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Chapter 20: Problem 24

The burning of fuel transfers \(4.00 \cdot 10^{5} \mathrm{~W}\) of power into the engine of a \(2000 .-\mathrm{kg}\) vehicle. If the engine's efficiency is \(25.0 \%,\) determine the maximum speed the vehicle can achieve \(5.00 \mathrm{~s}\) after starting from rest.

Short Answer

Expert verified
Total Work = (4.00 * 10^5 W) * 0.25 * 5.00 s = 1.00 * 10^6 J

Step by step solution

01

Calculate total work done by the engine

We know that the power is the rate at which work is done. We can find the total work done, considering the engine efficiency, using the formula: Work = Power × Efficiency × Time Plug in the given values, and calculate the work done: \(\text{Work} = 4.00 * 10^{5} \text{W} * 0.25 * 5.00 \text{s}\) Calculate the total work done:

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Most popular questions from this chapter

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