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Two charges, \(+e\) and \(-e,\) are a distance of \(0.68 \mathrm{nm}\) apart in an electric field, \(E,\) that has a magnitude of \(4.4 \mathrm{kN} / \mathrm{C}\) and is directed at an angle of \(45^{\circ}\) with the dipole axis. Calculate the dipole moment and thus the torque on the dipole in the electric field.

Short Answer

Expert verified
Question: Calculate the dipole moment and the torque on a dipole in an electric field where the charges are +e and -e, separated by a distance of 0.68 nm, and the electric field vector has a magnitude of 4.4 kN/C and is directed at an angle of 45 degrees with the dipole axis. Answer: The dipole moment is approximately \(1.088 \times 10^{-28} \ \mathrm{C} \cdot \mathrm{m}\), and the torque on the dipole in the electric field is approximately \(3.393 \times 10^{-25} \ \mathrm{N} \cdot \mathrm{m}\).

Step by step solution

01

Calculate the dipole moment

The formula for the dipole moment is: \[\vec{p} = q\vec{d}\] where \(\vec{p}\) is the dipole moment, \(q\) is the charge, and \(\vec{d}\) is the distance between the two charges. The charges are \(+e\) and \(-e\), so the magnitude of the charge is \(e = 1.6 \times 10^{-19} \mathrm{C}\). The distance between the charges is given as \(0.68 \ \mathrm{nm}\), which is equal to \(0.68 \times 10^{-9} \ \mathrm{m}\). Therefore, the dipole moment can be calculated as: \[\vec{p} = (1.6 \times 10^{-19} \mathrm{C})(0.68 \times 10^{-9} \mathrm{m}) = 1.088 \times 10^{-28} \ \mathrm{C} \cdot \mathrm{m}\]
02

Find the electric field vector

The electric field vector \(\vec{E}\) has a magnitude of \(4.4 \ \mathrm{kN}/\mathrm{C}\), which is equal to \(4.4 \times 10^{3} \ \mathrm{N}/\mathrm{C}\). The electric field is directed at an angle of \(45^{\circ}\) with the dipole axis. We can use the angle to find the electric field vector components. In the horizontal direction, \(E_{x} = E \cos(45^{\circ}) = (4.4 \times 10^{3} \ \mathrm{N}/\mathrm{C})\cos(45^{\circ})\). In the vertical direction, \(E_{y} = E \sin(45^{\circ}) = (4.4 \times 10^{3} \ \mathrm{N}/\mathrm{C})\sin(45^{\circ})\).
03

Calculate the torque on the dipole

The torque on the dipole in the electric field can be calculated using the following formula: \[\vec{\tau} = \vec{p} \times \vec{E}\] Taking the cross product, we get: \[\tau_{z} = pE \sin(\theta)\] The angle \(\theta\) between the electric field vector and the dipole moment vector is \(45^{\circ}\). Using the values of dipole moment (\(p = 1.088 \times 10^{-28} \ \mathrm{C} \cdot \mathrm{m}\)) and electric field magnitude (\(E = 4.4 \times 10^{3} \ \mathrm{N}/\mathrm{C}\)), we can find the torque: \[\tau_z = (1.088 \times 10^{-28} \ \mathrm{C} \cdot \mathrm{m})(4.4 \times 10^{3} \ \mathrm{N}/\mathrm{C}) \sin(45^{\circ}) = 3.393 \times 10^{-25} \ \mathrm{N} \cdot \mathrm{m}\] The torque on the dipole in the electric field is approximately \(3.393 \times 10^{-25} \ \mathrm{N} \cdot \mathrm{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Electric Charges
Electric charges are one of the fundamental properties of matter, existing in two types: positive and negative. Like charges repel each other, while opposite charges attract. The unit of charge is the coulomb (C), and the charge of a single electron (or proton) is approximately \[\begin{equation}-1.6 \times 10^{-19} \text{C (electron)}, \ 1.6 \times 10^{-19} \text{C (proton)}. \end{equation}\] The interactions between charges are described by Coulomb's law, which states the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. This concept is crucial when analyzing the behavior of electric dipoles in an external electric field, as seen in the exercise provided.
The Role of the Electric Field
An electric field is a region around electric charges in which other charges experience a force. The strength and direction of this field are essential as they dictate how a charge will react when placed within this field. The electric field strength is measured in newtons per coulomb (N/C). An important property of electric fields is that they are vector fields, meaning they have both magnitude and direction, which was vital in solving the given exercise. The effect of an electric field on a dipole depends on its orientation relative to the field, hence, when the field is angled with respect to the dipole axis, the field's components must be considered separately to understand the total effect on the dipole.
Torque on an Electric Dipole
A torque is a measure of the force that causes an object to rotate. When an electric dipole, which consists of two equal but opposite charges separated by some distance, is placed in an electric field, the field exerts a torque on the dipole. This torque depends on the dipole moment, which is a vector quantity defined as the product of the charge magnitude and the distance between the charges, oriented from the negative to the positive charge. Mathematically, the torque on a dipole is given by the cross product of the dipole moment (\[\begin{equation}\vec{p}\end{equation}\]) and the electric field (\[\begin{equation}\vec{E}\end{equation}\]). Therefore, the resulting torque tends to align the dipole with the electric field, which is a key concept in understanding the exercise and determining the magnitude and direction of the torque that the dipole experiences in the given scenario.

