\)) through a closed surface depends on the net charge enclosed within that surface and is calculated using Gauss's Law. Essentially:
  • The electric field contributes more to flux if it is stronger.
  • Flux is also greater when the field lines are perpendicular to the surface.
  • When field lines run parallel to the surface, they don't contribute to the flux.
Be mindful that electric flux considers both the strength and orientation of the field across a surface.
Gaussian Surface
A Gaussian surface is an imaginary closed surface used in Gauss's Law to simplify the calculation of electric fields. You can think of a Gaussian surface as a balloon you could inflate to completely envelop charges in three-dimensional space.
The purpose of the Gaussian surface is to utilize symmetry in problems, allowing for an easier calculation of electric flux. When applying Gauss's Law, the choice of a Gaussian surface should:
  • Completely enclose the charge(s) involved in the calculations.
  • Take advantage of any symmetry present, making the mathematics simpler.
  • Be chosen such that it is easier to calculate the electric field over it.
Gaussian surfaces align the theory of electric fields with practical calculations, shining a light on how field lines interact with enclosed charges.
Net Charge
Net charge is the total amount of electric charge contained within a specific area or volume. It is the sum of all positive and negative charges in a given space. Think of net charge as the balance between positive and negative charges.
To find the net charge within a Gaussian surface:
  • Add the magnitudes of all positive charges.
  • Add the magnitudes of all negative charges.
  • Subtract the total negative charge from the total positive charge.
In exercises like the original problem, correctly identifying and calculating net charge is crucial. It directly influences the electric flux through the surface.
Three-dimensional Space
Three-dimensional space provides a real-world context in which electric charges are arranged not just on a flat plane, but with depth and spatial separation. This means that charges can be enclosed from all directions.
Understanding this space allows students to visualize how electric fields and Gaussian surfaces operate in all dimensions, not just along a single axis. In practice:
  • Charges can be placed in various configurations, which affects calculation.
  • Spatial understanding helps when determining symmetry for Gaussian surfaces.
  • Three-dimensional visualization improves comprehension of flux pathways.
Recognizing the role of three-dimensional space bridge concepts from theoretical exercises to tangible physical scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An electric dipole consists of two equal and opposite charges situated a very small distance from each other. When the dipole is placed in a uniform electric field, which of the following statements is true? a) The dipole will not experience any net force from the electric field; since the charges are equal and have opposite signs, the individual effects will cancel out. b) There will be no net force and no net torque acting on the dipole. c) There will be a net force but no net torque acting on the dipole. d) There will be no net force, but there will (in general) be a net torque acting on dipole.

Which of the following statements is (are) true? a) There will be no change in the charge on the inner surface of a hollow conducting sphere if additional charge is placed on the outer surface. b) There will be some change in the charge on the inner surface of a hollow conducting sphere if additional charge is placed on the outer surface. c) There will be no change in the charge on the inner surface of a hollow conducting sphere if additional charge is placed at the center of the sphere. d) There will be some change in the charge on the inner surface of a hollow conducting sphere if additional charge is placed at the center of the sphere.

Suppose you have a large spherical balloon and you are able to measure the component \(E_{n}\) of the electric field normal to its surface. If you sum \(E_{n} d A\) over the whole surface area of the balloon and obtain a magnitude of \(10 \mathrm{~N} \mathrm{~m}^{2} / \mathrm{C}\) what is the electric charge enclosed by the balloon?

The electric flux through a spherical Gaussian surface of radius \(R\) centered on a charge \(Q\) is \(1200 \mathrm{~N} /\left(\mathrm{C} \mathrm{m}^{2}\right) .\) What is the electric flux through a cubic Gaussian surface of side \(R\) centered on the same charge \(Q ?\) a) less than \(1200 \mathrm{~N} /\left(\mathrm{C} \mathrm{m}^{2}\right)\) b) more than \(1200 \mathrm{~N} /\left(\mathrm{C} \mathrm{m}^{2}\right)\) c) equal to \(1200 \mathrm{~N} /\left(\mathrm{C} \mathrm{m}^{2}\right)\) d) cannot be determined from the information given

Saint Elmos fire is an eerie glow that appears at the tips of masts and yardarms of sailing ships in stormy weather and at the tips and edges of the wings of aircraft in flight. St. Elmo's fire is an electrical phenomenon. Explain it, concisely.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free