Chapter 21: Problem 18
How is it possible for one electrically neutral atom to exert an electrostatic force on another electrically neutral atom?
Chapter 21: Problem 18
How is it possible for one electrically neutral atom to exert an electrostatic force on another electrically neutral atom?
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Get started for freeThe faraday is a unit of charge frequently encountered in electrochemical applications and named for the British physicist and chemist Michael Faraday. It consists of 1 mole of elementary charges. Calculate the number of coulombs in 1.000 faraday.
In solid sodium chloride (table salt), chloride ions have one more electron than they have protons, and sodium ions have one more proton than they have electrons. These ions are separated by about \(0.28 \mathrm{nm} .\) Calculate the electrostatic force between a sodium ion and a chloride ion.
As shown in the figure, charge 1 is \(3.94 \mu \mathrm{C}\) and is located at \(x_{1}=-4.7 \mathrm{~m},\) and charge 2 is \(6.14 \mu \mathrm{C}\) and is at \(x_{2}=\) \(12.2 \mathrm{~m} .\) What is the \(x\) -coordinate of the point at which the net force on a point charge of \(0.300 \mu \mathrm{C}\) is zero?
Two positive charges, each equal to \(Q\), are placed a distance \(2 d\) apart. A third charge, \(-0.2 Q\), is placed exactly halfway between the two positive charges and is displaced a distance \(x \ll d\) perpendicular to the line connecting the positive charges. What is the force on this charge? For \(x \ll d\), how can you approximate the motion of the negative charge?
In general, astronomical objects are not exactly electrically neutral. Suppose the Earth and the Moon each carry a charge of \(-1.00 \cdot 10^{6} \mathrm{C}\) (this is approximately correct; a more precise value is identified in Chapter 22 ). a) Compare the resulting electrostatic repulsion with the gravitational attraction between the Moon and the Earth. Look up any necessary data. b) What effects does this electrostatic force have on the size, shape, and stability of the Moon's orbit around the Earth?
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