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Most popular questions from this chapter

A thin, flat washer is a disk with an outer diameter of \(10.0 \mathrm{~cm}\) and a hole in the center with a diameter of \(4.00 \mathrm{~cm} .\) The washer has a uniform charge distribution and a total charge of \(7.00 \mathrm{nC}\). What is the electric field on the axis of the washer at a distance of \(30.0 \mathrm{~cm}\) from the center of the washer?

A cube has an edge length of \(1.00 \mathrm{~m} .\) An electric field acting on the cube from outside has a constant magnitude of \(150 \mathrm{~N} / \mathrm{C}\) and its direction is also constant but unspecified (not necessarily along any edges of the cube). What is the total charge within the cube?

Three charges are on the \(y\) -axis. Two of the charges, each \(-q,\) are located \(y=\pm d,\) and the third charge, \(+2 q,\) is located at \(y=0 .\) Derive an expression for the electric field at a point \(P\) on the \(x\) -axis.

A proton enters the gap between a pair of metal plates (an electrostatic separator) that produces a uniform, vertical electric field between them. Ignore the effect of gravity on the proton. a) Assuming that the length of the plates is \(15.0 \mathrm{~cm}\), and that the proton will approach the plates at a speed of \(15.0 \mathrm{~km} / \mathrm{s}\) what electric field strength should the plates be designed to provide, if the proton must be deflected vertically by \(1.50 \cdot 10^{-3} \mathrm{rad} ?\) b) What speed does the proton have after exiting the electric field? c) Suppose the proton is one in a beam of protons that has been contaminated with positively charged kaons, particles whose mass is \(494 \mathrm{MeV} / \mathrm{c}^{2}\left(8.81 \cdot 10^{-28} \mathrm{~kg}\right)\), compared to the mass of the proton, which is \(938 \mathrm{MeV} / \mathrm{c}^{2}\left(1.67 \cdot 10^{-27} \mathrm{~kg}\right)\) The kaons have \(+1 e\) charge, just like the protons. If the electrostatic separator is designed to give the protons a deflection of \(1.20 \cdot 10^{-3} \mathrm{rad}\), what deflection will kaons with the same momentum as the protons experience?

A body of mass \(M\), carrying charge \(Q\), falls from rest from a height \(h\) (above the ground) near the surface of the Earth, where the gravitational acceleration is \(g\) and there is an electric field with a constant component \(E\) in the vertical direction. a) Find an expression for the speed, \(v,\) of the body when it reaches the ground, in terms of \(M, Q, h, g,\) and \(E\). b) The expression from part (a) is not meaningful for certain values of \(M, g, Q,\) and \(E\). Explain what happens in such cases.

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