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The position versus time for an object is given as \(x=A t^{4}-B t^{3}+C\) a) What is the instantaneous velocity as a function of time? b) What is the instantaneous acceleration as a function of time?

Short Answer

Expert verified
Answer: The instantaneous velocity function is \(v(t) = 4 A t^{3} - 3 B t^{2}\), and the instantaneous acceleration function is \(a(t) = 12 A t^{2} - 6 B t\).

Step by step solution

01

Differentiate the position function to find the velocity function

To find the instantaneous velocity as a function of time, we need to differentiate the position function with respect to time. So, we will differentiate \(x=A t^{4}-B t^{3}+C\) with respect to \(t\). Using the power rule of differentiation, we have: \(v(t) = \frac{dx}{dt} = 4 A t^{3} - 3 B t^{2}\)
02

Differentiate the velocity function to find the acceleration function

Now that we have the velocity function, we can find the instantaneous acceleration as a function of time by differentiating the velocity function with respect to time. So, we will differentiate \(v(t) = 4 A t^{3} - 3 B t^{2}\) with respect to \(t\). Using the power rule of differentiation again, we have: \(a(t) = \frac{dv}{dt} = 12 A t^{2} - 6 B t\)
03

Final answers

a) The instantaneous velocity as a function of time is \(v(t) = 4 A t^{3} - 3 B t^{2}\). b) The instantaneous acceleration as a function of time is \(a(t) = 12 A t^{2} - 6 B t\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Instantaneous Velocity
Understanding the concept of instantaneous velocity is crucial when studying motion. It represents the speed and direction of an object at a specific point in time. Unlike average velocity, which considers the total displacement over a total time period, instantaneous velocity is focused on an infinitesimally small interval of time, giving a real-time speed.

To grasp this, imagine you're watching a car race. The racer's speed meter at any given moment reflects the car's instantaneous velocity. It tells you precisely how fast the car is moving at that exact second, which could be different from the car's average speed over several laps.

In mathematical terms, to find the instantaneous velocity, we differentiate the position function with respect to time. This is because differentiation gives us the rate at which a quantity changes, which is exactly what velocity measures - the rate of change of position.
Power Rule of Differentiation
The power rule is a fundamental technique in calculus used to find the derivative of a function where the variable has an exponent. This rule greatly simplifies the process of differentiation when dealing with polynomials or any function that can be expressed as a power of the variable.

The rule is straightforward: for any term with the form \( x^n \), where \( n \) is a real number, the derivative is \( n \( x^{n-1} \) \). For example, the derivative of \( x^4 \) is \( 4x^3 \), and the derivative of \( x^3 \) is \( 3x^2 \).

Applying the power rule not only yields the instantaneous velocity when differentiating the position function but also helps us derive the equation for instantaneous acceleration by differentiating the velocity function with respect to time. It's a critical tool for physics problems involving motion.
Position Function
The position function, often denoted as \( x(t) \) or \( s(t) \) in physics and mathematics, precisely describes an object's location relative to a reference point, at any given time. This function is fundamental in kinematics as it lays the groundwork for understanding motion.

For example, the given position function \( x=A t^{4}-B t^{3}+C \) encapsulates how the object's position changes in relation to time. Such an equation may seem complex, but it smoothly translates an object's motion into an algebraic expression that can be manipulated and analyzed to extract meaningful information about the object's behavior over time, such as its velocity and acceleration.

It's important to realize that the position function is the starting point in solving kinematics problems. Without it, determining the instantaneous velocity or acceleration would not be possible.

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Most popular questions from this chapter

You drop a rock over the edge of a cliff from a height \(h\). Your friend throws a rock over the edge from the same height with a speed \(v_{0}\) vertically downward, at some time \(t\) after you drop your rock. Both rocks hit the ground at the same time. How long after you dropped your rock did your friend throw hers? Express your answer in terms of \(v_{0}, g,\) and \(h\).

Two athletes jump straight up. Upon leaving the ground, Adam has half the initial speed of Bob. Compared to Adam, Bob jumps a) 0.50 times as high. b) 1.41 times as high. c) twice as high. d) three times as high. e) four times as high.

You and a friend are standing at the edge of a snowcovered cliff. At the same time, you both drop a snowball over the edge of the cliff. Your snowball is twice as heavy as your friend's. Neglect air resistance. (a) Which snowball will hit the ground first? (b) Which snowball will have the greater speed?

Can an object's acceleration be in the opposite direction to its motion? Explain.

You drop a water balloon straight down from your dormitory window \(80.0 \mathrm{~m}\) above your friend's head. At \(2.00 \mathrm{~s}\) after you drop the balloon, not realizing it has water in it your friend fires a dart from a gun, which is at the same height as his head, directly upward toward the balloon with an initial velocity of \(20.0 \mathrm{~m} / \mathrm{s}\). a) How long after you drop the balloon will the dart burst the balloon? b) How long after the dart hits the balloon will your friend have to move out of the way of the falling water? Assume the balloon breaks instantaneously at the touch of the dart.

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