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An ideal gas undergoes an isothermal expansion. What will happen to its entropy? a) It will increase. c) It's impossible to determine. b) It will decrease. d) It will remain unchanged.

Short Answer

Expert verified
Answer: a) It will increase.

Step by step solution

01

Understand the isothermal process in an ideal gas

An isothermal process is a thermodynamic process in which the temperature of the system remains constant. In the case of an ideal gas, when it undergoes an isothermal expansion, pressure (P) and volume (V) change in such a way that the product of pressure and volume (PV) remains constant.
02

Recall the mathematical expression for entropy change

The entropy change (∆S) of an ideal gas in an isothermal process can be expressed as: ∆S = nR * ln(V2/V1) where n is the number of moles of the gas, R is the universal gas constant, V1 and V2 are the initial and final volumes of the gas, and ln represents the natural logarithm.
03

Analyze the effect of isothermal expansion on entropy

Since the process is an expansion, the final volume (V2) will be greater than the initial volume (V1). In the entropy change equation, the ratio V2/V1 will be greater than 1. As the natural logarithm of a number greater than 1 is positive, the entropy change ∆S will be positive.
04

Choose the correct answer

As we found that the entropy change (∆S) is positive, it implies that the entropy of the ideal gas will increase during an isothermal expansion. So, the correct answer is: a) It will increase.

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Most popular questions from this chapter

The number of macrostates that can result from rolling a set of \(N\) six-sided dice is the number of different totals that can be obtained by adding the pips on the \(N\) faces that end up on top. The number of macrostates is a) \(6^{N}\) b) \(6 N\) c) \(6 N-1\). d) \(5 N+1\).

An ideal gas is enclosed in a cylinder with a movable piston at the top. The walls of the cylinder are insulated, so no heat can enter or exit. The gas initially occupies volume \(V_{1}\) and has pressure \(p_{1}\) and temperature \(T_{1}\). The piston is then moved very rapidly to a volume of \(V_{2}=3 V_{1}\). The process happens so rapidly that the enclosed gas does not do any work. Find \(p_{2}, T_{2},\) and the change in entropy of the gas.

A refrigerator with a coefficient of performance of 3.80 is used to \(\operatorname{cool} 2.00 \mathrm{~L}\) of mineral water from room temperature \(\left(25.0^{\circ} \mathrm{C}\right)\) to \(4.00^{\circ} \mathrm{C} .\) If the refrigerator uses \(480 . \mathrm{W}\) how long will it take the water to reach \(4.00^{\circ} \mathrm{C}\) ? Recall that the heat capacity of water is \(4.19 \mathrm{~kJ} /(\mathrm{kg} \mathrm{K}),\) and the density of water is \(1.00 \mathrm{~g} / \mathrm{cm}^{3}\). Assume the other contents of the refrig. erator are already at \(4.00^{\circ} \mathrm{C}\).

20.14 Imagine dividing a box into two equal parts, part \(A\) on the left and part \(B\) on the right. Four identical gas atoms, numbered 1 through 4 , are placed in the box. What are most probable and second most probable distributions (for example, 3 atoms in \(\mathrm{A}, 1\) atom in \(\mathrm{B}\) ) of gas atoms in the box? Calculate the entropy, \(S\), for these two distributions. Note that the configuration with 3 atoms in \(\mathrm{A}\) and 1 atom in \(\mathrm{B}\) and that with 1 atom in A and three atoms in B count as different configurations.

An Otto engine has a maximum efficiency of \(20.0 \%\) find the compression ratio. Assume that the gas is diatomic.

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