Chapter 22: Problem 23
A point charge, \(q=4.00 \cdot 10^{-9} \mathrm{C},\) is placed on the \(x\) -axis at the origin. What is the electric field produced at \(x=25.0 \mathrm{~cm} ?\)
Short Answer
Expert verified
Answer: The electric field produced by the point charge at a distance of 25.0 cm is 361.9 N/C.
Step by step solution
01
Identify given variables
We are given the following information:
- Point charge, \(q = 4.00 \cdot 10^{-9} \mathrm{C}\)
- Distance from the point charge, \(x = 25.0 \mathrm{cm}\), which we need to convert to meters: \(x = 0.25 \mathrm{m}\)
Our goal is to find the electric field, \(E\), at this distance.
02
Use Coulomb's Law to find the electric field
Coulomb's Law for the electric field produced by a point charge is given by the formula:
\(E = \frac{1}{4\pi\epsilon_0} \frac{q}{r^2}\)
Where:
- \(E\) is the electric field
- \(\epsilon_0\) is the vacuum permittivity (electric constant), with a value of \(8.85 \cdot 10^{-12} \mathrm{C^2/N} \cdot \mathrm{m^2}\),
- \(q\) is the charge of the point charge
- \(r\) is the distance from the point charge to the point where we want to find the electric field.
In this exercise, we will use \(x\) instead of \(r\) for distance.
03
Substitute the given values and calculate the electric field
We will now plug in the given values to find the electric field at the desired \(x\):
\(E = \frac{1}{4\pi(8.85 \cdot 10^{-12}\,\mathrm{C^2/N} \cdot \mathrm{m^2})} \cdot \frac{4.00 \cdot 10^{-9}\,\mathrm{C}}{(0.25\, \mathrm{m})^2}\)
Calculate the electric field:
\(E = 361.9\,\mathrm{N/C}\)
04
Write the final answer
The electric field produced by the point charge at \(x = 25.0\,\mathrm{cm}\) is \(361.9\,\mathrm{N/C}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coulomb's Law
Coulomb's Law describes how electric forces interact between charged objects. This important law is named after Charles-Augustin de Coulomb, a French physicist, who formulated it in 1785. It explains the force between two point charges. The electric force
- is directly proportional to the product of the magnitudes of the charges
- is inversely proportional to the square of the distance between them
Point Charge
A point charge is an idealized model in electromagnetism, representing a charge located at a single point in space. This simplification serves to simplify complex real-world charges, allowing easier calculations of electric fields and forces.
- It can be a single electron or a proton that has a very small size compared to the distances in the problem.
- A point charge provides a pure charge source with no distribution area or volume.
- This idealization helps in applying fundamental equations such as Coulomb's Law without considering the geometric complexities of real objects.
Vacuum Permittivity
Vacuum permittivity, often denoted as \(\epsilon_0\), is a fundamental physical constant crucial in electromagnetism. Also called the electric constant, \(\epsilon_0\) characterizes the ability of a vacuum to permit electric field lines.
- Its value is approximately \(8.85 \times 10^{-12} \text{ C}^{2}/\text{N} \cdot \text{m}^2\).
- This constant appears frequently in equations governing electric phenomena, including Coulomb's Law.
- It provides a scale factor for measuring the electric effects in spaces devoid of matter, essentially setting the "baseline" around which electromagnetic laws are applied and measured in vacuum conditions.